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Mechanical free energy devices => mechanic => Topic started by: Gabriele on January 12, 2014, 05:36:44 PM
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If i apply a force G un the red left piston,will the system move?
P.S. In blue water and that strange white snake an empty flexible tube
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maybe, if your snake is soft enough.
automotive repairing station are the good sample with the snake have been put to the zoo,
lol
puzzle solved.
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Isn't clear. If i put a plastic flexible tube on the left,and I apply an equal force on the right and on the left,on the left cilinder there is much pressure than right. Cause surface of piston in contact with the water is less. This if the plastic flexible hose is orizzontal and not curved. My question is the following: Does the reaction on the hose became istantanly great causing pressures on both cilinder became the same,or the is a linear variation of resistence coming to the max when the hose is pratically bend in 2?
Thank you
P.S. Sorry for my bad english ;D
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huh.. this is a great puzzle
hose should bend up.
next clue ?
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IF the hose bends,we can gather energy from the movement of the two pistons because displacing of water is negative on the left and positive to the right cilinder... so the applied forces moves right same distance... this IF the hose bends...
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i don't get it
first, is the pict correct? , i guest not.
the pict show condition/position after applying force FR or FL or BOTH,
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Appling for example a strong spring that pulls the two pistons togheter,we have a bigger pression on the left chamber,so if the hose can flect the left piston will move right pulled by the right piston, cause on it is acting a superior pressure respect the left...clear now?
PS. Your pic is correct,same of mine... isn't corrected the relation...
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if we push/pull pistons at the same time, with same force,
of course, we get the difference of pressure,
and if we add more and more then the hose/device will explode.
in other words, i don't understand .
sorry.
better wait for an expert.
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Once we put a strong spring,we don't need nothing more... I think the hose will flect moving righ,then the water pass throug a small connection hose from left chamber to right chamber.now the water leave left chamber is equal that goes to right chamber moving the piston. The two pistons are "fixed" they will move right togheter without loosing potential of the spring... so if the flexible hose flets...
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Need help
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from me, your device can do nothing, unless you find/hide a little
trick to play with, and i don't know what is that.
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Someone had understand the problem?
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This the ipotetical behavior if the hose bends.....i think it will bend untill moment of forces acting on it will bilanciate the difference of pressure
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nobody?