
I studied the Edwin Gray tube and didn't understand where the free energy came from.
For Gray Patent #4,661,747 Figure 2, it is said that when 12 and 32 high-voltage discharge produce a spark,
radiation is generated on 12, and radiant energy or cold electricity is received by 34.
It may be that the OU effect appears in this link.
I also don't know what radiant energy is, I don't know what cold electricity is.
I only know that in a vacuum tube, when the cathode is heated and attracted by the positive high voltage of the anode,
electrons run from the cathode to the anode in a vacuum. Electrons can be seen emitting a faint blue glow.
Because electrons cannot move in the air, the radiation of the radio antenna should not radiate electrons or charges from the antenna,
but only drive the charge around the antenna to vibrate.
If the Gray tube does radiate some charge, it is received by 34. Then I think it may be OU in this link.
When radiant energy or charge is radiated from 12, it has nothing to do with 12. And when 34 receives radiant energy,
it has nothing to do with the potential of 34 itself. Just as placing a radio on the ground can receive radio broadcasts,
and putting a radio on a high-voltage wire can also receive radio broadcasts.
Radiation is completely different from induction,
and the amount of induced charge has a decisive relationship with the potential difference between 12,34.
Suppose that 12 of the Gray tube actually radiates out the charge and is received by 34 in a radiative manner rather than inductively.
Then no matter how high the potential of 34 itself, it does not affect the charge that 34 receives from 12.
Suppose 34 receives the charge q.
According to the capacitor formula: U=q/C
That is, the same amount of charge, the smaller the capacitance C, the higher the voltage U.
There is also a capacitor energy formula: W=0.5qU
That is, the same amount of charge, the higher the voltage U, the greater the energy W.
So the charge obtained by the Gray tube 34 is directly sent to 36, and there is no physical capacitor on the line,
only the stray capacitance of the line structure and the parasitic capacitance of the 36 inductor.
That is, the Gray tube is designed for the smallest capacitance to receive 12 radiation.
It is possible to get the highest possible voltage U.
If U is higher than a certain threshold, the OU effect will occur?
Gray Patent #4,661,747 does not seem to be used in Patent #3,890,548.
I look at Gray patent # 3,890,548 mainly to say that the capacitor discharges at high voltage, causing the motor to rotate.
But the conventional understanding is that the discharge time is very short, that is,
the current time flowing through the motor is very short, the rotor only rotates a little angle, the current is gone,
how to continue to rotate?
If you really give the motor current in a short time,
the motor is required to continue to rotate to the next magnetic pole without current.
There may be an option:The stator core of the motor is made using the steel wire of the past steel wire recorder,
or the magnetic powder material of the recording tape.
The short pulse current reverse-magnetizes such a core material, just like the commutation of a DC motor brush and a commutator.
The electric motor can really rotate continuously under short pulses.
Of course, the coercive force of the material is greater than the magnetic field of the permanent magnet of the rotor.
Sound tapes seem to be easily magnetized?
It is hoped that a small pulse magnetization current can be used to achieve the OU effect.
The above is all conjecture, maybe all wrong. Thank you guys!