Hello, I would say that after making tests with 12v dc without being connected to the electrical network realized that something strange was happening because the same circuit in my opinion behaves as a "joule thief". I observed that with only one pulse one 12v battery the voltage gain would quickly close to a capacitor 70v.
I repeat the circuit is not connected to the mains.
I'll try to make a circuit to pulse dc current.
I'm not here trying to prove anything because it is all in the name of science
The electric installation of my house has all electrical and fire protection if the phase is connected with the earth however the circuit works without the differential protection shoot.
I think that the patent does not specify how exactly is the circuit.
I will continue with my tests and will post new videos soon.
thank you

greetings, after doing some tests with pulses 12v dc transformer barbosa as thought behaves with a joule thief.
I have no oscilloscope to analyze the output but it would be interesting to observe the wave.
I made some changes in the original configuration because as I said the patent for this barbosa not tell everything.
Who would bother to patent something that is a fraud?
Thank you for your comments.
https://www.youtube.com/watch?v=LYbMfbeQMZ4

I live in portugal and in my home i have the same electric protection . 

Nelson can you give us a schematic of your setup.
Thanks
dave

Good afternoon, I found that the circuit generates large amounts of reactive power  when an inductive device is connected.
My watt meter measures the power factor and noticed that when I connect an inductive load directly to the power grid power factor varies depending on the equipment but always below 1 always 0.75 to 0.79. When I turn on the same charge through the circuit power factor is always 1 which tells us that the efficiency of the equipment is the best, all the energy supplied by the source is consumed by the load and reactive power is not needed.
  but when I disconnect the capacitor from the circuit (output) power factor goes to 0.1, 03 ranging.
For example, to get 1 kW of real power when the power factor is unity (equal to 1), 1 kVA of apparent power will necessarily be transferred (1 kW ÷ 1 kVA = 1). Under low values ​​of power factor, to transfer a greater amount of apparent power to obtain the same active power is required. To get 1 kW active power with power factor 0.2 will need to transfer 5 kVA of apparent power (1 kW = kVA 5 × 0.2).
Apparent power is the product of the current and voltage of the circuit. Due to energy stored in the load and returned to the source, or due to a non-linear load that distorts the wave shape of the current drawn from the source, the apparent power will be greater than the real power. A negative power factor occurs when the device which is normally the load generates power which then flows back towards the device which is normally considered the generator.
When power factor is equal to 0, the energy flow is entirely reactive.
I think this matter is a starting point to understand some details of circuit operation.
I think the reactive power generated is stored in the condenser and fed to the load causing not consume active power in phase.
I think this matter is a starting point to understand some details of circuit operation.
I think the reactive power generated is stored in the condenser and fed to the load causing not consume active power in phase so the meeter dont count real power W.

Capacitive loads such as capacitor banks or buried electrical cables produce reactive power with advanced power compared with voltage. Both types of load absorb energy during part of the AC cycle, only to return back to the energy source for the remainder of the cycle.

sorry for my english some the notes a copy from wiki to explain this.
I would greatly appreciate your opinions, soon I will make a video to illustrate this explanation.
May also see some tests I published some time about inductive reactive energy with my youtube channel that can be useful loads.
Thank you

Hello All,

I replicated Barbosa  and Leal circuit yesterday using the schematics shared on overunity.com.  Following are my findings.

I used Toroidal transformer  220V, 500W as primary coil and powered it up from Grid using 236V AC. I used the secondary coil( black 50mm copper cable) with one loop through Toroidal with closed circuit.  I connected the Phase(Line) from grid to the secondary loop too for polarity.   My Ground seem to be very good showing 0.245 Volts between Neutral and Ground.  I created 6 loops of ground cable around Secondary coil.  Then I powered up my primary coil and  immediately the secondly coil with little humming shows about 80 amps of current in. I measured volts between Secondary and ground to be 236V.

Then I put load connected to Secondary and Ground and my 500W lamp lit perfectly.   Now the interesting part is here.

I measured my input current(from grid) and my output on to the (Phase on load)  but they were both same as 2.1 amps.   The secondary coil was still showing 80amps current.  So where is OverUnity?  Did I do anything wrong in the circuit?

Please advise if anyone has replicated it with success.  If someone is successful, then please share the exact details of primary coil and secondary( cable length, no of loops, gauge of the cable...etc)  and how to connect ground of capturing electrons from ground. This may help.

The test I did leads lead me to the conclusion till now that there wasn't any Overunity in the circuit.

Thanks to all.

@ isam, I have tried all ways to connect this circuit, if you look at it all that is happening is the live goes almost direct through the load to earth and lights the bulb the rest of circuit is not used.

Regards
Keith       PS secondary amps around 100 in my circuit but has no effect on load up or down.

 Thanks to NelsonRochaa on overunity thread for  “Barbosa”
 
 
Barbosa power generator video clip(s) on Youtube below..Duplicators !!!
 
Acca…
 
 
https://www.youtube.com/watch?v=wbNvUZT4NC4
 
https://www.youtube.com/watch?v=KAtRv6PneNs