Conradelektro:

You believe that adding the red diode will route the collapsing field energy of the coil back to the battery (or the capacitor if you are using the capacitor.)

In fact this will not happen.  No recharging of the battery or the capacitor will take place.

Also, when you look at the original circuit, you don't need the FWBR, all that you need is a diode.

Please think about this and if you want to try to understand what I am saying as an exercise for yourself, more power to you.  For what it's worth, on many Mopozco clips he makes similar claims and they are also not true.  That means this is a common misunderstanding or misconception.

MileHigh

Conradelektro:

You believe that adding the red diode will route the collapsing field energy of the coil back to the battery (or the capacitor if you are using the capacitor.)

In fact this will not happen.  No recharging of the battery or the capacitor will take place.

Also, when you look at the original circuit, you don't need the FWBR, all that you need is a diode.

Please think about this and if you want to try to understand what I am saying as an exercise for yourself, more power to you.  For what it's worth, on many Mopozco clips he makes similar claims and they are also not true.  That means this is a common misunderstanding or misconception.

MileHigh

I know that it does not work, see my experiments

http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363629/#msg363629

http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363634/#msg363634

Less relevant:

http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363504/#msg363504

http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363590/#msg363590

http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363599/#msg363599

Greetings, Conrad

Hi Jorge,

attached your circuit for 24 V operation.

But it is still very close for the A3144 Hall sensor, because it should not be operated above 24 V, but should support for some time 28 Volt. Do not run it for hours on 28 Volt, only some minutes. You could touch the A3144 to see if it gets hot. To 2 K resistor (1 K + 1 K) in front of the A3144 does not help much but should prevent the worst.

The Gate - Source Voltage of the IRF510 will not rise above 14 Volt at 28 V supply Voltage. The two 10 K resistors act as a Voltage divider.

Greetings, Conrad

I have a correction.......the mosfet number is IRF 530....! but for the case i think is the same...!
jorge

Maximum Gate Source Voltage of IRF530 is also 20 Volt, Conrad

http://pdf.datasheetcatalog.net/datasheets/400/283721_DS.pdf

I have other question.....why you connect (in the battery charger) the negative pole to the positive line of current...? why not to the ground....?

Because the battery is charged with the "Back Electromotive Force" Voltage (counter electromotive force). This current comes out of the coil in the reverse direction (of the drive current). For this charging current the positive rail is the ground. Or said differently, the Voltage after the charging diode is above the positive rail.

http://en.wikipedia.org/wiki/Counter-electromotive_force

I attach the Bedini standard circuit, where you can see the reverse connection of the battery to be charged. Your circuit is in essence the Bedini circuit (with a Hall sensor instead of the trigger coil).

Greetings, Conrad

Ok, i have two news.....one bad and one good
1.- the bad news is that the circuit SELFRUNNING with capacitor IT DOESN´T WORK...i used a capacitor of 52,000 uf 30 volts, and i only see that the current charge 13.4 volts and when i disconnect the run battery, the rotor stop...!
2.- I am in a BLACK HOLE, but now, this morning, I LEARN MORE....! the good news is that i KNOW FOR FIRST TIME HOW IT WORKS THE BACK EMF and now i am charging one battery with very good results...! THE FLAT RODIN COIL is good, and the rotor works very fast, 14,000 rpm AND THIS IS AMAZING TO CHARGE A BATTERY...!


SALUDOS
JORGE

Hi Jorge,

Ad 1.) It was important that you did the experiment with the large electrolytic capacitor parallel to the run battery. All people who claim OU could have done a similar experiment in order to see that their contraption in fact consumes energy (instead of producing more than is put in). So, whenever you think you get more out than you put in, you can try to run the thing with a capacitor and you will quickly see what is really happening. I did this experiment several times and it taught me a lot.

Ad 2.) It is possible to charge an "external capacitor" or an "external battery" ("external" means, it is not the supply source) to a very high Voltage and it is intriguing. But I measured just recently that charging the external cap" or "external battery" needs energy (the circuit uses more energy from the supply source whenever something is charged). The energy put into the "external cap" or "external battery" always comes from the supply source and is always less than is supplied, although the possible high Voltag is astonishing. One can charge an external cap to several hundred Volts if the drive coil is driven with 10 to 20 Watt at 12 Volt.

See at http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363634/#msg363634

Also this test might be interesting for you:
http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg363629/#msg363629

General remark:

Your magnet bearings and your various coils are very beautiful and well fabricated. And I guess it is fun to experiment with them. But one should be very careful to claim OU. The power supplied to your circuits is quite easy to measure (with an Ampere-Meter) because it is direct current. But it is very diffcult to measure the output accurately because it is "pulses". So, many people think they get more out than they put in. Also "light" is not a good method for measuring the output. The human eye sees something as "bright" even at less than peak light output. So, a 20 Watt lamp or LED might seem to be brightly lit at 5 Watt.

I also think that it is good to share the tests and set ups with others because there are most likely people who have done it before and they can give you good advice. It is almost sure that you will not give away a secret worth keeping, but you loose a lot of time without the knowledge of others.

I have nothing against trying the impossible, but secrecy will not help you, it will cause you loss of time and many false avenues which you will follow for nothing, because it is already known that it does not work.

Greetings, Conrad

Conrad:

http://www.overunity.com/13551/magnet-coil-cores-demagnetization-power-and-lenz-delay/msg363833/#msg363833

When I look at your schematic in reply #14, I see the following:

When the IRF510 MOSFET switches off, the coil discharges current out the bottom of the coil, then it flows through the one branch of the rectifier, then it flows through the red diode, and then it flows back into the top of the coil.  That is the current loop that occurs when the coil discharges.

MileHigh