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Author Topic: Exploring the Inductive Resistor Heater  (Read 56000 times)

Offline lanenal

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Re: Exploring the Inductive Resistor Heater
« Reply #75 on: May 06, 2013, 06:53:19 AM »
Well, read my two questions carefully; you didn't actually answer the two questions that I asked.


The first question I answered indirectly, but you don't seem to understand. The second question can be answered the same way -- just try to understand my very post from which you raised your question, because it can be inferred from it. If you can't, I am sorry I can not help you either.


I have to say that we should focus on the validity of Greg's conclusion, not about nitpicking all those small things. That only distracts and disinforms.

Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #75 on: May 06, 2013, 06:53:19 AM »

Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #76 on: May 06, 2013, 09:23:38 AM »

The first question I answered indirectly, but you don't seem to understand. The second question can be answered the same way -- just try to understand my very post from which you raised your question, because it can be inferred from it. If you can't, I am sorry I can not help you either.


That's just the kind of non-answer we have come to expect from people who don't know what they are talking about, but attempt to "explain" things to people who DO.
Quote


I have to say that we should focus on the validity of Greg's conclusion, not about nitpicking all those small things. That only distracts and disinforms.

In other words.... stop picking on the ignorance of lanenal, and get back to discussing the bogus claims of someone else who is so ignorant that he uses a big resistor in line with a gate driver chip.



Meanwhile.... here's something that is in Gmeast's "direct lineage" of descent. This is the "work" that caused Gmeast to undertake his project, and this is the "work" that is at the basis of all his and Ainslie's claims.

Take a look at what Rosemary Ainslie thinks her circuit does.

Note carefully how she misrepresents the explanations that she has been given, while at the same time failing to understand HOW MOSFETS WORK and how the capacitances come into play. She still maintains, in spite of literature from Agilent, Tektronix, and others, and in spite of several very clear demonstrations to the contrary, that a Function Generator cannot pass current from an external source "from its signal terminal and probe"..... Further, she clearly STILL doesn't understand the linear operation regime of mosfets, something that plays a critical role in her circuit's behaviour.

It's easy to make fun of this ignorant and arrogant woman, because her own words, captured exactly in images like this, amply illustrate her paranoia, willful ignorance, arrogance, and insulting manner.

She libels anyone who disagrees with her, she lies about the events that happened concerning FuzzyTomCat and Harvey, and I am looking forward to seeing what she comes up with on June 1. Or is it July 1? Her original demo video, posted on one of her FOUR DIFFERENT YouTube accounts, contained so many lies and "smoking gun" reveals that she finally tried to remove it... but it is still available in spite of her coverups.


Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #77 on: May 06, 2013, 09:34:16 AM »

TK, what a great find -- I wonder what tool you have used, looks like you've got CIA team behind you :) .
Do you think so? Or is it more likely that I simply used the forum's "search" function?
Quote
In that post, I was talking about the time average current (cause that's what matters in that case) while ignoring the leakage current, in that case, it is obvious that the time averaged gate current is zero.


lanenal
Is it really?

Well, then..... you are in the position of having to explain my results, then.... Your flailing about is becoming amusing.

My light bulb attached to the FG output lead LIGHTS UP when the circuit is made through the mosfet's capacitances .... even though the "time averaged current" is zero, it being an AC signal that is applied by the FG. Yet, in spite of "time averaged current" being ZERO..... power is dissipated in the light bulb.

Why does my light bulb light up, if the "time averaged current" is zero and the mosfet cannot pass anything except the leakage current?


Why do we focus on these small things? Because they are at the root of the larger things, like claims of free energy/overunity performance, when there is actually none there.

Come on, lanenal, explain to me why my light bulb lights up. Time averaged current = zero, signal applied to a mosfet that is functioning in a circuit, and  to one that is isolated, with the same results: signals that are oscillating at or around the frequencies used in the circuits we are discussing here, pass through the gate-drain and gate-source capacitances with hardly any attenuation, and are fully capable of dissipating power in a load, even though the "Time averaged current" may be zero.

Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #77 on: May 06, 2013, 09:34:16 AM »
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Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #78 on: May 06, 2013, 09:48:52 AM »
Here's a video that presents a demonstration that Ainslie denies is even possible. She has claimed many times, even as recently as this morning, that a Function Generator cannot do this: Pass current from an external battery source to power a load, or act as a power supply itself.  You wonder why we continue to examine and stress the basics? It is because of things like Ainslie's ridiculous and ignorant-- willfully ignorant--- claims about circuits and test equipment behaviour. And Gmeast is her protégé!

http://www.youtube.com/watch?v=GuBWVmRmUtc

And here's another video illustrating some more things that Ainslie thinks are impossible. MOSFETs switch by gate CHARGE, and they can in many applications be used NOT as a switch but as an amplifier, with an output resistance that depends on the magnitude of the gate CHARGE, not some poorly defined and even less well understood (by lanenal and gmeast) "gate current". The "linear" mode of operation is very important in the behaviour of Ainslie's circuit.... yet she refuses even to acknowledge that it is even possible.

http://www.youtube.com/watch?v=tKstLQYayNA

And while I'm on the subject..... note Ainslie's claim in the post image above about running without a separate supply for the signal generator (which supplies the negative bias necessary to produce her magic oscillations) in her circuit. Guess who was the first to show how to do this, well before Ainslie's claim (never demonstrated) to have managed it. And also note her lie about what it is that I "claim". All of us have shown that a negative bias current is producing the oscillations in her circuit; we have shown how to make the oscillations without any FG at all, in a steady state, by supplying the required bias current from an external power supply, an external battery, and finally-- MY WORK-- from the circuit's run batteries themselves by using a charge pump inverter. And I have shown, by reproducing her measurements, that her measurements do not mean what she thinks they mean at all and that there is no battery recharging, or lack of discharging, or any other anomalous effect happening in her circuit.  Now, Gmeast's circuit either IS, or IS NOT, a replication of Ainslie's work, depending on the day of the week or the phase of the moon.... but everything we have learned from dealing with Ainslie and her circuit(s) over the past three or four years applies directly to his circuit work as well.

http://www.youtube.com/watch?v=OHxstOJkFtM


A demonstration of the necessary bias current to obtain oscillations in the Ainslie "Q-array" circuit, no signal generator needed:

http://www.youtube.com/watch?v=hbHo3CCJtaw



Offline lanenal

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Re: Exploring the Inductive Resistor Heater
« Reply #79 on: May 06, 2013, 02:21:41 PM »
Do you think so? Or is it more likely that I simply used the forum's "search" function?Is it really?

Well, then..... you are in the position of having to explain my results, then.... Your flailing about is becoming amusing.

My light bulb attached to the FG output lead LIGHTS UP when the circuit is made through the mosfet's capacitances .... even though the "time averaged current" is zero, it being an AC signal that is applied by the FG. Yet, in spite of "time averaged current" being ZERO..... power is dissipated in the light bulb.

Why does my light bulb light up, if the "time averaged current" is zero and the mosfet cannot pass anything except the leakage current?


Why do we focus on these small things? Because they are at the root of the larger things, like claims of free energy/overunity performance, when there is actually none there.

Come on, lanenal, explain to me why my light bulb lights up. Time averaged current = zero, signal applied to a mosfet that is functioning in a circuit, and  to one that is isolated, with the same results: signals that are oscillating at or around the frequencies used in the circuits we are discussing here, pass through the gate-drain and gate-source capacitances with hardly any attenuation, and are fully capable of dissipating power in a load, even though the "Time averaged current" may be zero.


Why are you keep repeating some trivial common sense which you pretend that I don't understand? And as I have already pointed out, it is not pertinent here because that energy has already been accounted for by Greg in his first post.

Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #79 on: May 06, 2013, 02:21:41 PM »
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Offline poynt99

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Re: Exploring the Inductive Resistor Heater
« Reply #80 on: May 06, 2013, 03:24:03 PM »
It appears Lane is simply here to troll again. I've had similar dealings with him in the past.

He's clearly demonstrated here that he has no intention of having a reasonable discussion.

Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #81 on: May 06, 2013, 05:52:53 PM »
That's clear enough. But what do you expect from that crowd of mutual apologetics?

Remember this blast from the past?
http://www.youtube.com/watch?v=P8AIRkWF55k
What is the correct circuit diagram? Where is the Black lead from the function generator located? Why was one battery removed in the second half, leaving only 48 volts, when the claim is made that the circuit AS SHOWN can withstand 72 volts input?


Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #81 on: May 06, 2013, 05:52:53 PM »
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Offline picowatt

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Re: Exploring the Inductive Resistor Heater
« Reply #82 on: May 06, 2013, 07:01:14 PM »
Sorry, I posted in the wrong thread...

Offline SeaMonkey

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Re: Exploring the Inductive Resistor Heater
« Reply #83 on: May 11, 2013, 05:36:45 AM »
Quote from: PicoWatt
Desulphators supposedly produce finer grained sulphate crystals effectively increasing plate area.  As well, pulse and reverse pulse plating similarly are known to produce finer grained structures.  Visualize large clumps of sulphate crystals forming at the plates as opposed to a much smoother, finer grained structure.  As well as an increase in surface area, less resistive losses occur over the finer grains.  This is, supposedly, how a desulphator functions, and the waveforms used to desulphate have much in common with the waveforms of these OU circuits.

Lead Sulfate is the normal electrochemical
product of battery discharge (lead-acid battery)
as the Sulfuric Acid electrolyte combines with
the active materials of both the positive and
negative plates.  Initially, the lead sulfate crystals
are very tiny and nearly amorphous.

If the partially discharged battery with such lead
sulfate on the plates is re-charged immediately
and fully that lead sulfate will be almost completely
converted (by electrochemical decomposition) back
into active plate materials and regenerated sulfuric
acid.

If, however, the partially discharged battery is left
unattended for some time the lead sulfate crystals
will begin to undergo a phase change to become
larger "hardened" sulfation which will resist conversion
back into active plate materials and regenerated
sulfuric acid by normal charging voltages.

Typically, this hardened sulfation will gradually increase
in volume and mass as the battery ages and will deprive
the plates of active material capacity.  The battery becomes
weak with reduced capacity and will not hold a charge.

The desulfator circuit applies to the battery very sharp
and very short pulses of considerable overvoltage at
a frequency of about 1000 Hz.  The higher than normal
voltage is necessary to rejuvenate the hardened sulfate
crystals by decomposing them back into active plate
material and sulfuric acid; thus restoring the integrity of
the plates to near original condition.  The plate area which
had been lost to the hardened sulfation is recovered and
made available for normal discharge/charge cycles.

It is a slow process which evolves considerable heat and
there are invariably some losses in the plate structure,
especially with automotive batteries which are by design
much less robust than a deep cycle battery.  But if the
battery hasn't sustained significant damage to the plate
structures substantial capacity and usefulness will be restored,

Fortunately, desulfators are easy and inexpensive to make
and they can be very effective.

"Reverse Pulse Plating" is a unique process which is similar
to "burping" a battery during charging in order to reduce
the buildup of dendrites.

Regarding the matter of inductive discharge, it was long
ago discovered that a free-wheeling diode across a DC
Motor which is pulse driven both reduces the possibility
of transient generation and significantly increases the
efficiency of the motor.

It stands to reason that a free-wheeling diode placed
across an inductive resistor would produce the same
result when pulse driven.

Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #83 on: May 11, 2013, 05:36:45 AM »
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Offline SeaMonkey

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Re: Exploring the Inductive Resistor Heater
« Reply #84 on: May 11, 2013, 05:46:36 AM »
Quote from: lanenal
Why are you keep repeating some trivial common sense which you pretend that I don't understand?

They do it because they are unable to resist the
temptation for mischief.  They quite literally are
unable to help themselves.  The adrenaline rush.

Boys will be boys! :o

Will Rosie ever come back to put them in their
place? 8)

Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #85 on: May 11, 2013, 10:40:26 AM »
Ainslie is promising another of her famous demonstrations of incompetence on June 1.  But she is already snivelling about what is to be shown. She's not going to be showing what she promised to show LAST APRIL and failed to do so, for instance. Maybe you can figure out what she intends to try to demonstrate. I can hardly wait.

Of course, based on her past record, the chances of there actually being anything demonstrated on June 1st is very small. After all, she has told us how she is constantly being hacked, her computers stolen, and other sabotage perpetrated against her. What will she blame her next failure-to-deliver on? Is MrSean2K really vacationing in South Africa this month? Are her lawyers prepared to meet with Bryan Little to discuss a settlement for all the slanders and libels against him she's committed? The world is watching carefully.

And I am laughing so hard I can hardly see the screen.

Free Energy | searching for free energy and discussing free energy

Re: Exploring the Inductive Resistor Heater
« Reply #85 on: May 11, 2013, 10:40:26 AM »
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Offline gmeast

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Re: Exploring the Inductive Resistor Heater
« Reply #86 on: May 11, 2013, 02:43:13 PM »
Ainslie is promising another of her famous demonstrations of incompetence on June 1.  But she is already snivelling about what is to be shown. She's not going to be showing what she promised to show LAST APRIL and failed to do so, for instance. Maybe you can figure out what she intends to try to demonstrate. I can hardly wait.

Of course, based on her past record, the chances of there actually being anything demonstrated on June 1st is very small. After all, she has told us how she is constantly being hacked, her computers stolen, and other sabotage perpetrated against her. What will she blame her next failure-to-deliver on? Is MrSean2K really vacationing in South Africa this month? Are her lawyers prepared to meet with Bryan Little to discuss a settlement for all the slanders and libels against him she's committed? The world is watching carefully.

And I am laughing so hard I can hardly see the screen.


TK,


You do persists. You should read some of the comments in threads on respectable energy sites. They are all about you. Free energy has been here all along in the form of your blubbering. If only we could harness the abundance of energy flowing from that trap of yours, the would would finally be at peace. I've already contacted Stefan. When he returns from vacation, he'll see that YOU, once again, turned a thread meant to share results of research into a forum to promote your own malicious bullshit. He locked one of your threads and now he'll lock this one. It's that p-nis problem I guess.


Regards





Offline poynt99

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Re: Exploring the Inductive Resistor Heater
« Reply #87 on: May 11, 2013, 03:54:26 PM »
The main problem with Rosemary's (and gmeast's) test protocols, is they assume that a battery's A-h rating is constant and linear, independent of time or current during discharge.

Take a 100 A-h battery for instance. The A-h rating on a battery is usually given at a 20 hour discharge to 10V. At this rate of discharge the battery will output roughly 5A of current. 5 x 20 = 100; all seems good.

Now, decrease the discharge time to 2 hours; would we expect the battery to supply 50A for the duration? In practice, the battery would deliver about 40A, and therefore the actual A-h rating at the 2 hour discharge is 80 A-h.

Go to the extreme and decrease the discharge time to 2 minutes. In practice the battery would deliver about 680A for an actual A-h rating of 22 A-h.

So it's quite evident that we can't linearly extrapolate the A-h rating when changing from one discharge current to another. So what are the implications?

If we are to properly compare the A-h rating and capacity of a battery, the battery needs to be discharged at the same average current for all cases. One battery rating called "Reserve Capacity" is tested by measuring the length of time the battery can deliver 25A (starting current) until it discharges to 10V.

References:
http://www.dcbattery.com/faq.html
http://www.allaboutcircuits.com/vol_1/chpt_11/3.html
http://www.answers.com/topic/amp-hour-ratings
http://overlandresource.com/what-is-an-amp-hour-and-how-to-calculate-battery-capacity
http://www.odysseybattery.com/documents/US-ODY-TM-001_0411_000.pdf


Quote
How Are Amp Hours Determined? Battery manufacturers complete tests on their batteries to give them an Amp-Hour rating. A typical time period for a test is 20 hours, but it varies - batteries are tested over different periods, such as 24 hours, 75 hours, even 100 hours.  But as you'll see below, a 100 Amp-hour battery tested over a 100 hour period (i.e. 1 amp drawn for 100 hours) will not have the same capacity as a 100 Amp-hour battery tested over a 20 hour period (i.e. 5 amps drawn for 20 hours). It turns out that if you drew 1 amp continuously from the 20 hour test battery, it would last for 110-120% longer than on the 100 hour test battery.

Offline TinselKoala

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Re: Exploring the Inductive Resistor Heater
« Reply #88 on: May 12, 2013, 09:10:18 AM »

TK,


You do persists. You should read some of the comments in threads on respectable energy sites. They are all about you. Free energy has been here all along in the form of your blubbering. If only we could harness the abundance of energy flowing from that trap of yours, the would would finally be at peace. I've already contacted Stefan. When he returns from vacation, he'll see that YOU, once again, turned a thread meant to share results of research into a forum to promote your own malicious bullshit. He locked one of your threads and now he'll lock this one. It's that p-nis problem I guess.


Regards

Preserved for posterity.
You are the blubbering one, Gmeast. You can whine and insult all you like, but the record is clear: You cannot refute anything that .99, Picowatt, or I have said. You started two threads whose only purpose was to insult and mock me, nothing to do with any topic on this forum at all, in clear violation of this site's TOS and in violation of civil behaviour. You are a troll.
You have used and continue to use foul language like a ten year old child. You cannot even discuss things rationally with Picowatt, who has never said a harsh word to anyone.
Anyone who reads the thread you are talking about -- this thread -- can see for themselves that I DIDN'T EVEN POST IN IT until after you started with your insults and disrespect of your betters, specifically PicoWatt. So you are lying again when you blame your difficulties on me.

Your famous "FUCK THEM ALL DEAD" quotation will go down in history as typical argumentation from you and your ilk. Some people might even interpret that as a physical threat. I just find it very childish and insulting. Nobody here has spoken to you like that, except in direct response to your own foulness.

Your whining to Stefan is also typical. You've said many times that you don't care about this forum, that you aren't going to post here any more, and then you start up your threads just to insult and denigrate those who know their topic far better than you do. What was the last thread that was locked that I posted in? It was the Wayne Travis thread, and he asked for that thread to be locked because he could not answer the points I and others raised .... and he STILL cannot show what he claimed to have two years ago. And the thread before that was the Tar Baby thread.... my own thread, the only one that I've started here.... locked because Ainslie deliberately flamed and lied and even threatened Stefan with her lawyers. I keep the pressure on, and claimants who cannot support their claims with facts wind up whining, pleading with the site owner (even after insulting him over and over.... ) and flaming me whenever they can, just like you do.

Stefan might not have time or patience to review all the facts. And you distort them as you see fit, and avoid the truth like it would melt you. But I know this much: YOU, Gmeast, have contributed nothing to this site, you've never helped anyone, and you have been incredibly and increasingly insulting and foul-mouthed. You've insulted Stefan, complained about his administration, and you even use other forums to insult this site and its members. Why would anyone want you around? You don't even understand your own topic.

Offline poynt99

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Re: Exploring the Inductive Resistor Heater
« Reply #89 on: May 12, 2013, 07:18:47 PM »
In case the message wasn't clear, allow me to spell it out a bit:

As the data shows, outlasting the rated 20 hour discharge figure of a battery is NOT proof that the circuit it is powering is OU or applying charge back to the battery.

The same goes for an apparent negative input power measurement. That one is easy to achieve, even in a simulation as I have done.

The only way Rosemary and gmeast will ever prove to anyone that their circuits are operating in some extraordinary mode, is to either perform proper power measurements, which they have not done, loop their devices and remove the power source, or demonstrate that the power source will outlast its amp-hour rating, based on the drawn operating current, also not yet done.

For the latter, the circuit would have to be run for at least 200 hours continuously (assuming a 100 A-h battery), based on a 1 ampere or so current draw typical of Rosemary's circuit. If the battery has significantly declined in open circuit voltage at the end of the run, then obviously there was no recharge occurring.

The so-called "control" is not even required if these tests are performed properly.

 

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