So if I understand you correctly,..you are stating that regardless how cogless a alternator is,...it is still going to have resistance present?

Yes, resistance to rotor rotation whenever you connect a load across the generator output coil.

You are expected to do your homework first in conventional electrical engineering and when you know what obstacles you are to face with in energy conversion you may start doing something to circumvent them.

Here is a demo on Lenz law.
http://www.youtube.com/watch?v=WHCwgc_xs3s
As an analogy, think gravity as the prime mover for this virtual generator and the Lenz drag in this case works against gravity. In case of real generator Lenz drag works agains the prime mover of the generator. In the video the load is the self-impedance of the output coil because it is shorted. If you load this coil with say 2 Ohm, or 5 Ohm or 100 Ohm resistors instead of the short (i.e. instead of the self-impedance of the output coil) the falling speed of the coil would gradually increase, meaning the Lenz drag reduces as the loading current gets smaller and smaller, this is just like in a real generator.

If you look at a generator in depth, it is not an energy conversion device.  It is a poorly designed power generator that fights itself.  The more load on the generator, the more counter magnetic field that causes magnetic drag on the rotor, which takes proportionally more power to turn the generator.  It is not due to power conversion at all.

Hi Liberty
Ok here is a question for you.
If a generator's lenz force drag is greater than the power output that the generator is giving,then in the below video(that i will attach again)the motor should roll to a stop much quicker than it would with the generator unhooked-as a generator is a loss.
Now we know that this is the case(a generator is a loss)or we would have self running devices all over the place.
But here you have a motor coupled to a generator,and with the generator disconected there would be now lenz drag created within the generator-and when the motor is disconected from the batteries,it rolls to a stop in a given amount of time.
Now when a loss(the generator) is added to that system,one would think that the motor would roll to a stop in a shorter amount of time-as we are adding another loss to the system.
We also know that to get that motor to run on for a longer amount of time when the batteries are disconected,we would need some sort of energy input.
So how is it that by adding a loss to the system,we get a gain in run time?
If the lenz force drag is greater than the power coming out of the generator being routed back into the motor-the motor should run down to a stop quicker.
But here we see the run time is increased dramaticly when the generator is conected to the motor,and batteries disconected.
http://www.youtube.com/watch?v=hl57y-c_bWc