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### Author Topic: Is this the Smith/Kapanadze secret ?  (Read 44572 times)

#### saintsnick

• Jr. Member
• Posts: 51
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #30 on: November 26, 2014, 06:05:37 AM »

-Saintsnick

#### Belfior

• Hero Member
• Posts: 534
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #31 on: June 27, 2018, 11:18:42 AM »
Looking at the series of videos put out by Rick Friedrich

am I somewhere in the ball park with my deduction below?

There is really no secret. What Don Smith is using is just resonance and not even resonance in all cases. People get stuck in the math formulas and start babling, that "voltage is not power. Power is voltage times amperage". They forget that amperage only appears when you start wasting charge somewhere. You radiate energy into space with a stove or use some other form of transformation. So amps is actually something we might not want in our system at all. Gerard Morin seems to be able to speed up his motor with just voltage and amps stay low. Probs just copper losses.

Voltage is pressure and first we want to get a lot of pressure, so later on we can use some and some we can even waste in a spark gap or similar. Nature has provided us with plenty of ways to get voltage: Resonance, flyback transformers, Marx generators, charge pumps, Tesla coils. So we can almost say that voltage we can get to any pressure without using much input. Once again you get "priests" attacking you saying that "this and that is only voltage and that is not power. That is only 'static' charge and it has no power. There is only One God called Under Unity so go pay your electric bill". Let me tell you a secret. Charge equals charge equals charge. If you get that charge into a capacitor you got power. Does not matter if it came from Lord Kelvin's water drop static generator or from a comb.

So why high voltage? I think the reason is that if you primary has 1V and you get it into resonance with the secondary you get 20V. That is not much to bounce from. If you put 9000V into the primary and get 200kV out of the secondary you got something to work with and something to even waste. High frequency gets you out of the wires into the surface of the cables and losses are smaller. Also I think higher frequency is more power, because it is more movement (you can quote your favourite UU bible here telling me how wrong I am...)

In resonance there is no resistance between L1 and L2. You can use loosely coupled L3 to pick up energy.

Ok so now we got "pressure". Let's say we got 200kV at the end of the L2 at 31500Hz. We measure L3 so that we get 8000V out to a cap of 0.005uF . Capacitors have very little to do with amps. You only need a bit of current to fight the internal resistance of the cap, but the thing works just with farads and voltage. Charge is Q = C*V and amps is Q/s. So we are putting a charge of 8000V * 0.005*10^-6 = 0.04C of charge into that cap 31500 times per second. Now if we were feeding the cap with 60Hz and at the end of the line we got an inverter feeding a device at 60Hz, 230V we could power a device that takes 40mA. We are how ever filling a large capacitor bank 31500 times per second with 0.04C of charge. Charge is charge is charge, so usable charge is 31500 * 0.04C = 1260C in one second. Divide that by 60 and you should be able to feed a device that draws 21A at 60Hz. No losses yet in these calculations, so 21A is not going to be the real value. Maybe not even 10A out, but enough for 2-4A, 230V at 60Hz? That is enough to self loop and run a graphics card to mine Ethereum. For free.

So there is nothing magical here. Build up voltage and store it into a cap bank as charge. Voltage is arbitrary to manufacture. Voltage is potential, pressure, strength of the field. Amps are the charge that is lost. The difficult part is the tuning, storing HV and getting everything to usable level at the end including frequency. So maybe a (resonant) transformer after the cap that L3 is feeding? Primary shunted with a spark gap to get a pulse going and secondary drops the voltage to 14V? Then full bridge rectifier to get it to 12V DC -> inverter -> 230AC at 60Hz

So what Kapanadze is trying to hide with all the boxes and shit is a tesla coil with L1, L2 and then L3 on the other end of L2. L1 and L2 are in resonance. L2 is looped to itself and grounded. Slayer exciter could take care of that. L3 feeds a cap bank. Rest is transformation to usable range.

People get hung up on amps and they can say like "tesla coil is only voltage. There is little amps there". This only means the L2 has only copper losses so it is efficient. Get that voltage into a cap and you got charge. Charge is what matters. If the internal resistance of the cap is something foul then you got no charge. You need to impedance match that shit.

People get hung on the notion that they do not understand where the extra energy is coming from? Well energy Conservation Law tells us, that you cannot destroy or create energy. That means all the energy was there since the start. You just trick Nature by connecting 2 potentials and the energy rushes in when Nature is going to equalize that "error". Like there is zero energy in a 12V car battery, but make a path between the 2 terminals and you got lightning coming out. You are not asking how your car starts in the morning are you? The energy is not in the battery. It would melt.

now if someone wants to comment I would like to hear actual criticism based on facts and not something like this:

"I have a PhD and I have been working for an energy company for 50 years. This is a picture of a wall where all my certificates are. You cannot get more energy out, because Jesus and the Second Law of Thermo..." Well just prove to me that voltage does not equal charge in a capacitor? Minus some amps that go into copper and other internal losses. In an ideal cap it is just farads and volts that define charge. Amperage is then that charge pulled out in one second. So voltage+capacitance is what you have and amps is what you waste.

The only problem is the transformation. How do you get 200kV at 2.4MHz into a cap bank or translated in some other way to 12V DC? Voltage is difficult because of capacitor limits and frequency is nasty because of transformer hysteresis and eddy currents. Just give me a couple of methods and I will leave you all alone.

#### AlienGrey

• Hero Member
• Posts: 3616
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #32 on: June 27, 2018, 12:53:16 PM »
Well ok I have a Tesla coil with a single transistor driving it as a blocking oscillator if I hook a scope up although it's a Tesla coil it is wave form is just a sine wave ok I can add another coil and collect the magnetic flux into another coil but where is the free energy from the resonance.

The other thing Don L Smith makes a point about is the dual output Neon driver being a over unity in it self and it's frequency is 35.1 if you get a calculator and try and divide it by 8 or 9 witch one leaves no remainder ? I wonder why he chose that device ?

The other thing is as resonance is obtained our current drain goes up too.

There is something missing and I didn't see it in your write up and that is the dipole is constantly being destroyed, as the brighter the LED goes the more current is drawn.

AG

#### Belfior

• Hero Member
• Posts: 534
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #33 on: June 27, 2018, 02:11:05 PM »

Well ok I have a Tesla coil with a single transistor driving it as a blocking oscillator if I hook a scope up although it's a Tesla coil it is wave form is just a sine wave ok I can add another coil and collect the magnetic flux into another coil but where is the free energy from the resonance.

At the end of the secondary. You put it into a cap and it is changed into charge. Amps is charge over time. If you got a cap with 5M Ohm internal resistance, you might not very much charge, because once again you transformed that energy into amps/waste

Quote

The other thing Don L Smith makes a point about is the dual output Neon driver being a over unity in it self and it's frequency is 35.1 if you get a calculator and try and divide it by 8 or 9 witch one leaves no remainder ? I wonder why he chose that device ?

I think Don means that you get 9000V with a device that only takes milliamps, he thinks you get 9000V worth of charge 35000 times per second or the device is labeled as 35-70W device even if you get the charge 35000 times per second. He chose the device because it provides HV cheaply

The main point is that you need to look at charge. Charge you get with voltage. Amps come into play when you start wasting the charge

What people need is a new way of looking at this. The reason OU is hiding is that people are using formulas and ideas provided by the energy companies in the form of books and theories. Everything is setup so that it is impossible to get more out than goes in. You get started with a dipole that you keep destroying (we might not get out of that easily...), then you are told to get rid of resonance, make transformers with input&output in linear position in the center pole, permanent magnets do not do anything, use low frequency because otherwise God will punish you and what ever else there might be. It is like they make you play black jack and only the dealer has picture cards and aces...

Energy is there. Even physicists agree that it is everywhere. Even in the vacuum of space. They need it to be there, or their model of the universe breaks down. Dark Energy is the new name. Used to be called Ether, but all the cool kids don't use that anymore.
Nice thing about it is that you don't need to figure out how to get it. You just create a system that is not balanced. Nature will bring that energy there to equalize the situation. Just put your tongue in the bottom of a 9V battery. Is there energy there? Now join the terminals with your tongue. Did some energy appear? Still got your tongue together?

Short recipe to OU is:

1. What is charge? How do I get charge?
2. Store the charge
3. Use the charge

You can do this efficiently or badly and in that case you don't get much out and not even close to unity. You have to be efficient in all of those 3 stages.

#### AlienGrey

• Hero Member
• Posts: 3616
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #34 on: June 27, 2018, 04:58:22 PM »
How are you actually getting your charge?
it's a 9kv device but he uses a device like a variac to feed the 120volt input feed and attenuate that voltage
feed down in order to lower the neon PSU output down to 3kv and it's at 35100hz or 35.10khz
pulsed !

regards AG
« Last Edit: June 28, 2018, 12:46:26 AM by AlienGrey »

#### nelsonrochaa

• Hero Member
• Posts: 653
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #35 on: June 27, 2018, 07:56:28 PM »
How are you actually getting your charge?
it's a 9kv device but he uses a device like a variac to transform it down to 3kv and it's at 35100hz or 35.10khz
pulsed !

regards AG

Hi ppl,
AG Not necessarily. A charge on a capacitor with high voltage can be converted back into current without necessarily using a variac or a magnetic process .

In this video i made some years ago ,  i try show how to transform a high voltage in the order of 10KV with a low current, in lower voltage but with current through a nonmagnetic process. We could say that two terminal of spark gap could be considered a plates of a capacitor and the air the insulator , so in this way we have a electrostatic event because a capacitor store charges. This charges Vs time = current .

regards

Nelson Rocha

#### AlienGrey

• Hero Member
• Posts: 3616
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #36 on: June 28, 2018, 01:04:47 AM »
Hi ppl,
AG Not necessarily. A charge on a capacitor with high voltage can be converted back into current without necessarily using a variac or a magnetic process .

In this video i made some years ago ,  i try show how to transform a high voltage in the order of 10KV with a low current, in lower voltage but with current through a nonmagnetic process. We could say that two terminal of spark gap could be considered a plates of a capacitor and the air the insulator , so in this way we have a electrostatic event because a capacitor store charges. This charges Vs time = current .

regards

Nelson Rocha
An interesting way of bringing the high voltage back down to a usable level, I sort of reminds me of a crude PW switch mode switch mode ramping up a cap and then discharging it through the load in slow motion, did you ever manage to stablise the device in order to make the idea more usable ?

PS I was in fact referring to the 120 volt feed into the neon power supply as only 3kv is required not 9kv I should have explained my self a little better sorry, but your comment was interesting.
cheers AG
« Last Edit: June 28, 2018, 11:05:23 AM by AlienGrey »

#### MasterPlaster

• Hero Member
• Posts: 529
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #37 on: June 29, 2018, 04:48:43 PM »

This patent may be of interest:

#### NerzhDishual

• Hero Member
• Posts: 588
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #38 on: June 30, 2018, 01:18:00 AM »
Greetings OU dot com Distinguished Members,

Sorry for disturbing.

IMo, one of the secret is also in this "Displacement Current".

This current (electrons?) that, maths helping, kinda path through the dielectric
Come on.
------------------------------------------
Please#1, see the Tesla's Hairpin Circuit.
That, BTW, is not "renowned" as 'OU'
-------------------------------------------
Please#2, just alo consult this short vid:
"Extract Don Smith 2006 Tesla Tech short v"

According to the (late) Don Smith, the "current" does not come from the "source" (battery or grid)
but from the "environment". So it is free. IZIT not?

A (not so good) heat pump can show a COP > 3. Where does the energy come from?
But, from the "environment". No?

I must say that what I am stating is not intended to contradict any previous assertion.

Puisse le bonsoir vous seoir,
Jean

#### AlienGrey

• Hero Member
• Posts: 3616
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #39 on: June 30, 2018, 08:15:31 PM »
Greetings OU dot com Distinguished Members,

Sorry for disturbing.

IMo, one of the secret is also in this "Displacement Current".

This current (electrons?) that, maths helping, kinda path through the dielectric
Come on.
------------------------------------------
Please#1, see the Tesla's Hairpin Circuit.
That, BTW, is not "renowned" as 'OU'
-------------------------------------------
Please#2, just alo consult this short vid:
"Extract Don Smith 2006 Tesla Tech short v"

According to the (late) Don Smith, the "current" does not come from the "source" (battery or grid)
but from the "environment". So it is free. IZIT not?

A (not so good) heat pump can show a COP > 3. Where does the energy come from?
But, from the "environment". No?

I must say that what I am stating is not intended to contradict any previous assertion.

Jean
Bonjour, mon ami
Puisse le bonsoir vous seoir, ainsi

Re Don L Smith, where does the energy come from, It comes from the ambient a change there of by disturbing the surrounding
charge IE the Tesla coil in a special way, in our case and it's attraction of the surrounding area.

Regards
AG

#### Belfior

• Hero Member
• Posts: 534
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #40 on: July 01, 2018, 11:30:59 AM »
Anyone able to get the "Tesla Magazine" that Don Smith is talking right here? 5 page article laser printed?

https://youtu.be/Cr07kI7HhzU?t=2472

Energy is everywhere. That is why you don't need to think where it is coming from. Nature will deal with that.

What Don is showing is that you disturb that ambient so that electrons that normally are neutral (non-reactive in a local space) are exited to a higher energy level and then you provide a non-resistive path to ground. This is what the Tesla secondary is for. Self loop L2 with a spark gap to ground. L1 and L2 are in resonance and you pickup from L3 through diodes to a cap bank.

#### Belfior

• Hero Member
• Posts: 534
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #41 on: July 01, 2018, 11:34:21 AM »
Hi ppl,
AG Not necessarily. A charge on a capacitor with high voltage can be converted back into current without necessarily using a variac or a magnetic process .

In this video i made some years ago ,  i try show how to transform a high voltage in the order of 10KV with a low current, in lower voltage but with current through a nonmagnetic process. We could say that two terminal of spark gap could be considered a plates of a capacitor and the air the insulator , so in this way we have a electrostatic event because a capacitor store charges. This charges Vs time = current .

regards

Nelson Rocha

Any chance you might want to post a schematic or explain the process? I thought you kinda have to put the HV into a cap bank and then pulse a transformer to get it to lower voltage? how can I get my 8000V fully charged cap to a manageable level (12V super caps?) or even straight to 230V AC?

#### Belfior

• Hero Member
• Posts: 534
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #42 on: July 01, 2018, 12:23:46 PM »
So my idea here is that I can fill up a cap bank with a 35100Hz PSU putting out 9000V at 30mA. Current is irrelevant, if it is enough to charge the caps that have some internal resistance.

(so charging something that takes 105A/s to charge is not going to work https://youtu.be/xpy9CmAWrGo?t=90)

So my load is 0,26A at 230V 60Hz light bulb. My logic tells me that I need to match the amount of charge I am putting into the caps with my fast PSU to the pull that my load needs. So small buckets of charge 35100 times per second need to match the bigger pull of the load, but it only pulls 60 timer per second.

So how much load you can have depends on the charging of your cap bank. You could maybe put a voltage meter on the cap bank and if the voltage starts to droop while loaded that means the amount of out going charge is bigger than what you are putting in.

Sure there has to be some losses and components in between the cap bank and the load. We need to get down to 230V from 9000V and then get the freq right if we don't decide to go with a rectifier to 12V DC

#### Jo-EL

• Newbie
• Posts: 17
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #43 on: July 04, 2018, 01:50:22 AM »
Looking at the series of videos put out by Rick Frie......................
..............

So what Kapanadze is trying to hide with all the boxes and shit is a tesla coil with L1, L2 and then L3 on the other end of L2. L1 and L2 are in resonance. L2 is looped to itself and grounded. Slayer exciter could take care of that. L3 feeds a cap bank. Rest is transformation to usable range.

......................
The only problem is the transformation. How do you get 200kV at 2.4MHz into a cap bank or translated in some other way to 12V DC? Voltage is difficult because of capacitor limits and frequency is nasty because of transformer hysteresis and eddy currents. Just give me a couple of methods and I will leave you all alone.

You knows what you mean please make a Circuitdrawing.

Jo

#### AlienGrey

• Hero Member
• Posts: 3616
##### Re: Is this the Smith/Kapanadze secret ?
« Reply #44 on: July 04, 2018, 06:02:06 PM »
You knows what you mean please make a Circuitdrawing.

Jo
I looked at this one and thought I need a drink too !

Do you mean this ? page try p82    http://free-energy-info.com/Smith.pdf
AG