UncleFester is Tad?  No Shite? 

Hey, what ever happened with your Ed Gray replication?  In (I think) 2006 you were getting RE using carbon electrode spark gap in a copper tube as a collector. There is a PDF of your posts on the web somewhere.

@all

Is it possible the something else that mimics beta radiation is at work?

Is it possible the something else that mimics beta radiation is at work?

I say for sure!  As has been noted before, 6Kw of beta radiation would fry the hapless experimenter who stumbled across it...

Looks like our "beta" is actually an EMP affecting the meter...hmmm, where have I heard mention of an EMP and overunity before?

Eldarion

I keep hearing about this beta radiation frying our skin off etc.
We need to keep in mind that this concept is only producing small amounts of boron12 in the midst of the carbon atoms.
Theoretically, much of the beta will be absorbed by the carbon rod, probably producing some sort of EMP.
To get the beta out of the rod we would have to design a different source of carbon that will allow that beta to escape.
Perhaps carbon mixed with air in some way to allow lots of open space between the carbon particles.
Maybe graphite powder is the way to go. Vibrate the graphite to get it full of air and then feed it into the unit to be pulsed.
Something like this may give you that high beta we are always reminded of.
But I think much of the beta is getting trapped in the carbon rod, so we don't see it.
3.1mm of glass can completely stop beta so probably the same amount of carbon will too.
The beta we are observing is only that which is produced on the surface of the rod.

This is my theory on the subject anyway, and it's based on simple logic.

I managed to find some coal on Sunday and I plan on cutting a rod from it.
Will see what kind of results I get.

I keep hearing about this beta radiation frying our skin off etc.
We need to keep in mind that this concept is only producing small amounts of boron12 in the midst of the carbon atoms.
Theoretically, much of the beta will be absorbed by the carbon rod, probably producing some sort of EMP.

Yes, I agree, the fact that -according to the Protelf theory- beta emissions occur, does not necessarily mean we
will get freakishly strong radiation bursts outside of the rod material. Most of the 'reaction' should occur inside
the conductive rod, and most beta should immediately "bump into" surrounding atoms and become heat and/or
eddies and/or other EM inductive phenomena. Even if some of the beta gets out, it won't be much because we're
not using very high energy pulses anyway.
Besides, any form of electrical shielding will stop these rocketeer electrons, so a shield layer of glass, metal, plastic,
or even a combination of the two, should easily stop beta from reaching your skin.
If you're worried about your campfire starting a bushfire, you build a stone wall around it.
If you're worried about your beta frying your skin off, you build a shield around it.
Seems simple to me...

To get the beta out of the rod we would have to design a different source of carbon that will allow that beta to escape.
Perhaps carbon mixed with air in some way to allow lots of open space between the carbon particles.
Maybe graphite powder is the way to go. Vibrate the graphite to get it full of air and then feed it into the unit to be pulsed.
Something like this may give you that high beta we are always reminded of.

Hey! Don't go revealing my "death ray" reaction chamber idea to the people now!
How are we ever going to take over the world if they know?! (Muhahahaha?)

But I think much of the beta is getting trapped in the carbon rod, so we don't see it.
3.1mm of glass can completely stop beta so probably the same amount of carbon will too.
The beta we are observing is only that which is produced on the surface of the rod.

Yes, mostly. Some of it may be the occasional near-surface beta emission with high enough
energy to actually penetrate the surface layers. But most of the beta generated inside the rod
will never show up as beta, it will just be moving electrons inside the conductor with a high
kinetic energy.
Still, all the fuss about beta... I never heard anyone complain back when we didn't have LCD and
TFT screens yet and everyone spent the entire day in front of a large beta cannon, seperated
from the very same horrible beta radiation by nothing more than a sheet of glass.
Do you suppose such a fuss would have developed around those as well if they had called
them "beta radiation cannons" instead of the much more friendly "cathode ray tubes"?
Yes, you don't want high levels of beta radiation to hit your skin or any other tissue for more
than an instant. Just like you don't want high levels of any other form of radiation to hit
any particular tissue.
But that doesn't immediately make everything with beta in it a lethal radiation hazard.

This is my theory on the subject anyway, and it's based on simple logic.

Yes, I agree. Or at least, it seems to make much sense to me.

Hello to all
this is my first result
(http://img124.imageshack.us/img124/6845/picture140lm4.jpg)
leo48

@ AbbaRue,
For equation J = ?CE? = 1 watt/second, the voltage is the change in open circuit voltage of the capacitor (before discharge minus after discharge) as measured with high impedance voltmeter. Equation is meaningless when the capacitor is connected to a low resistance load or a voltage source while measuring the voltage. When correctly measured, time is not relevant, only the change in voltage.

Actually the way the equation is written is confusing. ?CE? = change in Coulombs of charge in the capacitor of C farads. Amps are number of Coulombs flowing in wire per second. Watts = amps squared times load resistance in ohms. So I think the equation J = ?CE? = 1 watt/second is only true for C=1F, E=1V, and load resistance = 1 ohm. No, it even isn't true then. Bad equation.

@Xee
Looks like you are well versed in electronic theory.
If I discharge a 0.16 F cap. at 37V across a resistor for 200 microseconds.
What resistance do I need to get 108J.

A capacitor discharges in 5 time constants.  1 time constant = R * C, or rearranged (tau / C) = R, where tau is 40us.  This gives R=0.00025 ohms.

I still haven't heard any rebuttal of my 6Kw problem mentioned above...

Eldarion