Language: 
To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
  the storage of cookies while browsing this website, on Login and Register.

Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Free energy with multiplying force  (Read 2963 times)

Offline vikram_gupta11

  • Full Member
  • ***
  • Posts: 197
Free energy with multiplying force
« on: October 14, 2016, 09:37:52 AM »
There is a sketch 10 numbered flashlights(coil+magnet system) are mounted  permanently in horizontal direction  on this balanced seesaw. This seesaw will turn back and forth in horizontal direction.

in this design we are shaking 10 no. flashlights with the force of equal to shake a single flashlight(COIL+MAGNET) and these flashlight will work or glow up there is no doubt about it. we can take not only 10 no. flashlight but also 20,30,50 or more because remember the seesaw is in balanced position so again say that there is need of only small amount of energy to move it and also consider that this seesaw is just moving only 2 to 3 centimeter sideways so this is also an advantage .
Friction is very less,applying force is same as we are shaking 10 no. flashlights with the force of shaking a single flashlight.sideways momentum is only 2 to 3 centimeter then why this should not work?






A common flashlight required input is 2 watt when will apply 2 watt then it will be glowed up. There are 10 no. flashlights mounted on a beam and we are turning the one side arm in horizontal direction.The overall weight of this seesaw is 4 kilogram and the speed to turning the seesaw arm is .03 centimeter/second(Thrice in a second).
Now used the F=ma equation m=4kg and a=.03*3 =ma=0.36 watt,the input is 0.36 watt but it will be not sufficient for flashlights to glow up as each flashlight want 2 watt input to counter lenz law So I add 2 watt more and now input is 2+ .36 watt and more 1 watt to counter mechanical loss so now total input is now 3.36 watt.
when we will apply this 3.36 watt input in seesaw arm then all 10 numbered flashlight will be start to shaking after consuming this input as this input will be distributed equally in all flashlights or in otherwords 3.36*10= 33.6watt and if each flashlight output is only 1 watt then overall output will be 10 watt which will be greater than input.

Input= 3.36 watt
each flashlight getting input=3.36 watt
10 flashlight getting input=33.6 watt
each flashlight output=1 watt
10 numbered flashlights output=10 watt
there will be no need of of applying 10 time more force or input in this design only one time 3.36 watt input will be sufficient for all 10 numbered flashlights due to this design as it will work to multiply the force.
For example if there are 10 passengers in a car and car is moving at the speed of 100 km/hour then the speed of each passenger will be also 100km/hour so I have used this example to multiply the force. This seesaw will work to balance the mass and multiply the force.
suppose this balanced system is a running car and each coil +magnet system is a passenger so these all 10 numbered coil+magnet will get equal amount of force and overall output will be greater than input.