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Author Topic: Fun Capacitor Circuit  (Read 11066 times)

Offline pg46

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Fun Capacitor Circuit
« on: June 11, 2006, 07:38:28 PM »
Hi all-

 Had a different Capacitor Set-up for those that want to try it out themselves or for those who just want to think about it.
Take 3 capacitors all the same. I used 35V - 22,000uf caps in this example. All are empty except that I will charge only C1 to 12 volts from source...here we go..
Charge C1 to 12 Volts, hook C1 neg to C2 neg, then take C2 pos and connect to C3 neg and finally take C3 pos back over to C1 pos.
 What you get is about 8V left in C1 and you get about 4Volts in each C2 and C3. Where you began with 12volts, now you have a total of 16 volts at 22,000uf - C1+C2+C3. about a 30% gain.
 Now, if you then use the stored energy in C2 and C3 to do some work they will now be empty and that leaves only the 8volts of the original charge in C1. So then you charge C1 back to 12 volts(thats only adding in 4 volts of additional energy), connect the ciruit again as described above and once again you end up with about 8 volts in C1 and 4 volts each in C2 and C3 again. Only this time around you only added 4 volts to top off C1 and have gained 8volts on C2 and C3(4 volts each)-thats now a 200% gain.  Use the charge in C2 and C3 to do the work again and repeat the cycle.
 I have used my small dc motors to discharge the caps and carefully timed the running times for the various charges and indeed they correspond to the correct charges in each cap - more volts means more runing time.
 Not likely,according to the energy formulas, that one has gained in energy but then you can run some motor much much longer than with the original 12 volt charge..hmmmm??...

best,

Free Energy | searching for free energy and discussing free energy

Fun Capacitor Circuit
« on: June 11, 2006, 07:38:28 PM »

Offline hartiberlin

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Re: Fun Capacitor Circuit
« Reply #1 on: June 12, 2006, 01:02:31 AM »
Hi PG46,
did you test out, if C1 alone at 12 Volts has a shorter running time
than C1 +C2 +C3 in series at 16 Volts ?
As the series capacity is then only 7333 uF with the 16 Volts
it has about 1,7 times less energy stored all in all in C1 +C2 +C3
than 12 Volts in 22000 uF.
As the stored energy is W=0.5 x C x V^2
the 12 Volts cap C1 should run longer...
If not you have found a mysterious energy multiplication...

Offline pg46

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Re: Fun Capacitor Circuit
« Reply #2 on: June 12, 2006, 05:04:35 AM »
Hi hartiberlin-

 The original C1 cap charged to 12 volts will run far less time then all the caps combined after my ciruit(C1+C2+C3) After the circuit I then reconnect C1,C2 and C3 in parallel which gives me 16volts @ 22,000uf At no point do I connect C1, C2 ad C3 in series excepting between C2 and C3 in the original charging.
 Using the energy formula as you posted W=0.5xCxV^2 , the original 12 V cap would have 0.5x.022x144=1.584Joules
 Then after my strange circuit I end up with C1 at 8 volts and C2 at 4 volts each
So C1 now has 0.5x.022x64=0.704 Joules  C2&C3 each have 0.5x.022x16=0.176joules
These 3 caps combined now only have 1.056 joules which is far less then the 1.584 joules that was in the original 12volt cap.
 See, if we take a single 12 volt cap and connect in parallel with 2 others the same we end up with 3 seperate caps charged to 4 volts each. Even though these are 12 volts combined, according to the energy formula these three combined don't add up to the original 12 volt charge (3 x 0.176=0.528) The original 12 volt cap has 1.584 joules
 So, does my little ciruit have any value, I don't know. You surely can run a motor much much longer than when using only the original 12 volts, although I am not testing under any load. Its real interesting after the first round if you use the energy in C2 and C3 and then top off C1 with just 4 additional volts to have 4 volts to use in each C2 and C3 again.
 
Best,

Free Energy | searching for free energy and discussing free energy

Re: Fun Capacitor Circuit
« Reply #2 on: June 12, 2006, 05:04:35 AM »
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Offline pg46

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Re: Fun Capacitor Circuit
« Reply #3 on: June 12, 2006, 05:46:32 AM »
Then after my strange circuit I end up with C1 at 8 volts and C2 at 4 volts each

oops, this should read- Then after my strange circuit I end up with C1 at 8 volts and C2 and C3 at 4 volts each

 Another way one could look at this circuit is where with one 12 volt cap one  normally can get only 3 - 4 volt caps when hooked in parallel with 2 other caps.
 Now with my circuit one can begin with a 12 volt cap and end up with 4 seperate 4 volt caps :)

Offline Elvis Oswald

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Re: Fun Capacitor Circuit
« Reply #4 on: June 12, 2006, 06:30:23 AM »
Let me ask so I know... these caps are good either way, so the neg and pos doesn't matter really, right?

Free Energy | searching for free energy and discussing free energy

Re: Fun Capacitor Circuit
« Reply #4 on: June 12, 2006, 06:30:23 AM »
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Offline pg46

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Re: Fun Capacitor Circuit
« Reply #5 on: June 12, 2006, 06:43:21 AM »
No, all the caps I am using  are clearly marked pos and neg. One must be very careful when charging the caps to connect properly and not to exceed the rated voltage capacity neither as otherwise they can explode or at the minumum ruin your capacitor.

Offline Elvis Oswald

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Re: Fun Capacitor Circuit
« Reply #6 on: June 12, 2006, 06:56:52 AM »
so they are polarized caps?

Free Energy | searching for free energy and discussing free energy

Re: Fun Capacitor Circuit
« Reply #6 on: June 12, 2006, 06:56:52 AM »
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Offline hartiberlin

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Re: Fun Capacitor Circuit
« Reply #7 on: June 12, 2006, 10:37:42 AM »
<After the circuit I then reconnect C1,C2 and C3 in parallel which gives me 16volts @ 22,000uf
......

How do you get 16 Volts, when you put all 3 caps in parallel again ??? Then you have 66000 uF at 16 Volts ???

Offline pg46

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Re: Fun Capacitor Circuit
« Reply #8 on: June 13, 2006, 08:58:57 AM »
Question: How many caps charged to 4 volts could one get from a single cap charged at 12 volts?

Hi - Sorry have been away travelling and so am with little computer access for a few days.

Elvis-
Yes, the caps I use are polarized.

 hartiberlin -
 Sorry about the voltage confusion. I will try to reword it a bit better. In my example from my 1st posting I might say instead that I have gained an extra cap charged at 4 volts than I would have otherwise.
 How is that so?
 
 Well lets see, if in set up #1 one takes a cap charged to 12 volts and hooked it in parallel with two other empty caps then one ends up with 3 caps charged at 4 volts each which is standard since the voltage is divided evenly amongst the caps. If in setup #2, one takes a 12 volt charged cap but uses my circuit instead you'll wind up with 4 caps charged at 4 volts each. 8) there, thats better
 Sorry however, as I haven't been able to get to 16 volts with the same capacitance I stared out with.  :-[
 Nevertheless, where most folks will want to answer the first question of "how many 4 volt caps can one get from a 12 volt cap?" with a 3,  I can answer it with "4 at the very least"   ;)

Free Energy | searching for free energy and discussing free energy

Re: Fun Capacitor Circuit
« Reply #8 on: June 13, 2006, 08:58:57 AM »
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Offline FreeEnergy

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Re: Fun Capacitor Circuit
« Reply #9 on: June 13, 2006, 09:33:50 AM »
pg46 please post picture(s)

Offline hartiberlin

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Re: Fun Capacitor Circuit
« Reply #10 on: June 13, 2006, 11:07:04 AM »
but you claim you get more energy alltogether in all caps.. so do you put then all 3 or 4 caps in series or what ? I am now totally confused and don?t know what you are doing exactly... please describe again in detail how you get the motor to run longer compared to the standard 12 volts single cap. Thanks.

Free Energy | searching for free energy and discussing free energy

Re: Fun Capacitor Circuit
« Reply #10 on: June 13, 2006, 11:07:04 AM »
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Offline pg46

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Re: Fun Capacitor Circuit
« Reply #11 on: June 15, 2006, 08:00:29 AM »
Hi All-

 Sorry for the delayed responses, as like I said before I haven't steady access to internet just now since I am currently travelling.
 hartiberlin-
 If we put the energy formulas aside for the moment.
  Let me say here first that it is far easier to actually do the circuit than to write about it  :D Let's run through it again here anyhow-
1)Take 3 identical caps 2) lets call them C1,C2 and C3   3)charge C1 to 12 volts 4)connect C1 neg to C2 neg 5) connect C2 pos to C3 neg 6) finally connect C3 pos back over to C1 pos
 You will end up with approx. 8 volts in C1 and 4 volts in each C2 and C3  - thats it !

Best,

Offline FreeEnergy

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Re: Fun Capacitor Circuit
« Reply #12 on: June 15, 2006, 09:56:55 AM »
there is a saying - energy cannot be destroyed or created, it can only change form - somewhere in quantum physics
« Last Edit: June 15, 2006, 10:16:36 AM by FreeEnergy »

Offline NerzhDishual

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Re: Fun Capacitor Circuit
« Reply #13 on: June 15, 2006, 10:55:45 PM »
Hi pg46 

Is that what you really mean?
Sounds not 'conventional'. :D
Anyway, I will try it.

Best

(http://jeanyves.hervouet.free.fr/4overun2/caps_1.gif)
(http://jeanyves.hervouet.free.fr/4overun2/caps_2.gif)
(http://jeanyves.hervouet.free.fr/4overun2/caps_3.gif)
(http://jeanyves.hervouet.free.fr/4overun2/caps_4.gif)
(http://jeanyves.hervouet.free.fr/4overun2/caps_5.gif)
(http://jeanyves.hervouet.free.fr/4overun2/caps_6.gif)


Offline NerzhDishual

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Re: Fun Capacitor Circuit
« Reply #14 on: June 16, 2006, 01:14:01 AM »
Hi everybody and especially pg48

Should I be understood when craming my own stuff into this one: a quote from pg48   
Quote
See, if we take a single 12 volt cap and connect in parallel with 2 others the same we end up with 3 seperate caps charged to 4 volts each. Even though these are 12 volts combined, according to the energy formula these three combined don't add up  to the original 12 volt charge (3 x 0.176=0.528) The original 12 volt cap has 1.584 joules.

That is exactly what I was saying in another post. When you parallel-connect 2 or more caps, it appears  that you are loosing NRG, as pg46 is pointing out with his 3 caps (1.584 joules vs 0.528 joules).

Should I be allowed to 'self-quote' my May 16, 2006 post to "free energy circuit setup"? (It was about 2 caps and the "lost NRG".)

Quote
Not at all, said my physics textbook!
The reasoning is (sorry for my translation, but the French text is not so limpid):There have been production of another energy that the electric charging energy of the second cap. The wires between the two cap have been travelled by an electric current which have produced in these wires a calorific energy w''. This calorificNRG does not depends upon the resistance of the wires and represents the difference w-w'' wich equals W/2.

Ok scientists...
So, when I put a motor betwen the two caps, I guess that the calorific NRG should vanish as I have the same results (V/2 for each cap) plus a motor running. [...]
Sorry, but I can not help smelling a rat.

That is what I was saying a couple of weeks ago.
I can say that again.

The caps's behavior seems to be strange.
But, the  experimenter creativity is infinite.

Best


 

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