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Author Topic: Confirming the Delayed Lenz Effect  (Read 779634 times)

Offline CRANKYpants

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Re: Confirming the Delayed Lenz Effect
« Reply #390 on: October 24, 2011, 08:10:44 PM »
Hi everyone,

just a quick update of how one could use an off the self Transformer with a small Capacitance in Series to create a Delayed Lenz Effect or Phase Shift.

Power out is 10.8 Watts

Power in is Reactive 0 Watts

Luc

OUTPUT POWER = 10.8 WATTS
INPUT TRUE POWER = 1.97 WATTS
EFFICIENCY = 10.8/1.97 x 100 = 548.2 %

REACTIVE POWER = 147.4 VAR

CAN ANYONE FIND AN ERROR IN MY MATH?  ;)

BTW ITS NOT DELAYED LENZ BUT "SHIFTED LENZ" AND WHY TESLA INVENTED BI-FILAR WINDINGS TO GET RID OF THE EXTERNAL CAPACITORS.

CHEERS
T
« Last Edit: October 24, 2011, 08:34:38 PM by CRANKYpants »

Offline CRANKYpants

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Re: Confirming the Delayed Lenz Effect
« Reply #391 on: October 24, 2011, 08:30:48 PM »
Fantastic. ;)

But I think you should not stop here. Because if everyone would use reactive power then el. energy companies would start sending bills for reactive power.

Keep up the good work. ;)

Electronic meters display the energy used on an LCD or LED display, and can also transmit readings to remote places. In addition to measuring energy used, electronic meters can also record other parameters of the load and supply such as maximum demand, power factor and reactive power used etc. They can also support time-of-day billing, for example, recording the amount of energy used during on-peak and off-peak hours.


Offline wings

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Re: Confirming the Delayed Lenz Effect
« Reply #392 on: October 24, 2011, 08:49:46 PM »
OUTPUT POWER = 10.8 WATTS
INPUT TRUE POWER = 1.97 WATTS
EFFICIENCY = 10.8/1.97 x 100 = 548.2 %

REACTIVE POWER = 147.4 VAR

CAN ANYONE FIND AN ERROR IN MY MATH?  ;)

BTW ITS NOT DELAYED LENZ BUT "SHIFTED LENZ" AND WHY TESLA INVENTED BI-FILAR WINDINGS TO GET RID OF THE EXTERNAL CAPACITORS.

CHEERS
T


In Europe we pay an extra cost if the reactive power is below phase 0.9 

Offline CRANKYpants

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Re: Confirming the Delayed Lenz Effect
« Reply #393 on: October 24, 2011, 09:08:48 PM »
In Europe we pay an extra cost if the reactive power is below phase 0.9

NOW ALL LUC HAS TO DO IS:

1) TAKE A BATTERY INVERT THE OUTPUT TO AC
2) RUN IT THROUGH HIS "SIDEWAYS" TRANSFORMER
3) BUMP IT UP BY 500%
4) RECTIFY IT
5) FEED THE OUTPUT INTO ANOTHER BATTERY AT 5 TIMES THE 1ST BATTERY INPUT
6) RUN LIKE HELL... 8)

T

Offline wings

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Re: Confirming the Delayed Lenz Effect
« Reply #394 on: October 24, 2011, 09:15:36 PM »
NOW ALL LUC HAS TO DO IS:

1) TAKE A BATTERY INVERT THE OUTPUT TO AC
2) RUN IT THROUGH HIS "SIDEWAYS" TRANSFORMER
3) BUMP IT UP BY 500%
4) RECTIFY IT
5) FEED THE OUTPUT INTO ANOTHER BATTERY AT 5 TIMES THE 1ST BATTERY INPUT
6) RUN LIKE HELL... 8)

T

 ;D ;D ;D

great

Offline gotoluc

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Re: Confirming the Delayed Lenz Effect
« Reply #395 on: October 24, 2011, 09:18:51 PM »
Electronic meters display the energy used on an LCD or LED display, and can also transmit readings to remote places. In addition to measuring energy used, electronic meters can also record other parameters of the load and supply such as maximum demand, power factor and reactive power used etc. They can also support time-of-day billing, for example, recording the amount of energy used during on-peak and off-peak hours.

Hi Thane,

thanks for doing all the full power calculations.

In the case the Utility Company would start charging for Reactive Power. Would that be for the 1.97 Watts used?

Just wondering :-\

Luc

Offline CRANKYpants

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Re: Confirming the Delayed Lenz Effect
« Reply #396 on: October 24, 2011, 09:26:31 PM »
Hi Thane,

thanks for doing all the full power calculations.

In the case the Utility Company would start charging for Reactive Power, would that be for the 1.97 Watts used?

Just wondering :-\

Luc

PROBABLY MORE LIKE (147.4 x 0.9) - 133.1 = 14.3 WATTS  :'( GIVE OR TAKE.

BUT IF YOU FOLLOW MY INSTRUCTIONS ABOVE YOU'LL BE ABLE TO POWER YOUR ELECTRIC SAIL BOAT ALL THE WAY TO AFRICA AND BACK WITH ONLY TWO BATTARIES.

CHEERS
T

Offline gotoluc

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Re: Confirming the Delayed Lenz Effect
« Reply #397 on: October 24, 2011, 09:32:13 PM »
PROBABLY MORE LIKE 147.4 x 0.9 = 132 WATTS  :'( GIVE OR TAKE.

BUT IF YOU FOLLOW MY INSTRUCTIONS ABOVE YOU'LL BE ABLE TO POWER YOUR ELECTRIC SAIL BOAT ALL THE WAY TO AFRICA AND BACK WITH ONLY TWO BATTARIES.

CHEERS
T

Wow :o... that's a rip off.

I'll get the H-Bridge out and make my own Power.

Will update in a couple of days

Luc

Offline wings

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Re: Confirming the Delayed Lenz Effect
« Reply #398 on: October 24, 2011, 10:36:48 PM »
NOW ALL LUC HAS TO DO IS:

1) TAKE A BATTERY INVERT THE OUTPUT TO AC
2) RUN IT THROUGH HIS "SIDEWAYS" TRANSFORMER
3) BUMP IT UP BY 500%
4) RECTIFY IT
5) FEED THE OUTPUT INTO ANOTHER BATTERY AT 5 TIMES THE 1ST BATTERY INPUT
6) RUN LIKE HELL... 8)

T

driving form zero to 16 KHz (with Arduino)

http://interface.khm.de/index.php/lab/experiments/arduino-dds-sinewave-generator/

this circuit in pure sinusoidal way
 
http://www.kerrywong.com/2010/03/12/a-power-inverter-with-arduino-pulse-source/

or use PWM ?

or other resonant circuit?

Offline futuristic

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Re: Confirming the Delayed Lenz Effect
« Reply #399 on: October 24, 2011, 10:57:04 PM »
I bought this for arduino to make DIY signal generator:
http://iteadstudio.com/store/index.php?main_page=product_info&cPath=18&products_id=414

But I don't know how to amplify the signal to get something in the range 20V 3A AC. Probably something like powerful audio amplifier?

Offline gyulasun

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Re: Confirming the Delayed Lenz Effect
« Reply #400 on: October 25, 2011, 12:37:21 AM »
...
BTW ITS NOT DELAYED LENZ BUT "SHIFTED LENZ" AND WHY TESLA INVENTED BI-FILAR WINDINGS TO GET RID OF THE EXTERNAL CAPACITORS.


Hi Thane,

My understanding on Tesla patent on Coil for electromagnets
http://www.tfcbooks.com/patents/coil.htm is that he neutralized the coil's inductance with the capacitance attained between the bifilar wires so that the input current found resistance only that of the coil's DC resistance. Does not this mean resonance and if it does then it could not give 90° phase shift but zero degree only?
Quote: "I have found that in every coil there exists a certain relation between its self-induction and capacity that permits, a current of given frequency and potential to pass through it with no other opposition than that of ohmic resistance, or, in other words, as though it possessed no self-induction". Unquote

So he did get rid of the external capacitors with using the  'distributed capacitance of parallel wires but then he must have got a phase shift of near or at zero degree. 

rgds,  Gyula

Offline kEhYo77

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Re: Confirming the Delayed Lenz Effect
« Reply #401 on: October 25, 2011, 03:24:58 AM »
Great news gotoluc! In the back of my mind I knew it was possible.
For those of you interested in building a cheap, pure sine wave inverter, here is a nice pdf:
http://www.megaupload.com/?d=P4PEGQ6Q

Offline gotoluc

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Re: Confirming the Delayed Lenz Effect
« Reply #402 on: October 25, 2011, 08:59:04 AM »
At everyone,

I connected the circuit to my H-Bridge but used 12vdc first so not to blow things up. The results are not the same then with the grid 120vac 60Hz sine wave.

There could be a mistake somewhere :-\ so lets look at this over carefully. Maybe the power meter I'm using is being fooled in this kind of configuration?

A youtube user posted this: "Sorry Luc, but I have to correct you on the voltage leading the current. In a capacitive circuit the current leads the voltage. This is what your scope is showing. Scope traces go from left to right with time."

I thought it was the other way around?... but I may not have it correct. Can you look over the scope shot below and comment.

I think a pure sine wave output inverter would help confirm but I don't have one. Only modified sine wave I have. I'll give that a try and let you know.

Thanks for sharing

Luc

Offline Overunityguide

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Re: Confirming the Delayed Lenz Effect
« Reply #403 on: October 25, 2011, 09:50:05 AM »
At everyone,

I connected the circuit to my H-Bridge but used 12vdc first so not to blow things up. The results are not the same then with the grid 120vac 60Hz sine wave.

There could be a mistake somewhere :-\ so lets look at this over carefully. Maybe the power meter I'm using is being fooled in this kind of configuration?

A youtube user posted this: "Sorry Luc, but I have to correct you on the voltage leading the current. In a capacitive circuit the current leads the voltage. This is what your scope is showing. Scope traces go from left to right with time."

I thought it was the other way around?... but I may not have it correct. Can you look over the scope shot below and comment.

I think a pure sine wave output inverter would help confirm but I don't have one. Only modified sine wave I have. I'll give that a try and let you know.

Thanks for sharing

Luc

Hi Luc,

Great Video...

Wattmeters base their reading on: E * I * cos(phi) or (power factor).

I am curious if your power meter is capable of showing the power factor. My power meter can show this value, and it shows me also if the load is running inductive or if it is running capacitive. I think that displaying that (those three individual values: E * I * cos(phi)) will help you a-lot.

With Kind Regards, Overunityguide
« Last Edit: October 25, 2011, 10:50:11 AM by Overunityguide »

Offline hoptoad

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Re: Confirming the Delayed Lenz Effect
« Reply #404 on: October 25, 2011, 11:10:16 AM »
I bought this for arduino to make DIY signal generator:
http://iteadstudio.com/store/index.php?main_page=product_info&cPath=18&products_id=414

But I don't know how to amplify the signal to get something in the range 20V 3A AC. Probably something like powerful audio amplifier?

Look around in some recycle electronics shops or even pawn shops for a pre 1980,s analogue amplifier. Old record players are a good source for dual channel analogue amps.

Digital amps for this type of experimenting are not really a good choice as many of them employ a direct coupled output, with a DC offset bias, which will affect your primary winding current consumption in a negative way. This is rare with analogue amps.

Besides that, old analogue amps are usually dirt cheap.

Cheers.