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Author Topic: Eliminate Lenz's current  (Read 5400 times)

Offline vineet_kiran

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Eliminate Lenz's current
« on: June 12, 2011, 09:27:06 AM »
Eliminate Lenz's current by varying number of turns.

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Eliminate Lenz's current
« on: June 12, 2011, 09:27:06 AM »

Offline teslaalset

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Re: Eliminate Lenz's current
« Reply #1 on: June 12, 2011, 10:40:52 AM »
Eliminate Lenz's current by varying number of turns.

If you're trying to propose OU with this idea, then you should keep in mind that it takes energy to push the windings together.
It's the total energy balance which should be kept in mind.

Nice puzzle though ;)

Offline broli

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Re: Eliminate Lenz's current
« Reply #2 on: June 12, 2011, 11:24:06 AM »
I suggest you read this thread:

http://www.energeticforum.com/renewable-energy/7113-spark-gap-step-down-transformer-ou.html

It has many case studies on what happens to flux, energy and other paremeters when one or more parameters of an inductor are changed.

In your case you decrease the windings, this will cause the current to increase proportionally, however in the energy equation both are squared so the total energy remains unchanged. Besides that you are also changing the length, decreasing length usually means a loss of inductive energy, as the windings naturally attract each other, so what you lose inductivly you have gained mechanically.



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Re: Eliminate Lenz's current
« Reply #2 on: June 12, 2011, 11:24:06 AM »
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Offline Airstriker

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Re: Eliminate Lenz's current
« Reply #3 on: June 13, 2011, 02:46:50 PM »
In your case you decrease the windings, this will cause the current to increase proportionally, however in the energy equation both are squared so the total energy remains unchanged. Besides that you are also changing the length, decreasing length usually means a loss of inductive energy, as the windings naturally attract each other, so what you lose inductivly you have gained mechanically.
Why the current should increase ? It shouldn't, as the total wire resistance is untouched. You're not removing a piece of wire from equation; you're just making a short circuit from the windings. Note, that the wire is not isolated.

Offline broli

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Re: Eliminate Lenz's current
« Reply #4 on: June 13, 2011, 03:06:29 PM »
Why the current should increase ? It shouldn't, as the total wire resistance is untouched. You're not removing a piece of wire from equation; you're just making a short circuit from the windings. Note, that the wire is not isolated.

The current increases due to flux conservation, when you short out the wires you are essentially creating one big loop of said current, this is not enough to maintain the already established flux due to the, previously, many loops. So the current will shoot up in order to maintain the existing flux.

Free Energy | searching for free energy and discussing free energy

Re: Eliminate Lenz's current
« Reply #4 on: June 13, 2011, 03:06:29 PM »
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Offline allcanadian

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Re: Eliminate Lenz's current
« Reply #5 on: June 14, 2011, 06:46:26 AM »
@Vineet Kiran
That's an interesting concept which is fairly well known because the same process is used in EMP weapons however with EMP devices the compression is performed by high explosives.
If we have a constant current source such as a battery connected to a coil then this coil will have a uniform magnetic field which surrounds each conductor. This magnetic field follows the inverse square law and gets progressively stronger the closer we get to the conductor. Now whenever we have a changing magnetic field and this change in the field influences a conductor we call this self-inductance and this produces a potential difference in the conductor. As such when your spring is compressed the magnetic field must change and this change must induce a voltage in the conductor thus a current because the circuit is closed.
This is how an EMP device works, a capacitor produces an initial high current in a coil and then high explosives "move" the coil very fast and the self-induction produces a massive current in the coil of millions of amperes. As the coil is blown apart it gets progressively smaller and the smaller the coil gets the more current is generated because the magnetic field around the conductor gets stronger the closer we get to the conductor following the inverse square law.

It is interesting to note that Ampere stated --- the magnetic field should be considered as distinct from the source which produced it however any change in force on the field must always translate back to the source.
Regards
AC

Offline vineet_kiran

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Re: Eliminate Lenz's current
« Reply #6 on: June 15, 2011, 06:44:55 AM »
Thanks for the information

Regards
Vineet.K.

Free Energy | searching for free energy and discussing free energy

Re: Eliminate Lenz's current
« Reply #6 on: June 15, 2011, 06:44:55 AM »
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