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Mechanical free energy devices => mechanic => Topic started by: billmehess on May 03, 2011, 06:54:33 AM

Title: SMOT - Next Video
Post by: billmehess on May 03, 2011, 06:54:33 AM
Here is the youtube link.
http://youtu.be/wKC1i3PCtpQ

I can now exit the SMOT down the uchannel at a greater height than the entry height.
Bill
Title: Re: SMOT - Next Video
Post by: billmehess on May 04, 2011, 12:26:40 AM
I have received a couple of emails regarding this video. Yes the exit point off the uchannel is higher than the entry point to the SMOT. Stay tuned.
Bill
Title: Re: SMOT - Next Video
Post by: hartiberlin on May 12, 2011, 07:47:42 PM
Well done Bill,
try to get it looping.

Try to use the braioschtoire principal
to get it back to the entrance.
Title: Re: SMOT - Next Video
Post by: billmehess on May 13, 2011, 06:11:05 AM
Well done Bill,
try to get it looping.

Try to use the braioschtoire principal
to get it back to the entrance.
What is the braioschtoire principal?
Also in my continuing work on a self looping SMOT I have found a way to have the ball propel itself
off the end of the uchannel instead of the normal dropping off. Just a thought here, since the ball enters the uchannel at a fairly low speed but shoots off the end of the uchannel at an incline it would appear logical to think that there is more energy out than in. Is this correct?
Title: Re: SMOT - Next Video
Post by: gyulasun on May 13, 2011, 03:50:02 PM
Hi Bill

here is a wiki link to brachistochrone problem: http://en.wikipedia.org/wiki/Brachistochrone_curve 

and some videos on youtube:
http://www.youtube.com/results?search_query=brachistochrone+problem&aq=0

"What's the fastest path between two points? A cycloid, the solution to the Brachistrochrone problem."

Unfortunately, the "academic circles" simply state the energy of the ball coming down on the cycloid curve is the same as that of the ball coming down on the linear ramp.

MHO is you surely can come better off when you choose such cycloid shaped plastic tube for the ball when trying to loop and NOT letting the ball fall and bump anywhere (bumping causes the most loss occuring).

Gyula
Title: Re: SMOT - Next Video
Post by: billmehess on May 13, 2011, 04:29:54 PM
Unfortunately this is not a solution to my work,  notice that both slopes are extreme. Any kind of slope will return the ball to the entry point and that is all I am working towards.
Bill
Title: Re: SMOT - Next Video
Post by: mscoffman on May 13, 2011, 08:02:11 PM
What is the braioschtoire principal?
Also in my continuing work on a self looping SMOT I have found a way to have the ball propel itself
off the end of the uchannel instead of the normal dropping off. Just a thought here, since the ball enters the uchannel at a fairly low speed but shoots off the end of the uchannel at an incline it would appear logical to think that there is more energy out than in. Is this correct?


Is this correct? - Affirmative. The ball is on a ballistic trajectory modified
by any residual R^2 magnetic array attraction (in any case) but shooting
it off means there was more energy. The distance it impacts a sunken flat
plane away from the end of the ramp could be used to estimate it's momentum
energy. Further is higher... As usual, good luck.

---

braioschtoire principal -> The formal name given by mathematicians
to the tendency of the gravity affected spheres to have different
intermediate speeds on one track curvature vs another. The name of
the analysis that gives correct answers.


:S:MarkSCoffman
Title: Re: SMOT - Next Video
Post by: billmehess on May 13, 2011, 08:57:14 PM
Is this correct? - Affirmative. The ball is on a ballistic trajectory modified
by any residual R^2 magnetic array attraction (in any case) but shooting
it off means there was more energy. The distance it impacts a sunken flat
plane away from the end of the ramp could be used to estimate it's momentum
energy. Further is higher... As usual, good luck.

:S:MarkSCoffman

Thank you Mark
Is this then a definitive example and proof of OU?
Title: Re: SMOT - Next Video
Post by: hartiberlin on May 14, 2011, 03:55:56 AM
Hi Bill,
Greg Watson said, that you can only get the ball away from the ramp as in your case,
when it falls deeper than the entrance and then bring it up again to the entrance.

For this reason this brachistochrone principle would be great !
(sorry for me wrong spelling in my last post here...)

Good luck,

Regards, Stefan.
Title: Re: SMOT - Next Video
Post by: futuristic on May 14, 2011, 10:45:51 AM
I  have never seen anyone trying this setup (in the attachment).

Figure 1:
Hold magnet above the exit point of the ramp. Try to find the distance/position where magnet helps pulling the steel ball away from the rail, but at the same time the magnet should be far enough that steel ball doesn't jump and stick on it.

Figure 2:
You could also try with two magnets in attraction mode, but separated by an inch or less, which would continue the magnetic field of the smot in the air.

Happy building ;)
Title: Re: SMOT - Next Video
Post by: billmehess on May 14, 2011, 03:15:41 PM
This will not work. The ball will be attracted to the magnet. This was one of the very first things I had tried months ago.
Think about it... if the magnet is strong enough to be attracted to the ball then that force only becomes stronger as the ball approaches the magnet.
For this to work the magnet must be pulled away as the ball approaches it. Only this changes the attractive forces and allows the magnet to arc up and then down to a higher plane.
Bill