To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
  the storage of cookies while browsing this website, on Login and Register.

Storing Cookies (See : ) help us to bring you our services at . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Charging Batteries from Batteries part 2. Free Energy?  (Read 35190 times)

Offline Tito L. Oracion

  • Hero Member
  • *****
  • Posts: 2203
Re: Charging Batteries from Batteries part 2. Free Energy?
« Reply #45 on: November 25, 2011, 01:10:42 AM »
Great idea danny  ;)


Offline TheCell

  • Sr. Member
  • ****
  • Posts: 285
Re: Charging Batteries from Batteries part 2. Free Energy?
« Reply #46 on: November 30, 2011, 07:50:48 PM »

With a 4 lead acid battery configuration, 2 in series loading 2 in parallel via a joule thief circuit , like shown in the attachment , it may be possible ,to charge the batteries by themself.
Notifying the ringing effekt , that causes energy be drawn from the ambient.

Ossi's circuit (experienced guy)
Imho it's not advantageous to apply a load during the charging process, because the dipole is destroyed then.
So remove the parallel stack , apply a load to it and write down volts amps and duration
(Energy consumed).
Then put the paralell stack back into the charging circuit and charge it full.

Exchange series and parallel stack
(prior parallel batteries now in series, and series batteries now parallel) simple
Charge the new parallel stack. When it's loaded , remove it from the charging circuit and apply
the load.  ... And so on. If the summary of the energy beeing drawn by the load exceeds
the capacity V * Ah of all 4 batteries you have your OU circuit.