The presence of a diode anywhere in the circuit produces ordinary electrolysis.
Even if there is no drawn diode in the "electric circuit", then the diode may be a different material of the electrodes.
If the material is the same, then the different area of the electrodes is also a diode.

If there is no diode, then there is no ordinary electrolysis and there is no gas. Two blade water heater.https://www.youtube.com/watch?v=MjJ1N4uJyV8
Don't do that, it's very dangerous!

Will we discuss ordinary electrolysis for the 100th time? Not tired?
  Try to do this, and then you won’t get a miracle without fakes.


 But I'd rather take on a more promising project.

If the material is the same, then the different area of the electrodes is also a diode.

Is this really right ?
p.s.
 I suggested here about a year ago another method invented by me.
Using pure alternating current, and not using diodes.
But as usual nobody no payed attention.

I need to show you old a movie
where for "electrolysis" I spend a large current = 6mA!
was made according to the precepts of Tesla...

How is your life on a stinking forum energyscience!?..
I saw you there often before

fifty replies for several years, on energyscience i don't think that it is many.
And serg speaks right.  Almost everything circuits contains this diode.
Because if was not have this diode,no one bubbles at all.   

In any case, when you create non-equilibrium conditions for electric current, you get a rectifier.

 A unipolar pulse current, or any current that does not have a positive component equal to a negative one, is not a pure alternating current.

This is an alternating current with a component of direct current.

And even if you have alternating current with equal energy positive and negative part and with absolutely identical electrodes in electrolyser, this current can be partially rectified when passing through the electrolyzer.

 How? If you have a positive pulse of 100 volts for 1 microsecond, and then a negative pulse of 1 volt for 100 microseconds.It seems to be the same, but a voltage of 1 volt usually does not lead to conductivity in electrolytes. The result of this is ordinary Faraday electrolysis.
https://simplifier.neocities.org/rectifier
https://www.youtube.com/watch?v=kam0f_UTb9c

Regarding electrolysis.

If the current through the electrolyzer is not symmetrical, then Faraday electrolysis occurs.

Nonlinear inductors and other elements of electrical circuits are not important.
 You have long been convinced that the decomposition of water by the correct alternating current does not occur. Even if the voltage is high.

Let's talk formally according to Stanley Meyer, although you can find worthy patents from other people.

Why did he accumulate voltage on the cell with a diode?

The literal decomposition of water by high voltage is extremely energy-consuming. Electrolysis has the highest efficiency at the lowest voltage. There are patents and articles that describe catalytic electrolysis processes at a voltage of less than 1.8 volts, even at 1 volt. Some even suggest that with the right catalysts, electrolysis or decomposition of water can be achieved even at 0 volts.

 Now we have to think.

 Why Stanley Meyer and other similar inventors need relatively high cell voltages?

Moreover, high-frequency, impulse and the like. Do you know how badly supports water these types of voltages? Even with distilled water, even with highly purified deionized water, I had problems with parameter instability and high voltage absorption in such purified  water.

But Meyer writes about ordinary natural water. Such water has a strong conductivity. Natural ordinary water practically makes a short circuit in Meyers small cells.

So, what is next? How could it even work then?

I hope you do not assume that the whole truth is written in patents?


I recently got a new idea. What if there was not quite water in the cells? Or even almost no water at all?
A liquid with high dielectric properties, in which some natural water is dissolved? Then everything falls into place.

For example, but maybe some other liquid:

https://en.wikipedia.org/wiki/Transformer_oil

just for study

Studied. We are talking about the decomposition of water vapor in an electric field using Stanley Meyer technology. You can find other people's patents for similar processes of decomposition of water vapor in an electric field.
It is probably fundamentally possible.
But where is the source of energy that will release more energy at the output than at the input?

In addition, your site talks about the decomposition of gas in plasma "according to Stanley Meyer technology."
But in the meantime, your site has a link to a video with a Meyer cell in which the liquid is clearly visible:
https://www.youtube.com/watch?v=eaO4RH5hmzg&t=1101s
In general, there are some other suggestions how to make the decomposition of water vapor energetically less expensive, but you are probably not interested.