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i drew the wires out to the side for visibility, but in actuality they'll have to be along the shaft to keep from interfering with the input charging brushes while they spin.

great work there!  may i ask where you obtained the "mesh" you used to make your cylinders??  i've tried to re-created those things using perforated aluminum cans, but i found that cutting and reshaping their cylindrical shape proved to be more of a problem than i could deal with....

Some of my "mesh" is homemade and some is bought. For the homemade ones I've used a hole punch, either pounding the punch with a hammer, or if the metal is thin enough, pushing it in by attaching the punch to a drill press in place of the drill bit and lowering it into the metal. These techniques at the bottoms of these two pages:
 http://rimstar.org/sdenergy/testa/potsmk2.htm
 http://rimstar.org/sdenergy/testa/potsmk4.htm
I then roll the end of a screwdriver handle (since it's sort of rounded and hard) over the holes to smooth the edges out. Then I roll the resulting sheet over a cylinder to get the right cylindrical shape.

I've also made homemade ones by drilling the holes if the metal is too thick for the above approaches.

The metals I've used are aluminium flashing from hardware stores, thinner metal sheets from craft stores (and ordering them if they didn't have what I wanted):
 http://www.ksmetals.com/craftprducts.html
and empty rectangular paint cans (because they're ferromagnetic, and rectangular because at least I'm starting with something flat, also these are ones that I buy empty so that they've never been used, and they're uncoated on the inside.)

For the store bought ones, I've just hunted around stores like Home Depot and craft stores looking at everything. The mesh in:
 http://rimstar.org/sdenergy/testa/276disksg2dcpsu3/05_276disk_grids2_DCPSU3_070719.JPG
was a layer from a filter found in Rona, a local hardware store like Home Depot. You usually find them in the air conditioner, stove range hood sections.

I've also have some that I ordered from:
 http://www.dickblick.com/products/amaco-wireform-mesh/#reviews
Photos of them can be found here:
 http://www.amaco.com/shop/product-368-wireform-metal-mesh.html

Getting the right preforated metal/mesh has always been a difficult thing.

on plauson::      i started out reading about it in some of his litterature, but in his #1540998 patent i believe its mostly discussed near the top, with bits and details down through the center, before he gets into the more complex machinery.

i started thinking along the lines of using the rotating motion of my wimshurst to operate the spinning portion of a plauson-hybrid device. this way i dont need a secondary drive mechanism.
basically what i came up with is an inverted plauson-machine.

That's exactly what I did too. The other difficulty I have is in attaching disks to shafts to get nice perpendicular motion. So I simply bought a Wimshurst machine off of ebay and took it apart:
 http://rimstar.org/equip/wimshurst_27cm.htm
(Geez... I guess one advantage of publicly documenting most everything is I always have a link  .)

the induced plates and transformer are the stator, and the charged plates rotate straight off the drive-shaft of the wimshurst.
i drew a basic picture of what i have in mind.

Thanks for the drawing. One thing I've learned recently is the issue of leakage between the rotor and stator where high voltage is involved and where your goal is to simply provide a high voltage for purposes of interacting with the electric field without transfering charge. If your stator or rotor has sharp edges and the voltage is high enough then charge will leak from one to the other. The solution is to either avoid sharp edges or use a lower voltage or both. I think that's why the testatika uses wires for it's sectors/rotor. I also think that's one reason my Hyde generator failed. I use wire sectors now (see attached.)
-Steve
http://rimstar.org   http://wsminfo.org

Thanks for the drawing. One thing I've learned recently is the issue of leakage between the rotor and stator where high voltage is involved and where your goal is to simply provide a high voltage for purposes of interacting with the electric field without transfering charge. If your stator or rotor has sharp edges and the voltage is high enough then charge will leak from one to the other. The solution is to either avoid sharp edges or use a lower voltage or both. I think that's why the testatika uses wires for it's sectors/rotor. I also think that's one reason my Hyde generator failed. I use wire sectors now (see attached.)
-Steve
http://rimstar.org   http://wsminfo.org

Interesting setup, could you post any more photos? ..I have some similar ideas;  ...I found some 'stained glass foiling tape' which is copper foil with an adhesive backing, I think that this may serve your purposes quite well also.  I found mine at hobby lobby and it requires less work for making sectors and comes in a variety of widths.  this website has some of those materials: www.diamondtechcrafts.com.

http://www.diamondtechcrafts.com/default.aspx?page=itemView&itemsysid=186031

I also figure that the spark gap of the whimhurst machine dictates the voltage difference prior to discharge, and that this distance is directly proportional to the radius / diameter of the rotor ( in some way ).

Additionally, you could create your own adjustable spark gap using a plastic or vinyl pipe and two screws whose inner thread diameter is equal to the inner diameter of the vinyl pipe.  ( just screw one screw into one end of the pipe and once into the other end, attach electrodes and use one of these screws to adjust the distance between the gap.  It may be best to use brass or copper screws for this, as the zinc plating on some screws will eventually blast off the ends and create a mess in the chamber.

Another way could be transforming the bidirectional energy (2wires, common) to an unidirectional impulse (1 wire) energy. Then, you can use an ignition coil to receive unidirectional high voltage and transform it to bidirectional low-voltage high current Pulsed DC.

Another way, as showed before, is to use the capacitive transformer. But in both cases you need to use unidirectional impulses as the input energy.
Perreault explains very well the circuitry to do that. Maybe some fractionation techniques must be envolved to accomplish that.

thinking i could drop 45VK down to 2300, then again down to 115V ... little did i realize, these things are designed for 2-3KV, when i pump 45KV through it, it sparks all over the place and doesnt do its job....

Putting 10-12 of the MOT's in series on the 45 KV side and then lowering the 115 VAC again might have worked.  You didn't have enough of the MOT's to begin with.

--Lee

@ Steven Dufresne
 from :

http://books.google.it/books?id=0RmkmrFxHM0C&pg=PA71&lpg=PA71&dq=%22the+super+tube%22+Moray&source=bl&ots=0rOGUKlrkV&sig=6UA4S52QSjdElnDEXD4pXXqlYf0&hl=it&ei=0Y8fS4WqO4St4Qb5n_zfCg&sa=X&oi=book_result&ct=result&resnum=7&ved=0CCoQ6AEwBg#v=onepage&q=%22the%20super%20tube%22%20Moray&f=false

@wings,
Thanks. I'm quite familiar with that diagram from Moray King's "Quest for Zero Point Energy". He derives it from Hyde's US patent 4897592 (see attached.) Hyde doesn't show any inductors but for the circuit to serve the function that Moray thinks it serves he adds the inductors.
-Steve
http://rimstar.org   http://wsminfo.org
PS. I highly recommend that book for anyone who's pursuing tapping ZPE and needs some ideas or stimulation.

Here's the patent:
#4,897,592

http://www.google.com/patents/about?id=HX4BAAAAEBAJ&dq=patent:4897592&as_drrb_ap=q&as_minm_ap=0&as_miny_ap=&as_maxm_ap=0&as_maxy_ap=&as_drrb_is=q&as_minm_is=0&as_miny_is=&as_maxm_is=0&as_maxy_is=

Sub-patent references to the main patent above:
#4,622,510
#4,595,852
#4,151,409
#4,127,804
#3,013,201
#2,522,106

--Lee

A lot of people have a hard time with evaluating the current in electrostatic systems.
So i felt the need to discuss the curent of an electrostatic discharge.

Now, when we measure electrostatic voltage potential - what we are actually measuring is a charge relative to some theoretical "zero value" being that of the charge held by the object recieving the discharge. We assume that an earth-ground holds a 'true zero' value.

Unlike current from a constant source, such as a generator or battery, the current from an electrostatic discharge is not constant. It takes the form of a symmetrical triangle-wave: increasing from 0 to peak during the first half of the discharge, then decreasing from peak to 0 during the second half. This makes accurately taking physical measurements of the current rather difficult.
Assymetry in this triangle-wave is a function of ionization of the dieletric and will not be included here.

What we will discuss is the method of calculating the peak current rating of a discharge, which occurs at 1/2 of the discharge-time (T)

To do this, we need to know two values:

1) Total Charge ( in Volts)
and
2) Discharge Time ( in seconds)

From this we can determine the rate of discharge, or change in Volts. 
Essentially:  Total Charge / Time of discharge
for example:
a charge of 13,020 V and a discharge time of 21.7 microseconds
gives us a rate of discharge of 600v per microsecond

The Peak Current of the discharge is:
                A(peak) = 1/2 change-in-V * K
where K is the dielectric constant
in the above example:  1/2 (600V/microsecond) * 1 (the dielectric constant of air)
gives us  300 microamps      below i have drawn how this triangle wave would look on a graph.

The 'mean-current' or average current of the discharge is a bit more complex, one would separate this graph into individual measurements, at say 1us intervals, add them together, then divide by the number of intervals to get the average current throughout the discharge.
which im not going to go through right now, but in this example would be something close to ..... 53 microamps give or take?

Hi sm0ky2 ! Just to tell you that you've made a little confusion: you talk about "charge", "discharge" where you should talk about "voltage", "drop of voltage".

Indeed, if you talk about "charge", it means "coulombs" and the ratio of "discharge" versus time is in coulombs/second, thus amps but pretty sure you knew it

Note:

VOLTAGE

is

HOW MUCH A UNIT OF "CHARGE"* IS "ENERGETIC"

in joules/coulomb.

(*a certain number of electrons)

You may not need this note but as I see often basic confusions around, I try to clear up them each time I can


But Very Thanks for sharing these formula, I didn't know

Regards,
Didier