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Author Topic: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?  (Read 71356 times)

HeairBear

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #90 on: November 05, 2009, 01:51:40 AM »
What about the materials the strings are made of? Most acoustics use either bronze or pig gut strings. Electrics have to use steel strings so the pickups can pickup the sound. Acoustics can not use normal electric pickups, so, that is the reason for mics and piezoelectric style pickups. Have any of you tried using electric strings on an acoustic? I know one of Wilby's acoustics does, I put them on it myself. Orca! The reason? Bronze strings tune up much tighter making the strings hard to press. Electric strings may sound tinny, but, playing acoustics can give a guy hand cramps after playing a set at a gig.

When one string is plucked, all the other strings will also vibrate, adding to the overall sustain, whether you can hear them or not. The same is true for pianos and all other stringed instruments. Using a single string of the same material on both guitars plugged into a good tuner may do the trick, but, I do not suggest it, for, doing so can warp the neck from lack of tension.

Maybe Danny Ferrington has some answers for such a test. Now, which one of you virtuosos is gonna make me a youtube video of them playing "Flight of the Bumble Bee"? Not the Nuno Bettencourt version either...

poynt99

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #91 on: November 05, 2009, 02:18:00 AM »
it is 'wilby', that is future tense. it is not 'is' nor 'was'... ::)

Maybe you should try getting drunk before you post then--you'd probably sound a hell of a lot more coherent.

You're a troll dude...and it's getting really old real fast. Take off eh!

.99

poynt99

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #92 on: November 05, 2009, 02:43:40 AM »
Pointy,
   Will rerun test with both through di box, no power to speaker, just using visual meter.

;)

Looking forward to the results.

.99

WilbyInebriated

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #93 on: November 05, 2009, 08:06:48 AM »
Maybe you should try getting drunk before you post then--you'd probably sound a hell of a lot more coherent.

You're a troll dude...and it's getting really old real fast. Take off eh!

.99
which words did you have trouble understanding? you should try something other than mythbusters 'science'.

i ask you to do it right (like i told tk) or tell you your 'test' is weak (like i told you about your 'sim') and you call me a troll. but yet, here you are in just about every thread offering your weak ass sauce tests as gospel (and science ::) ).

WilbyInebriated

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #94 on: November 05, 2009, 08:14:04 AM »
What about the materials the strings are made of? Most acoustics use either bronze or pig gut strings. Electrics have to use steel strings so the pickups can pickup the sound. Acoustics can not use normal electric pickups, so, that is the reason for mics and piezoelectric style pickups. Have any of you tried using electric strings on an acoustic? I know one of Wilby's acoustics does, I put them on it myself. Orca! The reason? Bronze strings tune up much tighter making the strings hard to press. Electric strings may sound tinny, but, playing acoustics can give a guy hand cramps after playing a set at a gig.

When one string is plucked, all the other strings will also vibrate, adding to the overall sustain, whether you can hear them or not. The same is true for pianos and all other stringed instruments. Using a single string of the same material on both guitars plugged into a good tuner may do the trick, but, I do not suggest it, for, doing so can warp the neck from lack of tension.

Maybe Danny Ferrington has some answers for such a test. Now, which one of you virtuosos is gonna make me a youtube video of them playing "Flight of the Bumble Bee"? Not the Nuno Bettencourt version either...

well said heair, but it's hopeless to get them to apply anything other than their mythbusters brand of science to anything.

The Observer

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #95 on: November 05, 2009, 03:36:50 PM »
Willy,
Quote
          it "sucks" it out... LOL

      This statement let's me know you are smarter than the average drunk.

Spoondini,

        I thank you for your willingness to experiment with your guitars.

Heairbear,
         
Quote
When one string is plucked, all the other strings will also vibrate, adding to the overall sustain

       Thankyou, Thankyou....Thankyou.
       This is my very poynt.
       This is what I am talking about.

      A Louder Longer Sound is produced because feedback is happening and energy is stored in the system.
      ______________________________________________________________________________

The real question is ... Does the Acoustic Chamber Amplify Sound?        YES  (refer below)

Consider this simple physics experiment.  (refer below)
       The chamber sounds out    Loudly     when speaker reaches it's resonant frequency.

Best Regards,
                        The Observer
       


spoondini

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #96 on: November 05, 2009, 10:53:01 PM »
FYI, I use phos bronze on both the electric and accoustic, both 11 guage.  Shouldn't be a factor.  Haven't had a chance to run the second round yet.  If they're close, then we can assume these 'other' factors could be influencing.  If there's obviously more sustain, then these factors are probably neglible.   I'll let you know by next Tues (next time I break out the sound system).

HeairBear

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #97 on: November 06, 2009, 12:33:46 AM »
Here is a pic of a "Drone Harp" or guitar which utilizes the effects of "Sympathetic Vibrations" to accentuate the tones produced. Although this version is a solid body, there are acoustic versions too. One of the factors that may have been ignored or missed is the shape of the sound hole, or, sometimes F holes. If the resonant cavity has no, or, badly designed sound hole, the resonance will be affected. One of the tricks to tuning electric guitars in not so quiet places(noisy bars), you can put your ear against the solid body and hear the vibrations much more clearly. And some ask, "Why don't you use an electric tuner?" I myself can't stand tuners and hearing the tuning, in my opinion, is far better than trusting an electric device I can't hear.

WilbyInebriated

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #98 on: November 06, 2009, 01:04:24 AM »
FYI, I use phos bronze on both the electric and accoustic, both 11 guage.  Shouldn't be a factor.  Haven't had a chance to run the second round yet.  If they're close, then we can assume these 'other' factors could be influencing.  If there's obviously more sustain, then these factors are probably neglible.   I'll let you know by next Tues (next time I break out the sound system).
"shouldn't be a factor" is an assumption. why not just remove that assumption right from the start instead of opening the test up to more assumptions later on as evidenced by this statement "then we can assume these 'other' factors could be influencing".


The Observer

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #99 on: November 11, 2009, 06:38:27 PM »
Spoondini,

Thanks again for your willingness to experiment.
I have been waiting for your results.

I would like to remind you that an acoustic Guitar's sound is roughly 1000 times as intense as the Electric Guitar's Sound.
 
                                                                    A Ratio of      1000 to 1

If energy is conserved... this means that the electric should ring around 1000 times longer than an acoustic string.

-----------------------------------------------------------------------------------------------------------------------
                                             My acoustic rings around 10 seconds.

             It follows that the electric should ring 1000 X 10 Seconds or 10,000 Seconds.
               
                                     10,000 seconds/60 seconds/min = 167 Minutes

                                            167 Minutes/60 Min/Hour = 2.78 Hours.
------------------------------------------------------------------------------------------------------------------------

I'm going to go out on a limb here and guess the Electric String won't ring that long. (2.78 Hours)

Further, I insist The Sympathetic Vibration from the Acoustic Chamber cannot Stop the String From Ringing.
           (anyone who thinks they can stop something ringing using it's natural frequency is a little Kooky)

      Indeed a feedback loop is created!!!!!

                              Please refer to the Speaker/Tube experiment for simplicities sake.

                   The Volume of Water in the Tube is varied until the resonant frequency is found.
                       At Resonance a Loud Sound is produced... with no extra energy required.

 
                                                                       The Observer


spoondini

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #100 on: November 11, 2009, 11:11:41 PM »
Observer,
    Many apologies but I did not run the experiment last night as I should have.  Not related to your theory but had a pressing issue of practicing with a 'fill in' drummer for a job next week and my mind was preoccupied with getting as much material under our belts as possible.  My equipment is currently at the drummer's house and I won't see it until again until next Tues.  At this time I'm still uncertain as to the results if the test is run with no external amplification and no processing.  I'm pretty certain (99.9%) an electric will not ring for 10,0000 times the duration, but I'm also not sure how you came up with that intensity ratio.  Could you please elaborate?

Also, as previously explained, feedback loops don't generate any additional energy with regard to sound at least.  The amplitude (amplification....) of the waves increase because they stack on top of each other due to bouncing back and forth at multiples of the wavelength.  The same energy is contained in waves not 'feeding back', it's just hitting more times per second.  This is what happens with certain frequencies in a room (depending upon shape) when my band set's up the PA, we have to cut certain 'hot' frequencies which 'sound' louder and on the stage monitors we cut frequencies to eliminate that nasty squealing feedback.  Again no energy created, just fewer bigger waves as opposed to more smaller waves on the non-feeding back frequencies.

However.... I can say that the natural feedback allows us to consume less energy.  As we cut specific frequencies to generate a 'flat' sound, it reduces the overall draw on the poweramps and still 'sounds' equally as loud.

Nabo00o

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #101 on: December 15, 2009, 10:21:46 PM »
Observer and all, I am sorry for not reading through the entire tread, I wanted to at the beginning but its just too much so I jumped to the last posts. So if any similar points have already been brought up and proved/disproved, then again, I'm sorry  :D


Now, this is just in line with what I have tried to understand for so long, steadily finding out that there is much that I didn't know or was wrong about. I had similar discussions with hansvoliven and fritz in regards to explaining the perceived increase in both amplitude and duration of the emitted sound with and without a resonator. In the end it boiled down to impedance matching, which frankly was a topic I was to inexperienced in to respond, so it stayed at that.

Now however, with gained insight from many other similar systems, based on forced oscillation and resonance, I believe I understand how it all connects, and why impedance matching alone cannot explain the phenomena of increased amplitude output from a resonantly driven oscillator.

-----------------------------------------------

So first to impedance matching.
It is crucial in the construction of a system where you want energy to be transferred through several oscillators and eventually to a load. For example in audio, transformers was used to step down the voltage so that the impedance of an eventual speaker would "seem" higher to the original source, thus causing more of the voltage drop to stay over the speaker coils instead of any resistive load elsewhere. Doing the opposite over long range power lines, the impedance of the long thin cables seemed smaller than the final destination, even if both where of the impedance without the transformer.

So this is important if we want to transmit the vibrations of a string to the air around it.
If the want the main resistance or opposition to change to be the air, and not friction or other losses, then it needs to have a larger resistance than anything else in the "circuit".
And, theoretically it can only reach a 100% efficient transfer.

---------------------------------------------------

Other attempted explanations has been that the sound is focused or that some inaudible frequencies are being limited and turned into audible ones. Both of these can be proved wrong in simple experiments where a pure sine wave is used and a very directional cone is pointing away from you.
The results are (and I have tested them) that the sound is still magnified by a very large amount, and that the direction which the cone is pointing doesn't matter the most as to how high the volume is. The equipment used was a small horn, a very small speaker (the ones you can place in the ear) and a computer program which can create sine waves and others at specific frequencies.

============================================

Now in my attempt to explain why this and much better controlled experiments would still show a big gain in the output amplitude, I see it as a completely basic result of the phenomena of resonance.
The implications are gigantic, if we can try to get our heads around the problems and results of resonance.

As a prerequisite in order to understand this better (at least for me), it is useful to investigate the function of the 2-stage oscillator, and the concept it uses. If you have done this, you will come to see that it is in fact exactly the same as an acoustic resonator, only that the vibration frequency is much lower, and instead of air resistance it uses a mechanical load.

Both resonators are exited by a small trigger signal, resulting in a new signal who's amplitude is directly proportional to the Q of the resonator times the input power.
As people working with LC circuits (tanks) know, resistive resistance in the circuit will lower the Q, minimize the oscillating energy and offer no way to exploit the huge increase in amplitude which the tank gives.

Looking at it in the acoustic wave way, the problem is that you are trying to tap the energy from the anti-node. The exactly same problem arises with springs and weights, pendulums, air pressure, and even standing sound waves. And here lies also the key:

You want to tap it at the node, at the point which the wave reflects and cause a standing wave to arise, where the motion is at a minimum, or zero if there truly existed real nodes in oscillators.
The losses you get from tapping it here is of a completely different kind than the ones you have between the nodes.

Consider an attached spring with a weight.
You steadily input energy in the form a push on the weight at the resonant frequency.
In short time the amplitude may be twice or even ten times as high as your input, but, it you then switches the input into an output by placing a physical resistance close to it (a liquid), than you will get exactly the same out as you placed inside. The losses was proportional to the velocity/amplitude and you ended up with nothing.

Now take the same spring and weight, but attach the spring itself to a load, a friction element maybe, for consistent results.      What in the world has happened?

What has happened is that the losses are no longer proportional with the velocity/amplitude, but only to the displacement of the spring.

When work is done in the load, the spring moves, and the weight looses potential energy as a result. This loss is proportional to the distance the spring moves. No matter what amplitude it is running in, the losses stays the same, as long as the distance is the same.
This means that the positive work done on the resistive element is not equal to the negative work done in the oscillator, because the value of force can be whatever we want without effecting the oscillator.

I apologize for the long and maybe untidy writing, I'm not that good at writing concrete and short, but in my view this translates to all other oscillators.


If the energy input is constant, and we vary the node resistance, then the amplitude of the oscillator will be proportional to this resistance. Energy output will then be: E(out) = E(in) * R(node)
And COP would be the same except /E(in) at the end.

See, the Q controls the amplitude and is equal to R(node) - R(anitnode)

So if we want to create as an efficient oscillator as possible, then the resistance at the anti nodes (air resistance, friction and others) needs to be as small as possible, while the resistance at the nodes needs to be as high as possible, and this would be our load.

In a LC tank the load should be either in the magnetic field or in the electric field.
The rotoverter is an example of the former.


Back to the subject, in this case the load would be the air, in which we create sound waves.
A load in the anti-node would have meant that we first vibrated a string, and then used friction directly on the string to load it. I think this is why strings with higher frequencies are faster drained, because they meet a larger resistance against the air than the lower frequencies, like ac versus coils.

Also if we placed something that could absorb sound waves inside the guitar, then we would loose a lot more of the volume, not only because it is absorbed as heat inside, but because we restrict the input energy from creating standing waves, which in turn vibrate the lighter and looser top wood, giving us that extra free source of sound.

Thank you for your attention ;D

Julian
« Last Edit: December 15, 2009, 11:02:12 PM by Nabo00o »

The Observer

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #102 on: February 17, 2012, 10:29:57 PM »





Greetings,


It's been awhile since I posted here.
Long story short, I have only started 2 threads here at OU.com.
Both of which pertain to what I believe are Unrecognized Sources of Energy.

1. one entitled   Magnetic Permeability ... I can't find anyone talking about this !!!!![/color]

My concern here is the fact that a "piece of iron" can magnify the magnetic field of a coil by 5000 times
... without using any extra energy. (iron has a Magnetic Permeabliity of 5000)

2. the other   Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?[/color]

My concern here is Resonance and that 2 tuning forks ring louder and longer than 1 when only 1 is struck.
Or that, an Acoustic Guitar is ~1000 times louder than an Electric Guitar (same strings, same strum)


After posting virtually every day for about  2 years (later in other threads),
 and receiving Flack from both paid posters and a lot of honest members
that just couldn't see what I was talking about.. I stepped down from my soapbox.


I purposefully stopped posting more in my threads as to keep them short and to the point
for anyone who was asking the same questions as me.

--------------------------------------------------------------------------------------------------------------------------

Anyways, the other night I listened to an interview by Kerry Cassidy from Project Camelot.
She interviewed a man named Ralph Ring who has been at this game for quite sometime.
His story is amazing and a lot of what he talked about probably goes farther than most if not all threads here.

What made me jump for joy was his statements about Magnetism and Resonance being sources of Free Energy.
In fact, he said "What they really don't want you talk about is Resonance." !!!!
Hmm, well... if you read just about any one of my posts you might get an idea as to why.


Apparently, they (Ralph's compatriots)  have well organized "pods" of people around the world with free energy devices
ready to be released, when the time is right and heavy suppression from the "bad guys" won't occur.
In fact, he mentioned middle school students will be able to replicate the devices with the proper instructions.
------------------------------------------------------------------------------------------------------------------------------------------

I so advise any Free Energy Researcher to listen to this.
You will be amazed and jumping for joy after listening to Ralph's story.
Here is the link to the archived version of the show ...

http://www.americanfreedomradio.com/archive/Project-Camelot-32k-021512.mp3


Best Regards,
                      The Observer

poynt99

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #103 on: February 18, 2012, 01:26:51 AM »
TO,

Once you are able to obtain some net work from a magnetic field for FREE, having the increased field from a ferromagnetic core will be of some benefit.

.99

SchubertReijiMaigo

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Re: Why is an Acoustic Guitar so much LOUDER than an Electric Guitar?
« Reply #104 on: February 18, 2012, 09:41:47 AM »
@ TO, check out the MRA (Norman Wootan & Joel McClain). The basic goal is to amplify the magnetic field inside the core (like Rotoverter TV) by high Q resonator... The amplified field created by an amplified current, will result in an amplified voltage at secondary by Q times the input voltage... (Working current stay the same...) but voltage not, it come from the amplified reactive current (LC resonance at primary).


When the device is loaded and still OU (by choosing carefully the value of L, C and the load R) and loop it you get paranormal "quantic" effect, like Ali has described in his generator a few day ago, I even warning him that playing with self looped high Q resonator can be dangerous if not mastered...


But since you're a "fan" of resonant things like me, I guess you should test it also.
The Magnetic Resonance Amplifier is basically a LC in series or in parallel (L is the primary of a transformer...) in a high Q mode (high L/C and low R )...


Measurement will be simpler, to avoid error: rectified DC with True RMS multimeter will make a good job, one measure at the DC side before the inverter, and after the rectified output of the transformer, if the device is OU looping with buffer cap and a regulator will be easy...


I understand better why you make post like this: "Magnetic field can be amplified 5000 times freely"
Yeah but for producing energy and OU we must:
1) Create a resonant condition...
2) Extract the amplified energy without totally reflecting to the source...
3) For me I see only two method:
a) At C value (Transverter diode plug system)...
b) At L value (Through a transformer, like the MRA)...




Regards, SRM.