Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Magnetic Permeability ... I can't find anyone talking about this !!!!!  (Read 70166 times)

The Observer

  • Sr. Member
  • ****
  • Posts: 397
Xee Man,

Sorry that the chronology of this response is a little out of whack.
I have been trying to address, understand and respond to every sentence of each comment.

                               Yes... Yes Yes    Yes           Yes.

A solenoid with a ferromagnetic core is in fact an electromagnet ( or at least can be called that ).                                                                                                                                                                                       

Yes, Yes...  I think you understand where the extra energy comes from.

Coil + Core... where the core always had energy.. nill when not organized... large when organized.

Now to produce electron movement in a second coil wrapped around the first... the field needs to change.
This is where a pulsed or AC current applied to the first coil comes in.

As I have mentioned, a resonant frequency of the atom dipoles could be a wise choice since motion is accumulative in this situation.

                                     None-the-less, I am happy that you can see what I am talking about.

I admit that I don't quite understand your comment about using a permanent magnet.
Wait, I get it.

You just stated the reason a permanent magnet is used in a loudspeaker !
It would be ridiculous to consume the energy of 2 pure coils to run the thing when you can use Mother Nature to help you out.

The permanent magnet in a speaker would consume an ENORMOUS amount of energy if it were just a coil.
And the coil that moves the whole thing is really a coil assisted by ferro core...so a pure coil here would also consume more energy than if it were just a coil.

This technically makes a Loud Speaker an overunity device since WAY more energy is required to run the thing without the magnet and the ferro core.

Just had an idea... I have a project for the naysayers.

    1. Calculate the energy needed to produce a magnetic field in a pure coil comparable with the magnet in any speaker you pick.
    2. Calculate the energy needed to produce a magnetic field in a pure coil comparable to the electromagnet in said speaker for any signal.
    3. Calculate how much energy is actually needed to just power the electromagnet of said signal ( the operandi mode of a typical loud speaker) to produce   
        same volume or decibel level as 2.
    4. Add 1 and 2 then compare that sum to 3.
    5. Explain why these are different.... if your calculations do not reveal an the equilibrium situation.

Just remember... to conserve energy in the classical agendized way... 3 CANNOT be less than the Sum of 1 and 2.
       They have to be equal or energy needs to appear to be lost for classical conservation of energy to make sense.

Well, perhaps you can see that this obviously is not the case.

The amount of energy it takes to run a loudspeaker is 1 + 2. Period. End of Story.
You need a strong changing magnetic field to to make the cone vibrate, there is 'no free lunch' as you like to say.
Since 3 is less than then a sum of 1 + 2 you better be damned sure the energy is coming from somewhere, and it does.

However, I am getting weary of saying where it comes from... so I will not repeat... it's late.

Optimism never hurts.
   
                                The Observer



The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hey Otto,

Still haven't checked out what you mentioned about the SM thread.

Busy today... but I will check it out.

Stay cool,
         
               The Observer

The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hey Xee,

I investigated the question having to do with the amount of force and time it takes for the dipoles to spin.

Turns out there is a characteristic number called COERCIVE FORCE that applies to ferro materials.
This is exactly what you were wondering  about... as was I.

My Physics Book had a pretty good chapter on this.

                      I have to get to work... so I will elaborate on this later.

But in a few words,

There is a huge range of this 'stickyness' of dipoles depending on the material. (Corecive Force)
Some stick alot... and some spin about as freely as you want.
A hysteresis diagram can show the entire loop which makes it obvious what is going on.

Something like soft iron doesn't need much to saturate, other materials need more (like magnets)...and some (like metallic glass) Way way less !!!

Also as you know. ferro materials have the domains where every dipole  is lined up, which is not explained by Newtonian Physics.
This can only be explained using Quantum Physics apparently.

Well, gotta get going.

Be well,
           The Observer

Charlie_V

  • Sr. Member
  • ****
  • Posts: 362
@The Observer

You are correct that there is an amplification between a coil without a core and one with a ferrous core.  I'm surprised why no one has addressed the real reason why your idea will not work easily. 

The current flowing in the first coil will produce a magnetic field.  This magnetic field will be amplified (intensified) by the iron core.  This will produce a larger voltage in the secondary coil (assuming that the turns ratios are the same - but this is not important since they could be different and the effect is the same).  The MAIN problem, is that when you apply a load to the second coil, current in the second coil will flow in such a way to CANCEL the current flowing in the first coil. 

This cancellation causes the power in the second coil to be equal to the power in the first coil.  The same thing happens in generators and motors (thankfully it happens in motors, otherwise they would spin so fast they would fly apart!)  On the flip side, IF this cancellation effect could be neutralized, then you would get the sought-for energy amplification in the second coil. 

The cancellation effect I'm speaking of is named after Hendrik Lorentz, who mathematically described it in the 1890s.  I've spent a great deal of time studying this effect.  People commonly use the Lorentz force - which is what the effect is called - to claim there are "no free lunches."  However, they are not entirely correct.  The Lorentz force is NOT the same as friction (I associate friction as the "no free lunch" force).  Lorentz is a completely different phenomenon and not well understood.  Yes there is a classic formula to represent it, but the true explanation (i.e. why does it happen) is not apparent nor explained.

The reason I attribute it to being different from friction is that friction takes energy from the system.  The Lorentz force balances energy.  There is a huge difference between taking and balancing.  Once something is taken, its gone! Where as in a balanced system, nothing is taken away, everything just stays equal.  Unfortunately, we have been working with balanced generators/motors/transformers for so long, we have come to lump this strange force with "losses".  No one can tell their apples from hemorrhoids anymore :-\

Now, most things that are balanced can be unbalanced.  I feel the same thing can happen for Lorentz.  I built a testing apparatus that I'm still taking measurements on.  The results, so far, are promising.  It has gotten further in testing than any of my other designs - fingers crossed!!

ADD:  Here is a picture of Hendrik Lorentz.  If you look closely at the chalk board behind him, you will see a list of all the good boys and girls - which I'm sure he's checked twice.  I believe the reindeer and sleigh are parked out front...

The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hello Charlie,

       I appreciate your interest in Magnetic Permeability and your invention, what-ever it may be.

Alright, I looked long and hard at the reason you say my machine, as I have described it, would not work.

     (In short, a transformer possessing a ferromagnetic core that uses resonant frequencies to achieve more energy out than energy in
      using the total organizable electric current of ferromagnetic atoms that results in a switchable and magnified magnetic field
      and the properties of forced resonance which results in increasing the magnitude of motion of the ferromagnetic atoms.)

I do have a hard time with the CANCEL out thing.
I am very suspicious that a transformer takes more energy out of a primary whether a load is on it or not.

  I had to learn more about transformers... and a few things just don't make sense.

                               http://en.wikipedia.org/wiki/Transformer

1.  Since the efficiency of a transformer is hard to calculate... ? ? (VI = P in vs. VI = P out) THEY instead refer to the
     hysterisis loop of the core & loss in copper windings to get an effieciency #.   Which happens to be around 99 %.
     A pretty damn impressive # in and of itself.

     But it is Very, Very Misleading...
              That is, one would assume the efficiency has to to with the ratio of power in vs. power out..
                This is the very thing we, at overunity.com, are concerned about by definition.
                   Yet THEY quote the efficiency of the device that I claim ADDS ENERGY to the situation + the resistance of copper windings (give me a break).
                       That device being the ferromagnetic material used in the core.
                            Hmm, Hmm, Hmm.

              Why in God's name would they do this?

     Perhaps, just perhaps... the energy required to run a transformer is equal to what 2 coils would be?
     Adding a piece of metal to the equation cannot add energy under conservation laws.
        and.. YET IT DOES.     Conundrum.

I conjecture this is one of the reasons a misleading number is quoted...that conservation laws would then be violated .(whoo whoo and flashing lights)

Another reason has to with frequency which I will get to later. (perhaps in another comment, as I need to investigate this phenomenon a bit more)
        Suffice it to say that Voltage increases in the secondary as Frequency increases in the primary.

2. Then is mentioned (in the wiki article on transformers) that V in = V out... I in = I out... therefore P in = P out. Where IN is the primary and OUT is the     
    secondary.  V is Voltage, I is Current and P is Power.     P=IV    or     PIV as I like to say.

    Not only that, but a resistance R on the secondary side will produce a resistance R*(ratio of windings) on primary side (and vise versa, reciprocate ratio.)

     Fine, if these are the "rules" lets break it down for a "transformer" with equal windings on the primary and secondary.
          This means that R is going to be the same on both sides. That's what THEY say..

But first this...

I remember a question on a physics test in College.  I was one of the only ones in class to get it right.  It's a simple question.

                        What household appliance has greater resistance, an electric stove or digital alarm clock?

                                                  Answer...  Digital Alarm Clock

The reason is  V=IR.  The current needed to power a clock is way less than needed to power the stove.
Therefore, according to ohms law, the resistance of the clock is way more than the resistance of the stove.

       This is not an intuitive answer because resistance implies energy used.
       Resistance takes energy (swimming against the current)... going with the flow does not (swimming with the current).

Anyways as R goes up, I goes down in a circuit for any given Voltage.   V = I *R
  To be more clear... the higher the resistance... the less the current.

      As that dude Archer would say... Do we agree with this?   lol
         Yes or No.

Now Power... what needs to to be compared, is P = I * V     PIV      as aformentioned.

So now we would agree... that when voltage is constant.. more Current equals more Power...less Current equals less Power?
     Yes or No ?

Finally, there is the aforementioned coils (of exact equal dimensions)  sitting next to each other.
          The secondary is not  hooked up to anything.. this means 0 electrons are flowing which means the I = 0..
           The primary is hooked up to ... lets say   110 AC Volt at a frequency of 60 Hz.
         
          Because  P (primary) = P (secondary)   this means that    VI (primary) = VI ( secondary)

Do we agree ...Yes or No?

    If you have agreed to this, you have also agreed that NO POWER is being consumed in the primary of a transformer
            when the secondary is not hooked up to anything  !

    That is, P of the Secondary has to be 0 since no electrons are flowing, therefore P of the Primary must be 0.
                                         P=IV   No electrons moving, no power.

    In other words, THE LAW that states all must be equal and no energy extra energy can come from unrecognized sources,
                                                      then postulates that NO CURRENT will flow in the primary.

I DISAGREE.

Ever heard of a wall vampire? 
It's the black square transformer used to transfer 120 V AC to smaller DC voltages which are used by cell phones and a jillion other things.

According to LAW, these devices should use NO POWER when not hooked up...  YET THEY DO.

   There are People Laws now about building a circuit in transformers to detect if the secondary is loaded, so that current is only used when it is hooked up 
   to something. Apparently, MANY watts of power are wasted each year due to the fact that Transformers DO NOT consume less power when the secondary is
   not loaded or bear a very high resistance.
 
This is a direct contradiction to P(of primary) equals P(of secondary).

I say, simply...that the secondary of a transformer is a reciever.  No different than a radio reciever.
There is simply no way for a radio transmitter to have any idea how many radios are tuning in (interestingly enough... with resonant tuned circuits).

The truth is, the primary of a transformer always consumes the same power no matter what is hooked up to the secondary.

I realize this statement flies in the face of many people, laws and agendas...
                                                                                                             however I am an Observer not influenced by others, always thinking for myself.

So, perhaps I have overlooked something, but I have not accepted what someone else said on the surface.
                                                       For that I am satisfied.

Please think about this and the loudspeaker example mentioned previously.
Ferromagnetic materials (including magnets) have energy that can be tapped into, and are everyday.
It just isn't recognized as such.

May you perceive that which is true,
                                                    The Observer

Charlie_V

  • Sr. Member
  • ****
  • Posts: 362
Hey Observer, you bring up some good points.

Quote
Then is mentioned (in the wiki article on transformers) that V in = V out... I in = I out... therefore P in = P out. Where IN is the primary and OUT is the     
    secondary.  V is Voltage, I is Current and P is Power.     P=IV    or     PIV as I like to say.

Wiki is not so correct about this.  The power in equals the power out but the voltages and currents do not have to equal each other.  Vin can be way larger than V-out, I-in can be way lower than I-out.  But they are ratioed with each other.  So whatever  V-in or I-in are, V-out can be equal, larger, or smaller.  In the case that V-out is smaller, I-out will be able to be larger than I-in.  If V-out is larger, then I-out will be smaller than I-in.  It works just like mechanical gears. 

Now the reason they say that the primary does not consume any energy is because typically the inductance is very large.  So the power factor of the primary circuit is close to zero - meaning the power in the primary is mostly reactive power.  There is still resistance losses in the primary (plus things are never ideal and the power factor is probably greater than zero, meaning there is some real power consumption).  When you apply the secondary, the secondary should have its impedance matched with the primary winding.  This allows real power to transfer to the secondary (the turns ratios between primary and secondary can scale the voltage/current - but typically not the power). 

The efficiency of a transformer is Pin/Pout.  In the case of your test question, a stove generates heat through resistance.  However, you want current to flow so you will make sure the resistance is lower so more current flows.  The heating elements will then be made of a metal (and a size) that is not rated for the amount of current flowing in them.  Clocks have a high resistance too, but usually have inverters inside to step the voltage down to probably ~12V or so.  So, 12V divided by a large resistance is much lower current than 120V divided by a resistance.  I would imagine a stove has a fairly low resistance compared to a clock - since you want more current to flow in the heating elements.  I've never measured either of them so I wouldn't know.

You are correct that a transformer is just like a radio receiver.  Also, I didn't say your idea would not work, I said it wouldn't work easily, I believe back torque can be overcome - I'm still working on that though.  And I agree that they do not explain the way metals tend to amplify the magnetic field without any input energy - the energy required to align the poles is usually very very little - depending on the material of course. 


The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hey Charlie,

Actually I owe you an apology in that, I may have insinuated that you said my idea (or something like it could not work).
   Indeed you said 'work easily'.  Thank You.
     I think you can see what I am talking about... and greatly appreciate your input.
       I am surprised  more haven't jumped in on this.         

It is nice to get feedback, because that causes new questions that need to be correctly answered.
   Something I apparently find... fun.

Now you said,          '"It works just like mechanical gears."

As in     Pin = Pout   and I and V match up when all is said in done to make       P=IV  (primary)   =    P=IV  (secondary).

I know, this is what is accepted.
  In fact my College Physics book says that everything I say that I am wrong.
   Well, not quite, there are holes in their assertion, but anyways...
     That is, they say .....Pin always ='s Pout,
        where I am saying,   "I'm not so sure about that !"

Here is what I say.
   
       You (not you Charlie, the misinformed) are comparing apples to oranges.

Gears are a Newtonian device ... a transformer is a Quantum Mechanical device.
  The rules are so different that old Lorentz's head would spin just looking at all the free lunches.
   
It is very useful, in understanding quantum physics to observe a stone that is thrown in a pond.

  There is plenty I know I'm not seeing, but this is what I do see.

    1) The wave created by the stone goes out in all directions.

    2) The wave created by the stone has a constant speed.

    3) The wave created by the stone makes a leaf on the water bounce up and down when it passes by.

    4) The wave created by the stone can make many leaves bounce up and down.

    5) Because of the finite and constant speed of the wave in water, when the wave passes a fixed object (say a stick in the mud),
        The resultant wave from this interference can never interfere with any other portion of the original wave.

     6) Oh, wait a minute... here comes a water bug, Let's call the bug Charlie.
         Charlie's top speed seems to be the same as the wave of water's speed.

     7) Charlie must have seen something, because he suddenly scurried across the water !
         Charlie's movement created a wave.  And Charlie was always the the for front of the wave produced.

     8) When Charlie stopped, so did the creation of the wave produced by Charlie's movement.

     9) A new bug with same top speed arrives on the scene wearing sunglasses and a straw cowboy hat, named Chuck.

    10) Charlie suddenly decides to scamper over to the shore that is a long ways away. (Chuck looks a little strange)
          This produces a wave.

     11) Chuck who was standing near by (look'in cool), finds out that Charlie left when he felt that wave. (these bugs are blind)
           The wake of Charlie's wave let Chuck know that something happened.

      12) After Chuck recieves this information, Chuck decides that Charlie must be Stopped ! from reaching the shore.
           Chuck likes Charlie and just wants a hug.

           Alternately, Chuck is so cool, he doesn't even flinch at this new information, and just rides the wave like the leaves.

       13) Chuck chases... "Must stop Charlie, Charlie cannot get to shore. Must conserve energy."

       14) Do I have to tell you who loses the race?

When something else moves... it is a result of a previous action.
   Sure it has an action (movement), but there is no equal and opposite reaction.
      What happened, happened. 
         An equal and opposite reaction would have to reach beyond the bounds of time and space to achieve this.
            Because of the nature of the medium in which it exists,
               Nothing can really catch up with anything else.

As far a transformer goes, I hope you can see the analogy.
That is, what is forced in first coil, is just absorbed by the other.
The best way for the coil to conserve energy is to just bounce like a leaf in the pond, that's it.

I am pretty sure, but don't quote me yet.
    That the back emf has to with the energy of all the dipoles turning back to their original position from the ferromagnetic material of the core.
       This energy of course doesn't have to be a bad thing.
         In fact, is probably an important factor in finding resonance in a the circuit I am talking about.

Thanks for reading.
There will probably be more as my exploration continues.
Any comments, thoughts, or even a thought experiment that continues the one I started with the pond, would be much appreciated.

      And with that, I wave goodbye,    ~~~~~~~~~~~~
                                                               The Observer
                                                             ~~~~~~~~~~~~





fritz

  • Sr. Member
  • ****
  • Posts: 424
Transformers:

Lets design a transformer.
A transformer is typically designed for its payload.
That means that the flux generated from the primary
coil is compensated by the flux from the secondary -
which gives an overall low flux compared to saturation
densities. N*I1 = N*I2.
If you don?t take the rated payload - the flux in the core
as well as the losses go up.
This means that a transformer has the worst efficiency
without load (gets warm) because of too much flux.
You can design a transformer for low losses without load -
then you need more iron.
You can even make a transformer with very less iron and big
coils - but this restricts your load range.
Another thing are the losses an resistance of the coil ....
....
Build one or think about it. There is no "transformer".
Every transformer is optimized for something.
A pulse transformer is something different than
a mains transformer - and a mains filter ....

The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hello Fritz,

Thanks for your input.

I guess I have a hard time with the word compensated.

I really, really believe that the electrons in the secondary move only as a result of the wave or waves that pass by.
I don't believe they have any momentum, that allows them to create their own magnetic wave in the coil.
When the wave stops, so do the electrons in the secondary.
The wave is what makes them move, the absence of a wave means the absence of movement in the secondary.

Perhaps down line in closed circuit secondary, away from the primary's magnetic field, a new wave can be produced.
   But, I really don't see how a  new wave is created at the secondary to counter act the primary.
      ESPECIALLY when nothing is connected to the secondary.
         How could No Electrons Moving create a field to get back at the primary?

What is being said...(not me) is that...

A current will not run through the primary when there is nothing loaded on the secondary.
Yes, I know they say there will be a little leak do to imperfections.

     Gee Wizz... what would happen if I put in a Thirdary, Fourthary, or even  10aries in the vicinity of the primary.

I guess they would all be communicating with each other to make sure Laws that have to do with Conservation of Energy are being upheld.
   This means that a radio transmitter emits no power if no-one is tuned in.
      This means that the radio transmitter could also determine how many are tuned in (with resonant circuits) at any given moment, since
        it's power would be in direct relation to the power being used by the coils in the radios.

          This is Bull Hockey. (that is a bull on ice doesn't stand up very well does he?)

Here is a real question.

     What really happens when I short circuit the secondary of a transformer?

         Let's say the secondary's circuit is made of some really hearty material that won't melt. (like the electric stove)

  Will this blow the AC Circuit breaker in the house or melt the primary ?


I realize there is a lot of theory here, and not much for experiments.
 I have taken apart a couple transformers (not an easy task), but I guess I would need to make my own from parts
  and acquire a VARIAC (I think) to produce a variety of voltages as well as frequencies.

Well, this is not over for me.
  Any input is greatly appreciated.

Have a Glorious Day !
                                The Observer

     
   
     




Charlie_V

  • Sr. Member
  • ****
  • Posts: 362
Quote
That is, they say .....Pin always ='s Pout,
        where I am saying,   "I'm not so sure about that !"

Yea I agree with you, science in general talks like they know everything - very arrogant if you ask me.

Quote
Gears are a Newtonian device ... a transformer is a Quantum Mechanical device.

Yes, gears and transformers are completely different.  A gear does not suffer from an effect like back EMF/Torque.  A gear only has resistive losses.  Really, I've tried to think of a mechanical analogy to Back EMF and there is none - this sets electrical phenomenon on a completely different playing field.

Quote
I am pretty sure, but don't quote me yet.
    That the back emf has to with the energy of all the dipoles turning back to their original position from the ferromagnetic material of the core.
       This energy of course doesn't have to be a bad thing.
         In fact, is probably an important factor in finding resonance in a the circuit I am talking about.

I have no idea what back EMF really is and why it happens.  It could be related to the ferromagnetic core but I'm not so sure since you get back EMF in air cores too.  I don't think back EMF is a bad thing, I think it is necessary - I just don't know why haha.

Quote
But, I really don't see how a  new wave is created at the secondary to counter act the primary.
      ESPECIALLY when nothing is connected to the secondary.
         How could No Electrons Moving create a field to get back at the primary?

The counter acting wave only occurs when the secondary is loaded.  If the secondary is open, there is no counter acting magnetic field.  You get a voltage.  When the coil is loaded (a short being the highest load it could see), electrons flow in a direction to create a magnetic field that opposes the applied field.  IF your applied field (being a magnet of another coil) is directly coupled, the counter field will fight the movement.

So, if you want to stop them from fighting, you need to find a way that the coil sees a changing magnetic field, but the field it creates is in a position that it can't fight the applied field. 

Quote
This means that a radio transmitter emits no power if no-one is tuned in.
      This means that the radio transmitter could also determine how many are tuned in (with resonant circuits) at any given moment, since
        it's power would be in direct relation to the power being used by the coils in the radios.

Radio transmitters "radiate" their power away - their load is the surroundings.  They cannot see nor do they care about the receivers.  They put out X amount of power in all directions.  The receivers collect a small fraction of that, depending on how far away they are.  If you could cover 360 degrees of a transmitter with receivers, you could collect that X power divided by the number of receivers, in each receiver.

Now a Magnifying Transmitter (aka a Tesla coil - made the way Tesla intended) WILL see the receivers.  Thats because a Tesla coil channels the energy directly to the receivers, it does not radiate the energy in all directions into space.  SO the Tesla coil is only loaded when a receiver is on.  The more receivers, the more load on the Tesla coil.  A radio antenna is 99.9% loaded all the time, and whatever the receiver collects is a small fraction. 

A radio antenna is like a water sprinkler spraying water in all directions, the receivers are like cups.  You can place a cup some distance from the spraying sprinkler, you will fill the cup up with a very small amount of water.  The closer to the sprinkler, the more water it will fill.  A Magnifying transmitter shoots a stream of water directly into your cup no matter the distance.  However, the more cups there are, the more streams the MT makes and the less water is available for each cup. 

The Observer

  • Sr. Member
  • ****
  • Posts: 397
Hello Charlie,

Thanks for your input.

I will consider your response at work today.

Be Well,
            The Observer

fritz

  • Sr. Member
  • ****
  • Posts: 424
Back EMF (electro magnetic force)
is quite easy explained and simple.

Mechanics:
Accelerate a flywheel with a slipping belt and a dc
motor. On turning on the belt will slip, but finally the
flywheel will reach the motor speed. Now the flywheel
is "charged" with rotational energy @ x .rpm.
If you decrease now the dc voltage which powers the
motor - the motor will (wants to) spin slower. Because the flywheel
is turning now faster than the motor - you will get
a pull instead of a push what concerns the belt.
The energy in the flywheel is now consumed by the motor
which wants to turn slower - now the motor turns into a generator
which wants to get rid of the extra energy from the flywheel - by
charging the battery (current reverses).
Well, every motor has a mass and is a flywheel. thats it.

Thats Back EMF, quite simple.

Or accelerate a car - if you release the gas pedal it doesn?t
stand sill instantly, no it slows down - consuming its inerta
versus friction.

Or if you start to run - and want to stop with one step -doesnt
work, you have to destroy the kinetic energy which is stored in
your accelerated body.

Charlie_V

  • Sr. Member
  • ****
  • Posts: 362
If I understood you, you are saying that back-EMF's mechanical equivalent is inertia?  I have to think about this some. 

fritz

  • Sr. Member
  • ****
  • Posts: 424
Ok, lets say you have a traditional dc motor with
high mass spinning at 500 rpm (because u supplied
a voltage x before which causes this speed).
Then you change the voltage (jump) to a value which
would finally ends up in 700rpm.
The motor takes now the same current - as if you
want to accelerate from 0 - 200rpm..
Why ?
The voltage "seen" by the motor - is the input dc voltage
minus the "inner voltage" == back EMF.
The current taken is always (
(outer voltage-inner voltage)/(inner coil resistance).
If outer voltage is lower current reverses.

There are lots of OU setups which somehow tweak around
with inner voltage, resonance and whatever claiming somehow
that in the inner voltage of the motor (in phases with no supply
current) powers back something) - here it gets difficult -

Back EMF itself is very simple.

Charlie_V

  • Sr. Member
  • ****
  • Posts: 362
Your not explaining what back EMF is, just how it works.  I know how it works and yes it is simple.  Very simple, when there is a change in magnetic field through a coil, the coil sets up a voltage.  The polarity of the voltage is such that if current is allowed to flow through a load, the flowing current creates a magnetic field that opposes the initial change. 

This change is geometrically dependent (unlike inertia which is independent - the mass of a weight will fight movement no matter which direction the change comes from).  Back-EMF only fights change that is perpendicular to the cross-sectional area of the coil. 

Back EMF is similar to inertia (or mass we should say since inertia is a mass phenomenon of rotating objects).  Like the mass of a physical object, it does fight change.

I know how the back-EMF(back-Torque - which I equate to the same thing) works but I want to know why.  I feel it is a balancing force, not necessarily a loss.  I THINK its purpose is to balance the energy in the system.  If you can unbalance it, then you might be able to collect or create energy.  It would be the same if you could manipulate the inertia of a rotating object.  Make it such that the force applying the rotation was not effected by the inertia of the object but the inertia of the object was present.  Thus, the mass would gain a momentum but the inertia would not fight the driving force.

The only difference is that I don't see a way of doing this with a physical object, but with a magnet and coil it might be a possibility.