Check out our Youtube channel for the latest Playlists and updates:https://www.youtube.com/user/overunitydotcom/playlists?view=1&flow=grid

Yes, Stefanof course, you are right, So your original proposal was not far off anyhow.But since the experimenters collect their gas generally through bubblers and measure volume, I would say my formula is more straight forward to use for calculating efficiency.

Another item; I get warnings from my security software of "spyware" when I open your website, and it states "ads.adbrite.com/adserver/....."Anything to warry about ?regards?ystein

I've been playing around with water electrolysis for quite a while now. A question: does your formula also apply for distilled water splitted in H2 and O2? Because HHO is a little different from H2O.If so, then what about the following figures. To produce 10 cm3 of H2 and app. 5 cm3 O2 I need 2 volts and ,31 A during 300 seconds. And these are probably conservative numbers, because my measuring equipment is not the best there is. So the energy input is:2V x ,31A x 300 secs/3600 secsI know this is a slow process, but I got these values over and over again, although I ran into problems using the same water over and over again. It seems to me the characteristics of water are changing.As power source I use a Philips PE 1512 Lab power supply and a common available electrolyzer. But I have great difficulty in accepting this to be overunity.Kind regards

So the question I have is how many watts is required to run a typical car?What about an SUV?If we uses Miles per Gallon to figure for cars, how many Watts per Gallon is Water?Let's assume that it takes 12 Volts times .5 Amps to produce 1 liter of Hydrogen within 60 seconds...Is that enough Hydrogen to run a car? What about an SUV?It sure would be great to have a spreadsheet that did all of this calculations for us.That way we could figure out that once we reach X number of liters of hydrogen per second, we have a usable system that will produce enough energy to run a car.Anybody want to tackle this? (it's a little out of reach of my math skills)FB