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Author Topic: Rotationnal attraction  (Read 2820 times)

Offline EOW

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Rotationnal attraction
« on: December 28, 2017, 12:25:17 PM »
Compare these 2 devices. In these 2 example I lost the same energy from the walls (left and right). I win the same from the green line. I win the same from the springs. No energy gave/needed to rotate the white shape. But there the right shift of the blue spheres are not the same.

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Rotationnal attraction
« on: December 28, 2017, 12:25:17 PM »

Offline EOW

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Re: Rotationnal attraction
« Reply #1 on: December 30, 2017, 08:03:27 AM »
I corrected small details. There is a right movement of the blue spheres (relatively from the left wall), this gives an energy, look at the barycenter. This device is overunity efficiency.

Offline EOW

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Re: Rotationnal attraction
« Reply #2 on: January 03, 2018, 08:27:38 PM »
The white shape have the orientation than the left (or right) wall. There is a right shift relatively to the left wall for the blue spheres.

Offline EOW

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Re: Rotationnal attraction
« Reply #3 on: January 04, 2018, 05:07:25 PM »
another angle

Offline EOW

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Re: Rotationnal attraction
« Reply #4 on: February 16, 2018, 09:40:41 PM »
gif doesn't work on that forum

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Re: Rotationnal attraction
« Reply #4 on: February 16, 2018, 09:40:41 PM »
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Offline EOW

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Re: Rotationnal attraction
« Reply #5 on: February 27, 2018, 11:47:31 PM »
No mass, no friction, no external gravity.
All volumes are constant.
I deform a device and I count all energies in/out.
I use small blue spheres like molecules of water, but no mass and no friction.
I attract the blue spheres from the green line.

Offline EOW

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Re: Rotationnal attraction
« Reply #6 on: February 28, 2018, 04:18:27 PM »
I change the axis of rotation of the magenta arm.

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Re: Rotationnal attraction
« Reply #6 on: February 28, 2018, 04:18:27 PM »
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Offline EOW

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Re: Rotationnal attraction
« Reply #7 on: March 08, 2018, 08:41:16 PM »
If I put white spheres (very small) at 74% and the rest of the device is the blue spheres, then the pressure on the walls is the same, so the energy from the rotation of the lateral walls is 0. But the springs lost -0.207 * 26 % of the device and the green line win 0.414*26 % of the device.

It is a theoretical device, just to break the law of conservation of the energy

To simplify the calculations:

No gravity
No mass
No friction
All volumes are constant
It is not a cycle ! I count all the energies in/out from the start to the end
The device is unstable, I need an external device to control it, but that device count all the energies in/out
The force of the springs is constant, doesn't depend of the length of the springs
The radius of the blue spheres is 1e-100 m
The radius of the white spheres is 1e-20 m
Surface of the device = 1 m²
Force of the springs = 1 N/m²


It works because the volume of the blue spheres doesn't depend of the radius of the blue or white spheres.

Offline EOW

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Re: Rotationnal attraction
« Reply #8 on: March 12, 2018, 08:06:38 PM »
I compare the same device with a modification.

First image: the device at start
Second image: explain how the blue spheres move
Third image: Another angle to watch where the part of the B1 goes
4° image: first solution, the new part is attached on the same Bx (with x number 1 to 4)
5° image: second solution, the new part is attached for the next Bx except for the last

First solution: the sum of torques and the rotation give a positive work
Second solution: the sum of torques and the rotation give a negative work

All the rest is the same.

Offline Floor

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Re: Rotationnal attraction
« Reply #9 on: March 12, 2018, 09:01:44 PM »
@EOW

I have looked at your diagrams twice. 

Nice drawings, but still I don't understand the motions and forces they are supposed to describe.

Perhaps if you will write detailed descriptions in your native tongue, and then translate and post them
we will under stand your principles illustrated.

          Best wishes
            floor



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Re: Rotationnal attraction
« Reply #9 on: March 12, 2018, 09:01:44 PM »
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Offline EOW

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Re: Rotationnal attraction
« Reply #10 on: March 12, 2018, 09:18:34 PM »
@Floor: ok, I try to explain:

I need to use an attraction like gravity can do but I want to change the orientation of that attraction in the same time I deformed the device. For that, I imagined a theoretical device, I replace the gravity by a lot of springs (ok, difficult to build in practice, but my goal is to break the law of conservation of the energy), the springs have the same force: the force doesn't depend of the length of the springs like that the calculation is easier. I replace the molecules of water by little spheres (a lot sure) and I attract each sphere with a spring from the green line. The blue color is the spheres (like water). At start, the orientation is 45° (relatively to the horizontal) and at final it is at 90°. I drew a red line to symbolized the orientation of the springs. I create a pressure like gravity can do with water in a container, but I have no mass (I don't need and it is easier to calculate), and the potential energy of gravity is replaced by springs. And an empty object like a white rectangle has on it a buoyancy force, exactly like a bubble of air in water on Earth.

Do you understand where come from the forces ? I added an example with the values of the pressure at the corners of the device if the force of attraction of the springs is 1N/m² (or  m³ if you think in 3 dimensions).

It is not a cycle, just a deformation of a device from 45° to 90°.

« Last Edit: March 13, 2018, 09:09:14 AM by EOW »

Offline EOW

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Re: Rotationnal attraction
« Reply #11 on: March 21, 2018, 10:19:47 AM »
I win the energy from the torque on the triangle and the rotation of the black arm. Something on the dot 'b' cancel the moment of the triangle, so the black arm receives a torque.
« Last Edit: March 21, 2018, 07:43:40 PM by EOW »

Offline EOW

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Re: Rotationnal attraction
« Reply #12 on: April 01, 2018, 08:32:15 PM »
I move out the white parts and move in the blue spheres.

Online Low-Q

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Re: Rotationnal attraction
« Reply #13 on: April 09, 2018, 08:25:12 AM »
I assume that the spheres is located in a magnetic area, and that the long white rectangles are magnets.
If they are, there is a huge friction between the small spheres, so I would suggest using magnetic oil instead.


Br. Vidar

Offline EOW

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Re: Rotationnal attraction
« Reply #14 on: April 10, 2018, 09:29:49 PM »
Hi Vidar,

It is a pure mechanical device, no magnetism, no gravity. Theoretical, so I don't have friction, it is just to break the law of conservation of the energy, but after, you're right, it is possible to think with magnetism.

I looked for break the law of conservation at least in theory.

My last idea to replace white parts with blue spheres is very good, because the springs lost less than the green line will win.

But do you understood how the device works ?

Regards

Free Energy | searching for free energy and discussing free energy

Re: Rotationnal attraction
« Reply #14 on: April 10, 2018, 09:29:49 PM »

 

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