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Author Topic: Who would you like to witness a self-runner?  (Read 1975 times)

Offline Paul-R

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Re: Who would you like to witness a self-runner?
« Reply #15 on: November 02, 2017, 05:27:52 PM »
I would suggest Patrick Kelly, but there are so many wild goose chases that I would be reluctant to suggest it to him.

What is the prime purpose of this demonstration?

If it is to gain venture capital, then maybe they will follow up this event with one in London.

Free Energy | searching for free energy and discussing free energy

Re: Who would you like to witness a self-runner?
« Reply #15 on: November 02, 2017, 05:27:52 PM »

Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #16 on: November 02, 2017, 05:34:36 PM »
Thanks, but never mind about the request because I was trying to rush the process. Humanity isn't ready, yet. I'll be back when it's time, about 3 years, but apparently I'm to release it in person to be by hand. Either a piece of paper or small disk that contains all the details. :)


Offline Paul-R

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Re: Who would you like to witness a self-runner?
« Reply #17 on: November 03, 2017, 04:45:23 PM »
Humanity isn't ready, yet. I'll be back when it's time, about 3 years
If humanity isn't ready now, it won't be any more ready in 3 years.

My guess is that it doesn't work dependably.

Offline blueplanet

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Re: Who would you like to witness a self-runner?
« Reply #18 on: November 03, 2017, 06:21:21 PM »
If humanity isn't ready now, it won't be any more ready in 3 years.

My guess is that it doesn't work dependably.

I have to agree with you.

In the air-core of his/her circuit, the inductive current of the space source B2 reaches 2A and the voltage reaches 0.9KV. This means the power of the so-called vortex is in the order of kilowatts. This so-called "air-core" looks like an artificial power source rather than any natural occurring source. Unless the inventor can shed more light on it, this power is simply not realistic.

With so much power, we don't need such a complicated circuit to detect it.

(Disclaimer: I am an academic. )




Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #19 on: November 03, 2017, 08:12:41 PM »
I have to agree with you.

In the air-core of his/her circuit, the inductive current of the space source B2 reaches 2A and the voltage reaches 0.9KV. This means the power of the so-called vortex is in the order of kilowatts. This so-called "air-core" looks like an artificial power source rather than any natural occurring source. Unless the inventor can shed more light on it, this power is simply not realistic.

With so much power, we don't need such a complicated circuit to detect it.

(Disclaimer: I am an academic. )

You're academic?? Show the math. 2A @ 0.9KV? Kilowatts? Oh my. Academics would understand a basic concept called phase angle taught in 101 electronics. I've already shown my math. Point out the error in my math. Show your math and  I'll point out your error. smh

Free Energy | searching for free energy and discussing free energy

Re: Who would you like to witness a self-runner?
« Reply #19 on: November 03, 2017, 08:12:41 PM »
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Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #20 on: November 03, 2017, 08:38:13 PM »
This post proves you don't know much about electrical engineering.

ps, I'll save you the time. The 0.9KV you talk about is more like 1.10KV across the capacitor and 1.12KV across the inductor, while the voltage from the free energy source is about 10mV (10E-3 V, 0.01 V). What academic are you? No offense, but it's obviously not electrical engineering. Lets save our time here and end this nonsense unless you want to prove to a lot of people you're an agent. ;)

It's okay, but please learn at school or on your own. Not at the cost of others. Or maybe that's your goal.

Offline Magluvin

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Re: Who would you like to witness a self-runner?
« Reply #21 on: November 04, 2017, 02:13:04 AM »
If humanity isn't ready now, it won't be any more ready in 3 years.

My guess is that it doesn't work dependably.

Tesla said it in an interview way back then, 'There is no better time than now' when asked if he thought the world was ready for free energy. ;)   And I agree

Mags

Free Energy | searching for free energy and discussing free energy

Re: Who would you like to witness a self-runner?
« Reply #21 on: November 04, 2017, 02:13:04 AM »
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Offline blueplanet

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Re: Who would you like to witness a self-runner?
« Reply #22 on: November 04, 2017, 02:33:20 AM »
You're academic?? Show the math. 2A @ 0.9KV? Kilowatts? Oh my. Academics would understand a basic concept called phase angle taught in 101 electronics. I've already shown my math. Point out the error in my math. Show your math and  I'll point out your error. smh


It is not from my maths. I actually ran LTspice simulation on your circuit. I agree that the power at B2 is most likely zero. However, the steady current of B2 was about 2A. This much current is unlikely from space waves. As I said, I am interested in your air-core. If there is any secrecy concerned, you can PM me.

Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #23 on: November 04, 2017, 02:40:06 AM »
The 2A is caused by the oscillator. Again, please learn basic 101 electronics before making such statements.

Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #24 on: November 04, 2017, 02:42:04 AM »
Tesla said it in an interview way back then, 'There is no better time than now' when asked if he thought the world was ready for free energy. ;)   And I agree

Mags

Yup. I'm more of an Einstein guy, who later greatly regretted helping scientists and engineers develop the nuclear bomb.

Free Energy | searching for free energy and discussing free energy

Re: Who would you like to witness a self-runner?
« Reply #24 on: November 04, 2017, 02:42:04 AM »
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Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #25 on: November 04, 2017, 02:47:11 AM »
If humanity isn't ready now, it won't be any more ready in 3 years.

My guess is that it doesn't work dependably.

After such technology is released to the public then how long would it be before they understand the physics that allows north korea and terrorists to blow up entire continents? Lets say it's 4 years. If the device is released in 2020, then maybe by 2024 the world would have calmed down, humanity enters full adulthood, and everything is okay. Release it now and maybe by 2021 the world isn't ready. Better to be safe.

Offline Magluvin

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Re: Who would you like to witness a self-runner?
« Reply #26 on: November 04, 2017, 03:02:08 AM »
Yup. I'm more of an Einstein guy, who later greatly regretted helping scientists and engineers develop the nuclear bomb.

Well then it would appear you have just turned to Einstein in the last day or so, as it seemed you were showing something to everyone here, till now.

Mags


Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #27 on: November 04, 2017, 03:08:44 AM »
Well then it would appear you have just turned to Einstein in the last day or so, as it seemed you were showing something to everyone here, till now.

Mags
How so? The spectrum footage? Nah that didn't show anything except an interesting self-runner effect.

Offline Magluvin

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Re: Who would you like to witness a self-runner?
« Reply #28 on: November 04, 2017, 03:16:22 AM »
How so? The spectrum footage? Nah that didn't show anything except an interesting self-runner effect.

lol  Well then what is the point????

Mags


Offline Theoretical Research

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Re: Who would you like to witness a self-runner?
« Reply #29 on: November 04, 2017, 03:19:12 AM »
lol  Well then what is the point????

Mags
Just to show an interesting effect. :/

Free Energy | searching for free energy and discussing free energy

Re: Who would you like to witness a self-runner?
« Reply #29 on: November 04, 2017, 03:19:12 AM »

 

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