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Author Topic: capacitor in series charging  (Read 1312 times)

Offline stoyan_

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capacitor in series charging
« on: February 11, 2017, 12:24:01 AM »
Initial state - State 1

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capacitor in series charging
« on: February 11, 2017, 12:24:01 AM »

Offline stoyan_

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Re: capacitor in series charging
« Reply #1 on: February 11, 2017, 12:24:59 AM »
State 2 - discharging during operation (it is not specified when).

Free Energy | searching for free energy and discussing free energy


Offline stoyan_

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Re: capacitor in series charging
« Reply #2 on: February 11, 2017, 12:25:56 AM »
State 3 - Charging again during operation (not specified again, it is specified during operation)

Offline stoyan_

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Re: capacitor in series charging
« Reply #3 on: February 11, 2017, 12:35:24 AM »
Hi all,
after posting the 3 pictures,

I've got the following question:

State 1 - Initial state . After starting what will be the Voltage of the capacitor C2
State 2 - Somewhere during operation The C2 is shorted/discharged
State 3 - Somewhere during operation (after fully discharging C2) the C1 is closed and the C2 is open again.

What will be the voltages of C2 in all states

Many thanks . I've got only simulation results.
S1 and S2 are switches (made with  transistors/MOSFETS/whatever)

(S1 is closed, S2 is open) State 1 - C2 (Voltage) =
(S1 is open, S2 is closed) State 2 - C2 (Voltage) =
(S1 is closed, S2 is open) State 3 - C2 (Voltage) =



Offline stoyan_

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Re: capacitor in series charging
« Reply #4 on: February 13, 2017, 08:17:24 PM »
Anyone interested ?

Free Energy | searching for free energy and discussing free energy

Re: capacitor in series charging
« Reply #4 on: February 13, 2017, 08:17:24 PM »
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Online citfta

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Re: capacitor in series charging
« Reply #5 on: February 13, 2017, 09:36:08 PM »
Well I am curious why you keep posting schematics of circuits that don't really make any sense.  I am not trying to be harsh but I don't understand what you are trying to do.  I am pretty sure I asked you once before what you were trying to do and got no answer.  Are you using this forum to try and learn about electronics?  Are you just throwing circuits together to ask questions about them for some other reason?  I am pretty sure you are getting no response from your questions because no one understands why you are asking them.  The circuit you posted in this thread makes no sense.

You have a cap being charged by a power source at the same time the current is going through a bridge rectifier to a cap and load.  Then you create a dead short across the cap and discharge it to itself without any kind of load or resistance.  Why?

I will answer this time but this will be the last time unless you explain what you are trying to do.  In the first schematic the cap will charge to about 220 volts.  In the second where you short the capacitor of course the voltage will be zero.  I don't understand why you even asked that.  In the last schematic the cap will again charge to about 220 volts.

Carroll

Offline stoyan_

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Re: capacitor in series charging
« Reply #6 on: February 13, 2017, 09:48:20 PM »
Thanks a lot. For confirmation. Need to be 100% sure.
Sorry and other opinions are also welcome.

Free Energy | searching for free energy and discussing free energy

Re: capacitor in series charging
« Reply #6 on: February 13, 2017, 09:48:20 PM »
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Offline stoyan_

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capacitor in series charging
« Reply #7 on: February 15, 2017, 09:20:33 PM »
Other opinions many thanks !

Offline stoyan_

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Re: capacitor in series charging
« Reply #8 on: February 18, 2017, 06:14:43 PM »
hi

Online citfta

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Re: capacitor in series charging
« Reply #9 on: February 18, 2017, 07:33:27 PM »
Other opinions many thanks !

What I posted was NOT an opinion.  It was fact based upon the known way that circuits work.

I have already suggested why no one responds to your posts.

Free Energy | searching for free energy and discussing free energy

Re: capacitor in series charging
« Reply #9 on: February 18, 2017, 07:33:27 PM »
Sponsored links:




Offline stoyan_

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Re: capacitor in series charging
« Reply #10 on: February 24, 2017, 05:31:00 AM »
Thank you. Anyone else ?

 

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