Author Topic: OVERUNITY AT LAST ! (Read 8498 times)

magnetman12003 · « **on:** December 08, 2016, 10:29:47 PM »

Check it out on the You Tube. All explained in my comments. I am willing to share the circuit with those interested but first I have to find someone that's good in CAD drawings to update my older drawing.

https://www.youtube.com/watch?feature=em-upload_owner&v=CzOo6aVEOzo&app=desktop

Turbo · « **Reply #1 on:** December 09, 2016, 09:48:40 AM »

How is that overunity when theres a big chunk of a battery connected to your circuit ?
Remove the battery and if it keeps running you might be on to something.

ayeaye · « **Reply #2 on:** December 09, 2016, 10:20:32 AM »

All i see, there is a big coil, and a smaller coil, and a bunch of batteries. Multimeter shows 46 V, and ammeter shows 0.7 A, if all were DC then it were 32 W. If not DC then the multimeter shows average, so it may as well be 1000 volts. Two liight bulbs are burning, not known what type of light bulbs these are and with what brightness they burn. So where is overunity? Or what else do you want to show? Your comments i cannot read, because youtube doesn't allow me to read comments.

magnetman12003 · « **Reply #3 on:** December 09, 2016, 10:27:32 AM »

I only have one 12 volt 1.2 amp battery connected to the circuit. The other batteries you see there are spares and are not used. I should have removed them to make a clean setup.

ayeaye · « **Reply #4 on:** December 09, 2016, 10:32:52 AM »

Quote from: magnetman12003 on December 09, 2016, 10:27:32 AM

I only have one 12 volt 1.2 amp battery connected to the circuit. The other batteries you see there are spares and are not used. I should have removed them to make a clean setup.

K, so you say your 12 volt battery gives 32 W? Very possible. What concerns batteries then they can give any power, from time to time or for a short time, the specifications of the battery do not show the power.

Please show the circuit diagram. Please measure the input power and the output power. If any of these is AC, then measure it with oscilloscope. As the frequencies you have are not great i guess, then you can use the computer microphone input as an oscilloscope. But calibrate it first with a square wave signal, as you can measure the amplitude of a positive square wave signal in the DC range of your multimeter. Read the posts there http://overunity.com/problems-and-solutions-for-accurate-measurements/#.WEqd97Np_iY to do it, but be careful. And if there is any other signal of interest, please show their traces. As if you think something interesting is happening, then it's important to see, what exactly is happening.

TinselKoala · « **Reply #5 on:** December 09, 2016, 12:21:17 PM »

Quote from: magnetman12003 on December 09, 2016, 10:27:32 AM

I only have one 12 volt 1.2 amp battery connected to the circuit. The other batteries you see there are spares and are not used. I should have removed them to make a clean setup.

Do not confuse "Amp" with "Amp-hour" (A-h). Your battery is capable of producing a current far higher than "1.2 amp" when driving a low-impedance load. "1.2 Amp-hours" is a measure of the energy capacity of the battery. 1.2 Amp-hours at 12 volts is equivalent to a stored (deliverable hopefully) ENERGY of 12v x 1.2 amp-hr x 60 min/hr x 60 sec/min = nearly 52 thousand Joules. I encourage you to "do the math" and to observe that the units properly cancel and result in units of Joules (Watt-seconds) in the answer. This is the figure you have got to beat somehow in your circuit's "output". To make it simple, the battery contains, when properly charged, about 52 thousand Joules of energy. You need to prove that your system can output more than that, before the battery runs down completely and your system stops running.

This energy can be delivered at a low power level over a long time, or at higher power levels for shorter times. Your video, unfortunately, does not show "OVERUNITY AT LAST!" but rather reveals once again how easy it is to be confused by pulsed circuits with high inductances, combined with less-than-adequate measurements and a lack of grounding in the basics of electricity and physics in general.

citfta · « **Reply #6 on:** December 09, 2016, 12:57:05 PM »

@ TK

Very glad to see you back. You are of course completely correct in your observations. The thing that caught my attention was the mention of overheating problems with the transistor. I don't believe any circuit could be OU if it is wasting a lot of energy heating up a transistor. Why people think they can invent an OU circuit or device without learning the basics is what I don't understand.

I am so tired of the old line they put out about not wanting to be confused by the "wrong" teachings in our school systems. That is like saying I want to explore unknown parts of the world but don't confuse me by teaching me how to read a map. We have to learn what is known before we have any chance at all of recognizing something that is unknown.

Edit: I see he has replaced the original video with another one. My comments about the overheating transistor were about the original video.

magnetman12003 · « **Reply #7 on:** December 09, 2016, 06:48:10 PM »

Quote from: magnetman12003 on December 08, 2016, 10:29:47 PM

Check it out on the You Tube. All explained in my comments. I am willing to share the circuit with those interested but first I have to find someone that's good in CAD drawings to update my older drawing.

https://www.youtube.com/watch?feature=em-upload_owner&v=CzOo6aVEOzo&app=desktop

The bottom line is the circuit draws 6.7 watts and it is powering two 7 watt lamps to full intensity ALL THE TIME IN BOTH CASES. Any reference to a transistor overheating is found in one of my other projects completely unrelated to this one.

ayeaye · « **Reply #8 on:** December 09, 2016, 07:08:11 PM »

Quote from: magnetman12003 on December 09, 2016, 06:48:10 PM

The bottom line is the circuit draws 6.7 watts and it is powering two 7 watt lamps to full intensity

And what is extraordinary in that? Two 7 watt lamps can well burn with a half brightness, with 6.7 watts. It is very difficult to measure brightness of lamps, no one also knows the sensitivity of your camera, cameras automatically adjust sensitivity. Lamps are also otherwise very bad as a load, in addition they are also non-linear. Better use resistors.

Measure input and output power with oscilloscope. I know it is much more difficult, but this is extremely important. A completely unavoidable and necessary evil. If you use computer microphone input as an oscilloscope, it has ac coupling, your multimeter may show the dc component.

As i said i cannot read youtube comments, i think some others who are not registered there, also cannot.

Use gschem for circuit diagrams, free and easy to use, install geda.

Turbo · « **Reply #9 on:** December 10, 2016, 07:01:44 AM »

Quote from: magnetman12003 on December 09, 2016, 06:48:10 PM

The bottom line is the circuit draws 6.7 watts and it is powering two 7 watt lamps to full intensity ALL THE TIME IN BOTH CASES. Any reference to a transistor overheating is found in one of my other projects completely unrelated to this one.

I have some LED's here i think they are overunity leds... can i send you a pic so you can see the brightness and confirm that they are ?

verpies · « **Reply #10 on:** December 10, 2016, 08:59:58 PM »

Quote from: magnetman12003 on December 09, 2016, 06:48:10 PM

The bottom line is the circuit draws 6.7 watts

How do you know that?

pulp · « **Reply #11 on:** December 10, 2016, 09:39:30 PM »

Try with one 12v MN27 battery and if works the same is over unity for sure.

allcanadian · « **Reply #12 on:** December 15, 2016, 07:08:02 AM »

Turbo

Quote

I have some LED's here i think they are overunity leds... can i send you a pic so you can see the brightness and confirm that they are ?

I'm sure there overunity because I can see them from here... no wait I was looking at the Sun again. False alarm.

AC

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