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Author Topic: twofer  (Read 7096 times)

Offline webby1

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Re: twofer
« Reply #30 on: November 10, 2016, 04:48:44 PM »
To take this to the next step that I was thinking,,

If I could reverse charge C2 just prior to the transistor firing off then the load would see the voltage on C2 plus the source voltage and that would allow the source to pass a larger current through the load,, so if I were running a pulse motor with something like this my input voltage would not change but the input current would increase as the pulse motor spun up faster providing for a larger reverse voltage on C2 to be captured from the drive coil\autotransformer increasing the difference in potential.

I do not see much with this but it is an interesting idea to use the input current to control the RPM instead of the input voltage,, I mean what is the difference between supplying 10V @ 100A or 100V at 10A as far as energy goes.

Free Energy | searching for free energy and discussing free energy

Re: twofer
« Reply #30 on: November 10, 2016, 04:48:44 PM »

Offline webby1

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Re: twofer
« Reply #31 on: November 10, 2016, 11:18:51 PM »
This is my setup now,,

These are some values I took with this setup

Right side resistor 545 left side 549

1uf timing cap
14000uf C2 cap  27.1 fluke 12.8V
53.3 fluke with resistors holding 9.2V on right and 5.93 on left

with a "new" cap on the right side
57.2 fluke 12.8V with resistors holding 9.9V on right 6.54 on left

with "new" cap on left side
54.8 fluke 12.8V with resistors holding 8.8V on right side and 7.18 on left

with both "new caps
58.6
4 fluke 12.8V with resistors holding 9.3V on right side and 7.91V on left


10uf timing cap
14000uf C2 cap faster rise time 27  fluke 12.8V
53.9 fluke with resistors holding 8.9V on right and 6.59V on left


47uf timing cap
14000uf C2 cap  faster rise time 27 fluke 12.8V
54.3 fluke with resistors holding 8.7V on right and 6.9V on left

270uf timing cap
14000uf C2 cap faster rise time 27.14 fluke 12.8V slightly higher cap voltage.
Holding 9V on the caps wih the reistors shows 57.5 fluke,, holding 8.5V average over resistor,, times 2

Free Energy | searching for free energy and discussing free energy


Offline tinman

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Re: twofer
« Reply #32 on: November 10, 2016, 11:49:20 PM »
To take this to the next step that I was thinking,,

If I could reverse charge C2 just prior to the transistor firing off then the load would see the voltage on C2 plus the source voltage and that would allow the source to pass a larger current through the load,, so if I were running a pulse motor with something like this my input voltage would not change but the input current would increase as the pulse motor spun up faster providing for a larger reverse voltage on C2 to be captured from the drive coil\autotransformer increasing the difference in potential.

I do not see much with this but it is an interesting idea to use the input current to control the RPM instead of the input voltage,, I mean what is the difference between supplying 10V @ 100A or 100V at 10A as far as energy goes.

10v @ 100A will produce far more waste heat than 100v @ 10A,even though the power value is the same.
So keep your voltage high,and your current low.


Brad

Offline webby1

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Re: twofer
« Reply #33 on: November 11, 2016, 12:25:24 AM »
Very true,,

Funny that it is IR^2 losses,, so more I more loss. 


Offline webby1

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Re: twofer
« Reply #34 on: November 11, 2016, 05:55:06 PM »
This one is a just for fun thing,, I was not expecting much of anything special,, and I think it almost delivered :)

I am only pulsing one switch,, not sure if it is S2 or S3,, but one works way better than the other.

I think this is basically a boost converter,, basically.

When I get my hand operated switching just right I can get both caps to go up,, I am using a jumper wire for the switch :)  and when I tap it with just a little bit of a slide to it at just the right rate both caps go up fairly easy,, the highest I have got so far with an input of 12.8V is 20.4V.

ETA:  the current goes up a lot as well but with a light enough tap I can keep it under 200mA

Free Energy | searching for free energy and discussing free energy

Re: twofer
« Reply #34 on: November 11, 2016, 05:55:06 PM »
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Offline webby1

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Re: twofer
« Reply #35 on: November 18, 2016, 07:46:53 PM »
This one is kind of fun,, I think I am biasing the circuit with the flyback or scavenge.

constant run values
R2 is 545 ohms     3.69V
R3 is 5600 ohms   8.07V

Input is 10V @ 26mA

When I short  the scavenge cap, C2, and short the load cap, C3, then run the input,, the load cap and input current go up but as the scavenge cap C2 increases in its voltage the load cap goes down as well as the input current.


Offline webby1

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Re: twofer
« Reply #36 on: November 18, 2016, 09:52:09 PM »
I forgot to mention that without the coil connected at all the input is  21mA @ 10V

Free Energy | searching for free energy and discussing free energy

Re: twofer
« Reply #36 on: November 18, 2016, 09:52:09 PM »
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