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Author Topic: Faraday paradox revisited,magnetic field rotation question.  (Read 15750 times)

Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #60 on: August 25, 2016, 04:18:29 PM »
Quote
Consider that the field is a loop from one pole to the other and any conductor would in fact be passing through the field in both directions. So any movement through the field generates a canceling charge from the same field passing through the conductor in the opposite direction and provide zero current.

hmm i also start thinking about something like this... yeah...

its like a two transformers connected out of phase? right? electron pushes against electron so 0 current? in such transformers configuration  coils(with stuck current) are getting hot or not?

Free Energy | searching for free energy and discussing free energy


Offline lumen

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #61 on: August 25, 2016, 05:13:28 PM »
hmm i also start thinking about something like this... yeah...

its like a two transformers connected out of phase? right? electron pushes against electron so 0 current? in such transformers configuration  coils(with stuck current) are getting hot or not?

Yes, same problem and with no current there is no heat generated.

The point that a connection is needed to, is exactly where the field starts to change direction and pass back through the conductor which is at the edge of the magnet face.
So now you can see that all you need to do is make a connection to that point on the conductor without passing through either of the two fields again. Impossible.

If one of the conductors does not move in the field then a current can be generated as in the case of the Faraday generator.
This is why we wonder where the current is generated, in the disk or the conductor, and may depend on whether or not the magnet rotates which one is providing the current flow.





Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #62 on: August 26, 2016, 09:58:40 AM »
and what about this?
https://www.youtube.com/watch?v=rWO7O5hvzWE

this is a soild proof for non rotating field?

Offline Enjoykin2017

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #63 on: August 26, 2016, 10:49:49 AM »
"Physics stands on a stable foundation of the facts, but not on drift sand of imaginary hypotheses", E. Rutherford.

http://rexresearch.com/gary/gary1.htm



Free Energy | searching for free energy and discussing free energy

Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #64 on: August 26, 2016, 11:47:48 AM »
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Offline lumen

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #65 on: August 26, 2016, 04:28:28 PM »
and what about this?
https://www.youtube.com/watch?v=rWO7O5hvzWE

this is a soild proof for non rotating field?

No, It's solid proof that there is no change in field direction with axis rotation.
The TV screen is only responding to field direction and density. Neither changes in axis rotation.

Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #66 on: August 26, 2016, 06:37:18 PM »
No, It's solid proof that there is no change in field direction with axis rotation.
The TV screen is only responding to field direction and density. Neither changes in axis rotation.

yees, electron gun will shoot the same direction no matter if the field rotate on axis or not, beam will not twist.
i have problems with making a magnet perfectly rotating on axis for electroscope experiment, magnet rotation should have no wobbling or orbiting...
Wesley Garry neutral zone stuff and pole reversal do not belong to this topic however its very interesting indeed.

Free Energy | searching for free energy and discussing free energy

Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #66 on: August 26, 2016, 06:37:18 PM »
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Offline Enjoykin2017

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #67 on: August 27, 2016, 12:50:20 AM »
PolaczekCebulaczek

In electronics acceleration of beam electrons is created by tension on a special electrode of electronic gun. It is acceleration by electric field.

In electrical engineering current in wires is created a little differently.

On a certain site of wire, create excess quantity of electrons, leading to deformation of their static fields. This deformation of power braids (static field) surrounding electrons is elastic.  Extent of this deformation of power braids is a tension ( voltage ) of electric current. And as soon as this very elastic and well deformed electron bunch get opportunity to move on a conductor which is for electrons by essence an hollow tube , it directs with a speed defined by well known experimentaly made formula in electronics

Ve= 5,95 x 105 √U (m/s).

Ve = Initial Velocity of Electrons (m/s).
U = Initial Accelerating voltage (V).

For example. At voltage (tension) of 220 V the speed of conducting electrons in the conductor is 90 000 km/s. At a voltage of 500 kV the speed of electrons will be 420 000 km/s. If that tension is 12 MV (million volts) like Tesla usually used in his experiments, speed of conducting electrons is 2 million kilometres per second. As you understand its a superluminal velocity ~7 times faster than light (photonic speed in free space).

So really going this process.  :)

My question: What will be with electrons when accelerated till superluminal speed you suddendly stop them. Can you calculate inertial forces which will smash electrons and throw out all their inner matter - magnetic particles (magnetic matter) and electric particles (photons) ? Keep in mind that density of these particles in an electron shell is 15 000 ton/cm3 and their number is ~ 3 х 1010 particles in equal shares.

Nothing in our dimension cant stand against Inertia forces !  :o

As with an electron we will have a lot of job, lets remember its main characteristics.

The electron has the mass of m = 9,1x10-31 kg, r radius = 2,82x10-15 m, its charge is q = 1,6x10-19 C. If we present an electron in the ball form, then it is easy to find density of its weight. It is d ≈ 1,5x107 kg/cm3.

These are 15 000 ton/cm3! Why the Mother nature for some reason needed such huge concentration of matter. And this workshop in vain does nothing.  ::)


ps: Power braids are in essence "LINES OF FORCES", and they present matter - electrical matter

---------------------------------------------------
"Physics stands on a stable foundation of the facts, but not on drift sand of imaginary hypotheses", E. Rutherford.
« Last Edit: August 27, 2016, 04:30:23 AM by Enjoykin2017 »

Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #68 on: August 27, 2016, 09:47:19 AM »
Quote
My question: What will be with electrons when accelerated till superluminal speed you suddendly stop them. Can you calculate inertial forces which will smash electrons and throw out all their inner matter - magnetic particles (magnetic matter) and electric particles (photons) ? Keep in mind that density of these particles in an electron shell is 15 000 ton/cm3 and their number is ~ 3 х 1010 particles in equal shares.

well, electron will crush upon itself when suddenly stopped. something like this will happen, i guess....

https://en.wikipedia.org/wiki/M%C3%B8ller_scattering

Enjoykin2017 if you want to smash some electrons, i recommend this :

Offline Enjoykin2017

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #69 on: August 28, 2016, 12:53:48 AM »
Yes you are right Tesla Disruptive Technology - source of RADIANT FREE ENERGY (COLD FIRE) !!  :)
....

"Physics stands on the strong base of the facts, but not on drift sand of imaginary hypotheses" — E. Rutherford.

Dear Ernest Rutherford's saying arose from difficult research experiences of radioactivity which had gave in the physicist's hands the most exact tool for an atom preparation – α-particles (twice ionized cores of helium He+2) which were bombarded thin plates of metals and studied paths of α-particles after interaction with a thin plate. Some of  α-particles flew away without changing  original direction, others deviated on different angles and quite seldom α-particles recoiled from a thin plate as though it was a monolith. It means there was a direct hit in a target core substance . Nearly four years were required to E. Rutherford to discover the atomic nucleus size (3х10-12 cm) and the size of atom which was four orders of magnitude more than the core. 

Not by tip of a pen or computer simulation, but with long experience,  wearisome experiments and observations,  E. Rutherford received the major truth. Tesla also !!

Here, the main interaction happens between electrons of an accelerated bundle and metal electrons. Other interactions are four orders magnitude rare and aren't defining. Specified interaction is a sharp braking of electrons of a bundle and a sharp acceleration of electrons of metal. There are practically no other acts.

Two electrons face different speeds. Collision turns out to be elastic, as having the same charges, in case of their approximation at distance equal to diameter of an electron, there is working Coulomb force of repulsion
Fc= e·e / (2·r)2

where е = 1,6 x 10-19 C — an electron charge;
r — electron radius;
2·r — distance between centers attractions of two electron spheres 2· 2,82 x 10-15 m = 5,64 x 10-15m.

Having these data, we will get Coulomb repulsion force
Fc= (1,6 x 10-19)2 / (2·r)2 = 2,56 x 10-38 / 3,18 x 10-29 = 8,04 x 10-10 N

Such is repulsion force between electrons. !!  :)

Now we need define inertial force when braking of an accelerated electron:
m = 9,1 x 10-31 kg is mass of an electron
Ve =  electron speed = 0,5 C  where C is light velocity 3 x 108 m/s (photon velocity in free space);
dt is braking time.

For determination of dt we need to take a distance of braking electron, equal S = 10·r which passes this distance at average speedf of Vavr = 0,5 · C / 2 = 0,25 · C. C is light velocity.

We get
dt = S / Vavr =   5,64 x 10-14m / 0,25 C  = 7,52 x 10-22 s.

Now find acceleration
a = dV/ dt =  (0,5·3 x 108 m/s)  /  7,52 x 10-22s  =   0,2 x 1030 m/s2

And the inertial force acting on an electron will be:
F = m·a  = 9,1 x 10-31kg · 0,2 x 1030 m/s2 =  1,8 x 10-1 N. (0,18N)

It is a very-very big force. The principal error here is acceleration determination. Let braking of electron going on a section not 10·r but 100·r, then we get
dt  = dt = S / Vavr =   5,64 x 10-13m / 0,25 C  = 7,52 x 10-21 s.

Acceleration and all remaining will decrease by factor
F = m·a  =   1,8 x 10-2 N. (0,018N)

And only if braking electron happens at distance 107·r, then braking force  is comparable to Coulomb repulsion force,  in case of interaction at distance 2·r.
F = m·a = 1,8 x 10-7 N. (0,000000018N)

And how strong will Coulomb repulsion forces at distance 107·r ??
Fc= e·e / (107·r)2
Fc= (1,6 x 10-19)2 / (107·r)2 = 2,56 x 10-38 / (107· 2,82 x 10-15)2 = 3,2 x 10-23 N

Having these data, we get
3,2 x 10-23 N / 1,8 x 10-7 N = 1,8 x 10-16

It is 16 orders of magnitude less. It means that an accelerated electron, having inertial force many orders bigger, will overcome Coulomb repulsion force and with giant force will hit an electron in thin metal plates.

Let now calculate the pressure of this force of F = 1,8x10-7 N on an electron.
If A= (4/3)·π·( 2,82 x 10-15 m)2 is area of a big circle of electron (cross-section) = 0,33 x 10-30 m2 ,

then the pressure will be
P = F/A =  1,8 x10-7 N / 0,33 x 10-30 m2 = 5,4 x 1021 N/m2 = 5,51 x 1017 t/m2. (tonne per square metre).  1t = 9806.65 N

Or 5,51 x 1013 t/cm2  55,1 billion tonnes per square centimetre.
Such a huge pressure in our macrocosm can't be realized, it is so giant huge.

Now it is easy understanding that the main defining force in the course of generation of X-ray radiation is inertial force of the accelerated electrons for which Coulomb repulsion forces have sixteen order of magnitude smallness.

Electrons of an accelerated bundle of a X-ray tube literally rush into electronic tank of an anti anode, break off its electrons on basic elements and give them a speeds from super luminous till speed of light. On that way X-ray electromagnetic field is created.

As an electron contains two sorts of matter - electrical matter (photons) and magnetic matter (dipole matter), in X-rays these particles are present at corresponding proportions.

So these particles which are beaten out from metal plate electrons in case of their collision at super luminous speeds are main structural particles of electromagnetic fields. These particles having weight, bear forces of fields. They are matter because only the matter can bear a force and their derivations  - force fields are simple clusters of these particles in corresponding proportions.

So really going this process and Tesla is a master №1 of smashing electroons ! :)  

Free Energy | searching for free energy and discussing free energy

Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #69 on: August 28, 2016, 12:53:48 AM »
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Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #70 on: August 28, 2016, 06:00:49 AM »
right... but lets stay on topic.

Im still struggling with electroscope experiment, electronic FET based electroscope is very sensitive, led is flashing when antenna is near motor so i need long shaft for magnet so fet wont pick up any E field coming from motor coil.

meanwhile...

I will never fully understand why when i move already moving electron it suddenly emits E field, its because i slowed electron speed?
In permanent magnet, electrons are moving, not like in wire but since they are moving so there is b field.
What about vacuum tube? is the e field there? i guess there is because electron beam will curve when charged plate is near it.Sooo when coil is wrapped around vacuum tube, a current is induced in that coil?




Offline lumen

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #71 on: August 28, 2016, 05:42:59 PM »
@PolaczekCebulaczek

Maybe you could just spin the magnet while hanging it from a string?

The electroscope would need to show charge while the magnet is spinning one direction and nothing while spinning the other direction to be a valid confirmation since your electroscope will show charge in only one direction.


Offline allcanadian

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #72 on: August 28, 2016, 06:30:19 PM »
@lumen




Quote
Maybe you could just spin the magnet while hanging it from a string?

The electroscope would need to show charge while the magnet is spinning one direction and nothing while spinning the other direction to be a valid confirmation since your electroscope will show charge in only one direction.
Or we could levitate it and spin it up to an absurd RPM with no friction like I did with my device in the picture below. The bottom plate is 3/8" thick aluminum to stabilize the magnet and as we know there is no drag on the axis of rotation.

AC

Offline PolaczekCebulaczek

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #73 on: August 28, 2016, 06:57:04 PM »
Quote
Maybe you could just spin the magnet while hanging it from a string?

The electroscope would need to show charge while the magnet is spinning one direction and nothing while spinning the other direction to be a valid confirmation since your electroscope will show charge in only one direction.

easy to say... magnet will wobble all over the place, it has to be perfectly stable rotation no orbiting or wobbling
the levitation sounds like awesome idea.

Quote
Or we could levitate it and spin it up to an absurd RPM with no friction like I did in the picture below. The bottom plate is 3/8" thick aluminum to stabilize the magnet and as we know there is no drag on the axis of rotation.

how did you levitate it? levitron stuff?


Offline lumen

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Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #74 on: August 28, 2016, 08:50:55 PM »
That's a good idea, but could you just as easily spin it on a string over the aluminum plate to stabilize it?

Find a wooden dowel to fit in a ring magnet and center a string in the dowel then wind up the string and as it unwinds over the aluminum plate it should be stable.

The aluminum plate may however mask another condition that may exist where the plate causes the field to become stationary and instead slip in the gap between the magnet and the plate.

That is why I originally thought suspended only from a string.

Free Energy | searching for free energy and discussing free energy

Re: Faraday paradox revisited,magnetic field rotation question.
« Reply #74 on: August 28, 2016, 08:50:55 PM »

 

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