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Gravity is what makes the machine work. He lifts the arm to create the wave. Or he pushes the balanced arm down, which lifts the opposite end. Gravity then takes over when he releases it.

Also his math is incomplete, you need to calculate the lengths of the arms in reference to the center axis.

It's a bunch of balanced weights. I disrupt that balance by, either lifting or pushing down, then release, the work I put in is translated.

This sounds like Bessler Wheel logic. But just saying this will not bring it home to you. Therefore let us pick apart your explanation, and examine the validity of each claim and idea. If the wave machine is only a bunch of balanced weights for you, then why don’t you start checking your theory by examining one single balanced weight? Imagine a modified special seesaw, which is not close to the ground, but it is at a height which allows the arms to make complete rotations around the axis. Now, you do the same as Prof. did in the video. You grab one end of the balanced seesaw, move it down a little and immediately move it up again into its starting position. Before you release the seesaw, make sure that the arm is stationary (v=0) just like it was before the start of our experiment. Now will this seesaw perform any oscillatory movement like it was observed in the wave machine? If gravity is the restoring force of any potential oscillation (like in the case of a simple pendulum), then your seesaw must oscillate.An alternative experiment is to just rise one end of the seesaw, make sure that it is stationary, and release it. Will it start to oscillate like a pendulum?I don’t respond to the second part of your post, because it makes no sense at all, and first we have to get you understand what is wrong with your explanation.

I think you are saying that the total potential + kinetic energy of the system is unchanged, like in a pendulum?

BTW, I wasn't able to watch the video - can't open that file.

This in turn creates a torsion stress in the above wire. The rest of the system behaves as a multitude of the pendulums oscillating around the point of the equilibrium.

This matter consists of the atoms. Perhaps by stressing it we can influence the atomic structure?

When you are done with digesting the material, then please try to summarize and explain the working mechanism of the wave machine as a series of coupled torsional oscillators. You may also perform a google search about coupled oscillators, or coupled pendulums to give you an idea how to attack the problem.

The biggest amplitude is at the point of the most twisted wire, and a vise versa. So the energy can be determined from the amount of work which takes to perform the twisting.

It equals F x S, where F is the twisting force, and S is the distance of the arch of the applied force.

The total for the wave would be the integral of these over the length of the wave.

Here is what we know: the properties of the transmission line (given by the manufacturer), the amplitude, wave length, and shape of the wave (sinusoid). That’s all. From this we should be able to calculate the energy content of the wave.The formula for calculating the work W=F*s is correct, but when we are dealing with rotation then engineers don’t use such notation. In case of rotation the work (or energy) is calculated as W=M*theta where M is a torque (M=F x r, vector product - where r is the radial distance of the attacking force from the axis) and theta is the angle of rotation (in radians).

This is partially true. First of all, in case of the wave machine, for the calculation of energy content, we can break it up into small discrete segments, and treat each segment as a simple torsion pendulum. Each rod with its piece of central torsion wire is a single segment. Therefore, instead of integration, we can simply use a summation to add together the energy contents of all the segments.

But what you have calculated with W=F*s or better with W=M*theta is only the potential energy stored in the elastic distortion of the wire (like in a spring), which is only half of the story. The torsion pendulum has got kinetic energy as well, which has to be added to the potential energy in order to get the total energy content.

Let’s summarize what we have figured out so far. The wave machine demonstrates the propagation of torsional waves in an elastic rod or wire as a transmission line. In order to let us see the wave movement, it uses balanced rods periodically attached to the torsion wire. The rods are either soldered to the torsion wire, or fixed to it with other techniques in such a way that they don’t slip. The rods serve dual purpose; they slow the wave down, and they also convert the torsion into translation to make the amplitude more visible. The wave machine can be analyzed as a series of individual torsion pendulums all connected together. Although the shape of the pulse on the attached photo superposition.png in reply #56 of this thread is not exactly sinusoid, for the sake of simplicity let’s calculate the energy content of one half of a sine wave. Let’s assume that the wavelength is λ, and there are 21 rods (20 torsion wire segments) within the half wavelength. The amplitude of vertical displacement of the wave is A, which corresponds to an angular rotation of the rod #10 in the center of the half sinusoid theta_max. Thus we have 20 complete mini torsion pendulums within this length λ/2, which contain the wave pulse and its energy. The displacement of the first and last bar is zero. Let us assume that the angular rotation of each rod in our half sinusoid can be calculated according to the equation attached below (0<=n<=20 is the number of the examined rod). The first rod is #0, the second rod is #1, the central rod is #10, and the last rod is #20.Now all you have to do is calculate the total energy content of the wave, by adding together the energies of all 20 individual mini torsion pendulums that contain the pulse. Please give us the formula that contains both potential and kinetic energies, and can be used for this calculation. This should not be too difficult for you since you have said that you are a mechanical engineer, and I have also given a number of references that discuss torsion pendulums in detail. You can also dust off your old textbooks and refresh your memory about the subject. Then we can demonstrate its use on a specific example, to calculate the numerical value of a specific wave pulse.

Finally we will be able return to the original subject of analyzing whether we can gain excess energy from the superposition of two waves that propagate in opposite directions or not.But I'm very interested in this subject anyway, it really makes me think hard.Finally here are two very useful documents for those who are seriously interested in the practical understanding and building a wave machine:Wave Motion Demonstrator - Instruction Manualftp://ftp.pasco.com/support/Documents/English/SE/SE-9600/SE-9600%20Manual.pdfCoupled Torsion Pendulumhttp://physics.unipune.ernet.in/~phyed/24.3/24.3_Pathare.pdf

Honestly, Zoltan, you are overestimating my limited mental faculties.

I would rather prefer to go the route of the lesser resistance, and have it already done for us by some superior mind.