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Well,so he ended up with more than half the energy in the two caps combined to that of what he started with.So 2.52 volts across 350F=1111.32 joules of energy in one cap,and none in the other.The end result wasCap 1 -1.468v across 350F= 377.129 joulesCap 2-1.273v across 350F= 283.593 joules.Total =660.722 joulesIf we double this,we have 1321.444 joules.So yes,he lost less than the half expected.

Yes, I get that we would need about 1.782V to be left in each capacitor to equal the same energy (Joules) we started with.Okay, screw energy for a moment and just focus on charge:T_{Start}C_{1} -- 2.52V -- 882 CoulombsC_{2} -- 0.0V -- 0 CoulombsQ_{Total}: 882 CoulombsT_{Final}C_{1} -- 1.468V -- 513.8 CoulombsC_{2} -- 1.273V -- 445.55 CoulombsQ_{Total}: 959.35 CoulombsSo how in the heck do we gain charge, but lose energy? Isn't this an entirely "closed loop" system? Charge just jumps in there as energy is split into two chunks? If we had a system that took charge in two clumps and put them into one clump, would we gain energy and lose charge?I need a better way to interpret these results Brad. What is the correct way to think about this simple system? Apparently you cannot think of energy like water and capacitors like buckets. This is so very fundamental, I'd hate to waste this moment and beat my head against the wall for another ten years.M@

Im not even going to pretend i know how that works.I have never had the need to understand or study this situation-Joules V charge,so i can t offer any help there.

Charge is conserved, as is energy. What may _not_ be conserved is the capacitance value of large capacitors, which may vary somewhat according to all kinds of things, like temperature, pressure, voltage, charge-discharge currents, number of C-D cycles, etc. Think about it.

As far as mentioning Kenny Wheeler goes.... even a broken clock could be right twice a day... unless it's a digital clock.

Awesome replies, keep it up This is a work in progress...

Im not even going to pretend i know how that works.C is I x time,where as Joules is watts per second--> 1 joule is 1 watt second.

Looks odd when we look at energy stored in cap'sExample1 volt over 1 Farad= 1 coulomb of charge,but only 500mJ of energy2 volts over 1 Farad =2 coulombs of charge,and 2 joules of energy3 volts over 1 Farad =3 coulombs of charge,but now the energy is higher at 4.5 joules.As we go on,the charge always is the same as the voltage across the cap. If you double the size of the cap,you double the value of charge and energy.So if we had 3 volts across a 2 Farad cap,we have 6 coulombs of charge,and 9 joules of energy.I am not sure why at a low voltage,the charge is a higher value than the joules value,and then they switch places as you raise the voltage,where the joules of energy becomes more than the charge value.I have never had the need to understand or study this situation-Joules V charge,so i can t offer any help there.Brad