Can you have a fixed finite inductance from an inductor that has resistance=0 and capacitance=0

Yes

Brad:

No!  No...

Please do not introduce an ideal pipe into the mix, ha ha.  My head is about to explode from all of the other ideal items we have already.

Bill

PS  No, the magnet would not fall as Lenz would be increased proportionally to the increased conductivity of the copper pipe.

Lol-sorry Bill

What about this-as we are talking about the magnet falling through the copper pipe.

Now lets say the leading field(the one on the bottom of the PM as we place it in the pipe) of the PM is the north field,and the trailing field is the south field. The magnet will induce a field in that copper pipe that apposes that of the magnet,ans so apposes the motion of the magnet. So just below the falling magnet,the copper pipe will be producing a north field--that apposes the motion of the magnet. But dose that mean that a north field is also produced just above the falling magnet--so just above the south field of the magnet,that wants to also appose the motion of the magnet.
Dose this mean that the copper pipe now has produced a mono magnetic field? --north below the falling magnet-pushing against the falling magnet,and north above the falling magnet-pulling on the falling magnet.

This is the way it would work with a shorted coil.
A north field approaches the shorted coil,and the shorted coil produces a magnetic field that apposes the north field of the magnet. Then if we turn the magnet around,and we pull the south field away from the shorted coil,then that shorted coil will produce a north field that wants to pull the magnet back toward it.


Sorry in advance Bill


Brad

Kool-aid is good, as long as it is cherry flavour.

If it is a flavoured powder you add to sugar and water, then probably same thing.

If it is a flavoured powder you add to sugar and water, then probably same thing.

Have you tried our famous vegimite  Poynt?
You have it on toast


Brad

.

It's because the shorted single turn copper coil is producing a magnetic field that apposes that which created it.

I agree and this can be observed in this this video.

If the pipe is cooled down enough,so as it became superconductive,would the magnet still fall?

Depends how large the inner diamaeter of the pipe is compared to the magnet.  If it is small enough then the magnet would bounce forever.
This video illustrates how a falling magnet behaves when it is released from the middle of a single shorted turn that has zero resistance.



P.S.
Again, I remind everyone that the magnitude of the current induced in a perfectly conducting ring does not depend on how fast that magnet is moving.

Also copper cooled by liquid nitrogen does not become superconductive, but the YBCO ceramic does.
Niobium metal becomes superconductive when cooled by liquid helium.