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# New Book

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### Author Topic: Recover energy from gravity  (Read 40754 times)

#### rc4

• Full Member
• Posts: 147
##### Recover energy from gravity
« on: February 15, 2014, 11:21:41 AM »
The fixed grey tube increase height of water, so increase pressure at bottom. External pressure don't change lateral force because grey tube is at right and at left. Inside container, at bottom there is more right force than left but this depend of the diameter of the tube, like tube has more volume inside water, the height of water is greater. Weight=f(h) but Fr-Fl=f(h'). Grey shape is a helix, the length of helix is greater than a triangle so the volume is greater too and the weight too. In the contrary, the right force is the same than a triangle.

Look at h2.png image, s1 and s2 sections are the same and the volume is the same too, so the same weight for container. But with a helix shape, the section is the same than the triangle but the volume is higher, it depend of 2pi. The limit is 0.63 (4R/6piR). Helix don't turn, don't move, it is there only for adding volume inside container, like that the weight is higher and the right force is always equal to the triangle, so the container give more energy than its own weight.
« Last Edit: February 15, 2014, 11:06:12 PM by rc4 »

#### Free Energy | searching for free energy and discussing free energy

##### Recover energy from gravity
« on: February 15, 2014, 11:21:41 AM »

#### rc4

• Full Member
• Posts: 147
##### Re: Recover energy from gravity
« Reply #1 on: February 16, 2014, 09:28:04 PM »
I compute the works for additional weight and F1-Fr force. With:

N: number of turns
S: section of helix (the section of the cable)
a: angle of axis of helix
P: pitch of helix
g: acceleration of gravity
rho: density

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #1 on: February 16, 2014, 09:28:04 PM »

#### Gabriele

• Full Member
• Posts: 249
##### Re: Recover energy from gravity
« Reply #2 on: February 17, 2014, 07:07:01 PM »
Or I'am stupid a lot,or you are a fucking GENIUS!

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #3 on: February 17, 2014, 07:15:12 PM »
You have to make the container turn to gain energy...

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #3 on: February 17, 2014, 07:15:12 PM »

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #4 on: February 17, 2014, 07:18:24 PM »
Seems genial...too genial....

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #4 on: February 17, 2014, 07:18:24 PM »

#### rc4

• Full Member
• Posts: 147
##### Re: Recover energy from gravity
« Reply #5 on: February 17, 2014, 09:12:39 PM »
the container must be like that for have angle constant
why turn ?

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #6 on: February 17, 2014, 09:24:12 PM »
Nope

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #6 on: February 17, 2014, 09:24:12 PM »

#### Gabriele

• Full Member
• Posts: 249
##### Re: Recover energy from gravity
« Reply #7 on: February 17, 2014, 09:26:30 PM »
Can be?

P.S: Are you surethe fall of the container doesn't balance energetically the energy gained from volume rised from revolving?

#### rc4

• Full Member
• Posts: 147
##### Re: Recover energy from gravity
« Reply #8 on: February 17, 2014, 09:58:13 PM »
the volume is always the same with last image (parallelogram)

#### rc4

• Full Member
• Posts: 147
##### Re: Recover energy from gravity
« Reply #9 on: February 17, 2014, 11:02:32 PM »
If the helix is in a parallelogram, I compute the volume less forces Fr-Fl but the weight come from the full volume of helix inside water, but there is less surface due to the helix, so the weight is lower than in the first parameter. The total is 0, but if the first parameter is not exactly that, the sum is not 0. In my calculation, I don't compute f1 and f2 forces of the weight, I consider the full weight, but it is less, it's Weight - (f1 -f2)*surface, so the sum is not to 0.

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #9 on: February 17, 2014, 11:02:32 PM »

#### rc4

• Full Member
• Posts: 147
##### Re: Recover energy from gravity
« Reply #10 on: February 18, 2014, 08:32:07 AM »
let a part of top helix outside water, like that the volume is lower so the weight too. With several number of turns, more than one turn can be outside water; And if the helix turn (not move, just turn like worm drive), the position of helix in water is always the same, need to choose the good position for have no torque on helix.
« Last Edit: February 18, 2014, 10:51:24 AM by rc4 »

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #11 on: February 18, 2014, 02:35:21 PM »
You should use an helix like that

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #11 on: February 18, 2014, 02:35:21 PM »

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #12 on: February 18, 2014, 02:50:54 PM »
If the section of the helix is ovoidal,you can use a rectangle containter insted a parallelogram

#### Gabriele

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• Posts: 249
##### Re: Recover energy from gravity
« Reply #13 on: February 18, 2014, 03:02:51 PM »
It is clear in this way you have to follow during the fall the rotations of the helix

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #13 on: February 18, 2014, 03:02:51 PM »

#### Gabriele

• Full Member
• Posts: 249
##### Re: Recover energy from gravity
« Reply #14 on: February 18, 2014, 03:06:04 PM »
Using an helix like in figure you can mutiply the turns without loosing Fr-Fl

#### Free Energy | searching for free energy and discussing free energy

##### Re: Recover energy from gravity
« Reply #14 on: February 18, 2014, 03:06:04 PM »