Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Is common air plane flight OU?  (Read 14410 times)

schuler

  • Jr. Member
  • **
  • Posts: 50
Is common air plane flight OU?
« on: April 11, 2013, 02:37:29 PM »
 :) Hello :)

I think this is the right place to post the question: is the flight of an air plane over unity? Let me explain: the power generated by most engines is not sufficient to lift an air plane. How can an air plane fly?

Follows an interesting link: http://www.allstar.fiu.edu/aero/airflylvl3.htm

Quote
If we estimate that the average vertical component of the downwash of a Cessna 172 traveling at 110 knots to be about 9 knots, then to generate the needed 2,300 lbs of lift the wing pumps a whopping 2.5 ton/sec of air! In fact, as will be discussed later, this estimate may be as much as a factor of two too low. The amount of air pumped down for a Boeing 747 to create lift for its roughly 800,000 pounds takeoff weight is incredible indeed.

This interesting thing is: a Cessna engine doesn't generate 2,300 libs of force. This is not just a force multiplier because 2.5 ton/sec of air is pumped per second. It seems to be energy multiplier (over unity).

Please share your point of view.

 :) Have fun. :)

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #1 on: April 13, 2013, 10:39:15 AM »
Hi Gianna,

Quote
If we estimate that the average vertical component of the downwash of a Cessna 172 traveling at 110 knots to be about 9 knots, then to generate the needed 2,300 lbs of lift the wing pumps a whopping 2.5 ton/sec of air!

Please explain from where the energy to pump 2.5 ton/sec is coming from. Some technical specs can be found here: http://en.wikipedia.org/wiki/Cessna_172 .

In your reply, I would recommend avoiding statements such as "I have faith that wings can do the magic". Please concentrate the reply in terms of energy. It is known fact 210hp can't lift 2,300 libs.

 :) Have fun  :)

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #2 on: April 13, 2013, 12:53:54 PM »
Follows interesting links:
http://www.grc.nasa.gov/WWW/k-12/airplane/thrust1.html

http://www.av8n.com/how/htm/4forces.html

Quote
Lift is the component of aerodynamic force perpendicular to the relative wind.
Drag is the component of aerodynamic force parallel to the relative wind.
Weight is the force directed downward from the center of mass of the airplane towards the center of the earth. It is proportional to the mass of the airplane times the strength of the gravitational field.
Thrust is the force produced by the engine. It is directed forward along the axis of the engine.

In most civilian airplanes (if not all), thrust is smaller than weight.

Follows interesting link about
Thrust-to-weight ratiohttp://en.wikipedia.org/wiki/Thrust-to-weight_ratio
 :) Have Fun  :) [/li]
[/list]

tagor

  • Hero Member
  • *****
  • Posts: 1333
Re: Is common air plane flight OU?
« Reply #3 on: April 13, 2013, 05:17:34 PM »
It is known fact 210hp can't lift 2,300 libs.

 :) Have fun  :)

LOL
you are very funy
 
in french
des objets plus lourd que l'air ne peuvent pas voler

L4ZEP

  • Newbie
  • *
  • Posts: 4
Re: Is common air plane flight OU?
« Reply #4 on: April 13, 2013, 06:40:57 PM »
L4ZEP:
Common air flight isn't OU, because the energy is after the landing of the airplane exhausted and gone as a warm packet of air.

fritznien

  • Sr. Member
  • ****
  • Posts: 294
Re: Is common air plane flight OU?
« Reply #5 on: April 13, 2013, 07:10:06 PM »
i get about 50 horsepower to keep the plane up.
the question is how much energy does it take to accelerate 2.5 tons of air to produce 2300 pounds of lift.
do the math.

Pirate88179

  • elite_member
  • Hero Member
  • ******
  • Posts: 8366
Re: Is common air plane flight OU?
« Reply #6 on: April 14, 2013, 08:29:31 AM »
Exactly correct that sailplanes can fly with no engine.  Ultralight planes fly with 25 hp.  This is NOT overunity but known physics that I learned while taking flight training.

The Wright brother's plane flew with about 40 hp and it was very heavy and the airfoils were not as great as they are today.

Airplanes fly due to a combination of Bernoulli  and Newrton.

Bill

Lakes

  • Sr. Member
  • ****
  • Posts: 383
Re: Is common air plane flight OU?
« Reply #7 on: April 14, 2013, 11:08:11 AM »
Only OU if you keep walking/running :)

http://www.youtube.com/watch?v=Xxu3hYFGT2c

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #8 on: April 14, 2013, 01:59:16 PM »
 :) Hi  :)

Thank you for all your replies with no exception.

I would like to bring to your attention that faith based argumentation won't convince me. Follows examples that won't change my mind in any direction:

Quote
* I have faith that wings do the magic.
* It's not OU due to physics that I've learned but I won't show you my calculation.
* I have faith that OU is impossible.
* I have attended to some cool classes and you should believe me.

fritznien, thank you for starting the debate in terms of numbers. I personally prefer numbers than faith. So, here we go:

http://www.convert-measurement-units.com/convert+Horsepower+to+Kilogram-force+meter.php
http://en.wikipedia.org/wiki/Horsepower

2300 libs = 1043 kg. Therefore, we need 1043kgf to sustain the flight.
1HP = 75kgf m/s .
14HP is approximately 1043kgf m/s. We could say that 14 horses could lift a Cessna... The problem is how efficiently the air plane engine converts its own 210 HP into aerodynamic thrust. The resulting thrust is smaller than the weight making impossible for a Cessna a sustained vertical flight (you can try in any flight simulator). In the case you have never tried, you can try this free flight simulator: www.gefs-online.com/ .

In a sustained horizontal flight, drag compensates thrust and lift compensates weight. So, the resulting force is vectorial ZERO. If the resulting force is zero and lift is bigger than thrust, from where comes the extra force?

 :) Have Fun :)

fritznien

  • Sr. Member
  • ****
  • Posts: 294
Re: Is common air plane flight OU?
« Reply #9 on: April 14, 2013, 10:54:42 PM »
in flight the force to produce lift is part of the drag. by your numbers we have lots of power for lift.
who said anything about vertical flight,the climb rating on a cesna is 1000 feet per min.
from wiki Cruise speed: 122 kn (140 mph; 226 km/h)
or 62 m/s
 you have 14 hp for lift 14*75=1050 kg/m
(1050kg/ms)/62ms=72kg rounded off of thrust to keep it in the air.
all thats required for the plane to fly is for the forward speed to be converted to a much slower
downward speed with much larger mass.could that be your 2.5 tons?
looks like a form of leaverage.
 if you want details on this you should be in a forum for fluid dynamics.
fritznien



L4ZEP

  • Newbie
  • *
  • Posts: 4
Re: Is common air plane flight OU?
« Reply #10 on: April 15, 2013, 04:48:07 PM »
@fritznien
Dear friend, you can't write what you want without a Lilienthal-Diagramm of a Cessna. It would be very messy. The thrust of the machine is a function of the motor, in the direction of the centerline of the airplane. The lift-force is a non-linear function of the velocity and the Anstellwinkel of the airfoil.
Please excuse me with my bad english, i'm only a german engineer.

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #11 on: April 16, 2013, 03:58:14 PM »
 :) Dear Gianna :) ,

Thank you for spending time thinking, writing calculations and putting effort to explain your point of view. I could not expect more. This is much appreciated. Now, I see how interesting is your proposal by bringing gliding to the topic. It makes easier to think with gliding because we can get rid of the power/thrust topic and concentrate on force/energy.

Your example is very useful. Assuming you are gliding at constant speed and direction, the resulting force is ZERO (drag compensates thrust and lift compensates weight). In this case, the thrust comes from the potential energy being converted into kinetic energy. The drag opposes inertia but the loss of altitude compensates the drag. I'm assuming there is nothing new here as you are a pilot. I'm writing this paragraph to help my own thinking.

Assuming that the gliding is gravity powered (instead of engine powered), I'll calculate the energy lost as a variation of the gravitational potential energy (dEnergy = m · g · dh). Where dEnergy means energy variation and dh means height variation. Therefore, the variation of potential energy per second is 1000kg * 9.8 * 3.3 = 32340J/s or 32340W.

1HP = 745W. So, we have 43HP.

Amazing: we are both getting the same result.

At this moment, we both agree that, in your example, the gliding is spending 43HP from the gravitational potential energy.

To be continued...

 :) Thank you for providing fun. :)

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #12 on: April 16, 2013, 04:19:07 PM »
 :) Hi Fritznien  :) ,

I think that I'm in the right forum because I intend to debate with intelligent and open minded people. I don't intend to debate with people that has faith that OU is impossible. I prefer rational based debates instead of faith based debates.

Quote
looks like a form of leaverage.

Please elaborate your point of view towards leverage. In the case that there is some sort of leverage (force multiplier without OU), where the "hinge, or pivot, called a fulcrum" is located? It seems to me that we have 2 options:

1) Leverage or
2) OU.

 :) To be continued :)

schuler

  • Jr. Member
  • **
  • Posts: 50
Re: Is common air plane flight OU?
« Reply #13 on: April 16, 2013, 04:27:28 PM »
Hi l4zep,
I'm not sure if I understand you nor I'm sure about the need for the diagram.

I have a perception that the debate doesn't involve fluid dynamics yet as the amount of air pumped down from wings (creating lift) can be calculated using Newton physics.

 :) Please elaborate. :)

tagor

  • Hero Member
  • *****
  • Posts: 1333
Re: Is common air plane flight OU?
« Reply #14 on: April 16, 2013, 05:41:10 PM »
:) Hi  :)

In a sustained horizontal flight, drag compensates thrust and lift compensates weight. So, the resulting force is vectorial ZERO. If the resulting force is zero and lift is bigger than thrust, from where comes the extra force?

 :) Have Fun :)

you need to learn this
 
http://en.wikipedia.org/wiki/Bernoulli%27s_equation
 
and this
 
http://en.wikipedia.org/wiki/Aerodynamic_lift